TSTP Solution File: NUM383+1 by SPASS---3.9
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- Process Solution
%------------------------------------------------------------------------------
% File : SPASS---3.9
% Problem : NUM383+1 : TPTP v8.1.0. Released v3.2.0.
% Transfm : none
% Format : tptp
% Command : run_spass %d %s
% Computer : n026.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 600s
% DateTime : Mon Jul 18 14:25:47 EDT 2022
% Result : Theorem 0.18s 0.43s
% Output : Refutation 0.18s
% Verified :
% SZS Type : Refutation
% Derivation depth : 6
% Number of leaves : 7
% Syntax : Number of clauses : 16 ( 8 unt; 2 nHn; 16 RR)
% Number of literals : 27 ( 0 equ; 14 neg)
% Maximal clause size : 3 ( 1 avg)
% Maximal term depth : 2 ( 1 avg)
% Number of predicates : 5 ( 4 usr; 1 prp; 0-2 aty)
% Number of functors : 6 ( 6 usr; 5 con; 0-1 aty)
% Number of variables : 0 ( 0 sgn)
% Comments :
%------------------------------------------------------------------------------
cnf(27,axiom,
in(skc12,skc13),
file('NUM383+1.p',unknown),
[] ).
cnf(28,axiom,
subset(skc13,skc12),
file('NUM383+1.p',unknown),
[] ).
cnf(38,axiom,
( ~ in(u,v)
| ~ in(v,u) ),
file('NUM383+1.p',unknown),
[] ).
cnf(40,axiom,
( ~ subset(u,v)
| element(u,powerset(v)) ),
file('NUM383+1.p',unknown),
[] ).
cnf(41,axiom,
( ~ element(u,v)
| empty(v)
| in(u,v) ),
file('NUM383+1.p',unknown),
[] ).
cnf(44,axiom,
( ~ in(u,v)
| ~ element(v,powerset(w))
| element(u,w) ),
file('NUM383+1.p',unknown),
[] ).
cnf(45,axiom,
( ~ empty(u)
| ~ in(v,w)
| ~ element(w,powerset(u)) ),
file('NUM383+1.p',unknown),
[] ).
cnf(47,plain,
element(skc13,powerset(skc12)),
inference(res,[status(thm),theory(equality)],[28,40]),
[iquote('0:Res:28.0,40.0')] ).
cnf(50,plain,
( ~ element(skc13,powerset(u))
| element(skc12,u) ),
inference(res,[status(thm),theory(equality)],[27,44]),
[iquote('0:Res:27.0,44.0')] ).
cnf(53,plain,
( ~ empty(u)
| ~ element(skc13,powerset(u)) ),
inference(res,[status(thm),theory(equality)],[27,45]),
[iquote('0:Res:27.0,45.2')] ).
cnf(68,plain,
~ empty(skc12),
inference(res,[status(thm),theory(equality)],[47,53]),
[iquote('0:Res:47.0,53.1')] ).
cnf(73,plain,
element(skc12,skc12),
inference(res,[status(thm),theory(equality)],[47,50]),
[iquote('0:Res:47.0,50.0')] ).
cnf(85,plain,
( empty(skc12)
| in(skc12,skc12) ),
inference(res,[status(thm),theory(equality)],[73,41]),
[iquote('0:Res:73.0,41.0')] ).
cnf(90,plain,
in(skc12,skc12),
inference(mrr,[status(thm)],[85,68]),
[iquote('0:MRR:85.0,68.0')] ).
cnf(92,plain,
~ in(skc12,skc12),
inference(res,[status(thm),theory(equality)],[90,38]),
[iquote('0:Res:90.0,38.0')] ).
cnf(93,plain,
$false,
inference(mrr,[status(thm)],[92,90]),
[iquote('0:MRR:92.0,90.0')] ).
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.06/0.11 % Problem : NUM383+1 : TPTP v8.1.0. Released v3.2.0.
% 0.06/0.12 % Command : run_spass %d %s
% 0.12/0.33 % Computer : n026.cluster.edu
% 0.12/0.33 % Model : x86_64 x86_64
% 0.12/0.33 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.33 % Memory : 8042.1875MB
% 0.12/0.33 % OS : Linux 3.10.0-693.el7.x86_64
% 0.12/0.33 % CPULimit : 300
% 0.12/0.33 % WCLimit : 600
% 0.12/0.33 % DateTime : Thu Jul 7 00:52:08 EDT 2022
% 0.12/0.33 % CPUTime :
% 0.18/0.43
% 0.18/0.43 SPASS V 3.9
% 0.18/0.43 SPASS beiseite: Proof found.
% 0.18/0.43 % SZS status Theorem
% 0.18/0.43 Problem: /export/starexec/sandbox/benchmark/theBenchmark.p
% 0.18/0.43 SPASS derived 45 clauses, backtracked 0 clauses, performed 0 splits and kept 65 clauses.
% 0.18/0.43 SPASS allocated 97676 KBytes.
% 0.18/0.43 SPASS spent 0:00:00.09 on the problem.
% 0.18/0.43 0:00:00.03 for the input.
% 0.18/0.43 0:00:00.03 for the FLOTTER CNF translation.
% 0.18/0.43 0:00:00.00 for inferences.
% 0.18/0.43 0:00:00.00 for the backtracking.
% 0.18/0.43 0:00:00.00 for the reduction.
% 0.18/0.43
% 0.18/0.43
% 0.18/0.43 Here is a proof with depth 4, length 16 :
% 0.18/0.43 % SZS output start Refutation
% See solution above
% 0.18/0.43 Formulae used in the proof : t7_ordinal1 antisymmetry_r2_hidden t3_subset t2_subset t4_subset t5_subset
% 0.18/0.43
%------------------------------------------------------------------------------