TSTP Solution File: NUM016-2 by Otter---3.3

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : Otter---3.3
% Problem  : NUM016-2 : TPTP v8.1.0. Released v1.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : otter-tptp-script %s

% Computer : n014.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Wed Jul 27 13:07:26 EDT 2022

% Result   : Unsatisfiable 1.59s 1.80s
% Output   : Refutation 1.59s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :    4
%            Number of leaves      :    8
% Syntax   : Number of clauses     :   14 (   8 unt;   3 nHn;  10 RR)
%            Number of literals    :   21 (   0 equ;   6 neg)
%            Maximal clause size   :    3 (   1 avg)
%            Maximal term depth    :    3 (   1 avg)
%            Number of predicates  :    4 (   3 usr;   1 prp; 0-2 aty)
%            Number of functors    :    3 (   3 usr;   1 con; 0-1 aty)
%            Number of variables   :   10 (   0 sgn)

% Comments : 
%------------------------------------------------------------------------------
cnf(1,axiom,
    ~ less(A,A),
    file('NUM016-2.p',unknown),
    [] ).

cnf(2,axiom,
    ( ~ less(A,B)
    | ~ less(B,A) ),
    file('NUM016-2.p',unknown),
    [] ).

cnf(3,axiom,
    ( ~ divides(A,factorial_plus_one(B))
    | less(B,A) ),
    file('NUM016-2.p',unknown),
    [] ).

cnf(4,axiom,
    ( ~ prime(A)
    | ~ less(a,A)
    | less(factorial_plus_one(a),A) ),
    file('NUM016-2.p',unknown),
    [] ).

cnf(5,axiom,
    less(A,factorial_plus_one(A)),
    file('NUM016-2.p',unknown),
    [] ).

cnf(6,axiom,
    ( prime(A)
    | divides(prime_divisor(A),A) ),
    file('NUM016-2.p',unknown),
    [] ).

cnf(7,axiom,
    ( prime(A)
    | prime(prime_divisor(A)) ),
    file('NUM016-2.p',unknown),
    [] ).

cnf(8,axiom,
    ( prime(A)
    | less(prime_divisor(A),A) ),
    file('NUM016-2.p',unknown),
    [] ).

cnf(9,plain,
    prime(prime_divisor(factorial_plus_one(a))),
    inference(unit_del,[status(thm)],[inference(hyper,[status(thm)],[7,4,5]),1]),
    [iquote('hyper,7,4,5,unit_del,1')] ).

cnf(10,plain,
    divides(prime_divisor(factorial_plus_one(a)),factorial_plus_one(a)),
    inference(unit_del,[status(thm)],[inference(hyper,[status(thm)],[6,4,5]),1]),
    [iquote('hyper,6,4,5,unit_del,1')] ).

cnf(11,plain,
    less(prime_divisor(factorial_plus_one(a)),factorial_plus_one(a)),
    inference(unit_del,[status(thm)],[inference(hyper,[status(thm)],[8,4,5]),1]),
    [iquote('hyper,8,4,5,unit_del,1')] ).

cnf(12,plain,
    less(a,prime_divisor(factorial_plus_one(a))),
    inference(hyper,[status(thm)],[10,3]),
    [iquote('hyper,10,3')] ).

cnf(13,plain,
    less(factorial_plus_one(a),prime_divisor(factorial_plus_one(a))),
    inference(hyper,[status(thm)],[12,4,9]),
    [iquote('hyper,12,4,9')] ).

cnf(14,plain,
    $false,
    inference(hyper,[status(thm)],[13,2,11]),
    [iquote('hyper,13,2,11')] ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.06/0.12  % Problem  : NUM016-2 : TPTP v8.1.0. Released v1.0.0.
% 0.06/0.12  % Command  : otter-tptp-script %s
% 0.12/0.33  % Computer : n014.cluster.edu
% 0.12/0.33  % Model    : x86_64 x86_64
% 0.12/0.33  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.33  % Memory   : 8042.1875MB
% 0.12/0.33  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.12/0.33  % CPULimit : 300
% 0.12/0.33  % WCLimit  : 300
% 0.12/0.33  % DateTime : Wed Jul 27 09:47:54 EDT 2022
% 0.12/0.33  % CPUTime  : 
% 1.59/1.80  ----- Otter 3.3f, August 2004 -----
% 1.59/1.80  The process was started by sandbox2 on n014.cluster.edu,
% 1.59/1.80  Wed Jul 27 09:47:54 2022
% 1.59/1.80  The command was "./otter".  The process ID is 22681.
% 1.59/1.80  
% 1.59/1.80  set(prolog_style_variables).
% 1.59/1.80  set(auto).
% 1.59/1.80     dependent: set(auto1).
% 1.59/1.80     dependent: set(process_input).
% 1.59/1.80     dependent: clear(print_kept).
% 1.59/1.80     dependent: clear(print_new_demod).
% 1.59/1.80     dependent: clear(print_back_demod).
% 1.59/1.80     dependent: clear(print_back_sub).
% 1.59/1.80     dependent: set(control_memory).
% 1.59/1.80     dependent: assign(max_mem, 12000).
% 1.59/1.80     dependent: assign(pick_given_ratio, 4).
% 1.59/1.80     dependent: assign(stats_level, 1).
% 1.59/1.80     dependent: assign(max_seconds, 10800).
% 1.59/1.80  clear(print_given).
% 1.59/1.80  
% 1.59/1.80  list(usable).
% 1.59/1.80  0 [] -less(X,X).
% 1.59/1.80  0 [] -less(X,Y)| -less(Y,X).
% 1.59/1.80  0 [] less(X,factorial_plus_one(X)).
% 1.59/1.80  0 [] -divides(X,factorial_plus_one(Y))|less(Y,X).
% 1.59/1.80  0 [] prime(X)|divides(prime_divisor(X),X).
% 1.59/1.80  0 [] prime(X)|prime(prime_divisor(X)).
% 1.59/1.80  0 [] prime(X)|less(prime_divisor(X),X).
% 1.59/1.80  0 [] -prime(X)| -less(a,X)|less(factorial_plus_one(a),X).
% 1.59/1.80  end_of_list.
% 1.59/1.80  
% 1.59/1.80  SCAN INPUT: prop=0, horn=0, equality=0, symmetry=0, max_lits=3.
% 1.59/1.80  
% 1.59/1.80  This is a non-Horn set without equality.  The strategy will
% 1.59/1.80  be ordered hyper_res, unit deletion, and factoring, with
% 1.59/1.80  satellites in sos and with nuclei in usable.
% 1.59/1.80  
% 1.59/1.80     dependent: set(hyper_res).
% 1.59/1.80     dependent: set(factor).
% 1.59/1.80     dependent: set(unit_deletion).
% 1.59/1.80  
% 1.59/1.80  ------------> process usable:
% 1.59/1.80  ** KEPT (pick-wt=3): 1 [] -less(A,A).
% 1.59/1.80  ** KEPT (pick-wt=6): 2 [] -less(A,B)| -less(B,A).
% 1.59/1.80  ** KEPT (pick-wt=7): 3 [] -divides(A,factorial_plus_one(B))|less(B,A).
% 1.59/1.80  ** KEPT (pick-wt=9): 4 [] -prime(A)| -less(a,A)|less(factorial_plus_one(a),A).
% 1.59/1.80  
% 1.59/1.80  ------------> process sos:
% 1.59/1.80  ** KEPT (pick-wt=4): 5 [] less(A,factorial_plus_one(A)).
% 1.59/1.80  ** KEPT (pick-wt=6): 6 [] prime(A)|divides(prime_divisor(A),A).
% 1.59/1.80  ** KEPT (pick-wt=5): 7 [] prime(A)|prime(prime_divisor(A)).
% 1.59/1.80  ** KEPT (pick-wt=6): 8 [] prime(A)|less(prime_divisor(A),A).
% 1.59/1.80  
% 1.59/1.80  ======= end of input processing =======
% 1.59/1.80  
% 1.59/1.80  =========== start of search ===========
% 1.59/1.80  
% 1.59/1.80  -------- PROOF -------- 
% 1.59/1.80  
% 1.59/1.80  -----> EMPTY CLAUSE at   0.00 sec ----> 14 [hyper,13,2,11] $F.
% 1.59/1.80  
% 1.59/1.80  Length of proof is 5.  Level of proof is 3.
% 1.59/1.80  
% 1.59/1.80  ---------------- PROOF ----------------
% 1.59/1.80  % SZS status Unsatisfiable
% 1.59/1.80  % SZS output start Refutation
% See solution above
% 1.59/1.80  ------------ end of proof -------------
% 1.59/1.80  
% 1.59/1.80  
% 1.59/1.80  Search stopped by max_proofs option.
% 1.59/1.80  
% 1.59/1.80  
% 1.59/1.80  Search stopped by max_proofs option.
% 1.59/1.80  
% 1.59/1.80  ============ end of search ============
% 1.59/1.80  
% 1.59/1.80  -------------- statistics -------------
% 1.59/1.80  clauses given                  9
% 1.59/1.80  clauses generated             11
% 1.59/1.80  clauses kept                  13
% 1.59/1.80  clauses forward subsumed       5
% 1.59/1.80  clauses back subsumed          0
% 1.59/1.80  Kbytes malloced              976
% 1.59/1.80  
% 1.59/1.80  ----------- times (seconds) -----------
% 1.59/1.80  user CPU time          0.00          (0 hr, 0 min, 0 sec)
% 1.59/1.80  system CPU time        0.00          (0 hr, 0 min, 0 sec)
% 1.59/1.80  wall-clock time        1             (0 hr, 0 min, 1 sec)
% 1.59/1.80  
% 1.59/1.80  That finishes the proof of the theorem.
% 1.59/1.80  
% 1.59/1.80  Process 22681 finished Wed Jul 27 09:47:55 2022
% 1.59/1.80  Otter interrupted
% 1.59/1.80  PROOF FOUND
%------------------------------------------------------------------------------