TSTP Solution File: MGT033+2 by Crossbow---0.1

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : Crossbow---0.1
% Problem  : MGT033+2 : TPTP v8.1.0. Released v2.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : do_Crossbow---0.1 %s

% Computer : n018.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 600s
% DateTime : Sun Jul 17 21:58:20 EDT 2022

% Result   : CounterSatisfiable 5.21s 5.40s
% Output   : FiniteModel 5.21s
% Verified : 
% SZS Type : -

% Comments : 
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.03/0.12  % Problem    : MGT033+2 : TPTP v8.1.0. Released v2.0.0.
% 0.03/0.12  % Command    : do_Crossbow---0.1 %s
% 0.13/0.33  % Computer : n018.cluster.edu
% 0.13/0.33  % Model    : x86_64 x86_64
% 0.13/0.33  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.33  % Memory   : 8042.1875MB
% 0.13/0.33  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.13/0.33  % CPULimit   : 300
% 0.13/0.33  % WCLimit    : 600
% 0.13/0.33  % DateTime   : Thu Jun  9 07:56:38 EDT 2022
% 0.13/0.34  % CPUTime    : 
% 0.13/0.34  /export/starexec/sandbox2/solver/bin
% 0.13/0.34  crossbow.opt
% 0.13/0.34  do_Crossbow---0.1
% 0.13/0.34  eprover
% 0.13/0.34  runsolver
% 0.13/0.34  starexec_run_Crossbow---0.1
% 5.21/5.40  % SZS status CounterSatisfiable for theBenchmark.p
% 5.21/5.40  % SZS output start FiniteModel for theBenchmark.p
% 5.21/5.40  % domain size: 2
% 5.21/5.40  fof(interp, fi_domain, ![X] : (X = 0 | X = 1)).
% 5.21/5.40  fof(interp, fi_functors, an_organisation = 0).
% 5.21/5.40  fof(interp, fi_functors, appear(0, 0) = 0 & appear(0, 1) = 0 & appear(1, 0) = 1 &
% 5.21/5.40    appear(1, 1) = 1).
% 5.21/5.40  fof(interp, fi_functors, cardinality_at_time(0, 0) = 0 &
% 5.21/5.40    cardinality_at_time(0, 1) = 0 &
% 5.21/5.40    cardinality_at_time(1, 0) = 1 &
% 5.21/5.40    cardinality_at_time(1, 1) = 0).
% 5.21/5.40  fof(interp, fi_functors, e = 1).
% 5.21/5.40  fof(interp, fi_functors, efficient_producers = 1).
% 5.21/5.40  fof(interp, fi_predicates, environment(0) & ~environment(1)).
% 5.21/5.40  fof(interp, fi_functors, esk1_2(0, 0) = 1 & esk1_2(0, 1) = 0 & esk1_2(1, 0) = 0 &
% 5.21/5.40    esk1_2(1, 1) = 0).
% 5.21/5.40  fof(interp, fi_functors, esk2_0 = 0).
% 5.21/5.40  fof(interp, fi_functors, esk3_0 = 0).
% 5.21/5.40  fof(interp, fi_functors, first_movers = 0).
% 5.21/5.40  fof(interp, fi_predicates, ~greater(0, 0) & ~greater(0, 1) & greater(1, 0) &
% 5.21/5.40    greater(1, 1)).
% 5.21/5.40  fof(interp, fi_predicates, greater_or_equal(0, 0) & ~greater_or_equal(0, 1) &
% 5.21/5.40    greater_or_equal(1, 0) &
% 5.21/5.40    greater_or_equal(1, 1)).
% 5.21/5.40  fof(interp, fi_predicates, in_environment(0, 0) & ~in_environment(0, 1) &
% 5.21/5.40    ~in_environment(1, 0) &
% 5.21/5.40    ~in_environment(1, 1)).
% 5.21/5.40  fof(interp, fi_functors, number_of_organizations(0, 0) = 1 &
% 5.21/5.40    number_of_organizations(0, 1) = 0 &
% 5.21/5.40    number_of_organizations(1, 0) = 1 &
% 5.21/5.40    number_of_organizations(1, 1) = 1).
% 5.21/5.40  fof(interp, fi_predicates, ~selection_favors(0, 0, 0) &
% 5.21/5.40    ~selection_favors(0, 0, 1) &
% 5.21/5.40    ~selection_favors(0, 1, 0) &
% 5.21/5.40    ~selection_favors(0, 1, 1) &
% 5.21/5.40    ~selection_favors(1, 0, 0) &
% 5.21/5.40    ~selection_favors(1, 0, 1) &
% 5.21/5.40    selection_favors(1, 1, 0) &
% 5.21/5.40    ~selection_favors(1, 1, 1)).
% 5.21/5.40  fof(interp, fi_functors, start_time(0) = 0 & start_time(1) = 0).
% 5.21/5.40  fof(interp, fi_predicates, subpopulation(0, 0, 0) & ~subpopulation(0, 0, 1) &
% 5.21/5.40    ~subpopulation(0, 1, 0) &
% 5.21/5.40    ~subpopulation(0, 1, 1) &
% 5.21/5.40    subpopulation(1, 0, 0) &
% 5.21/5.40    ~subpopulation(1, 0, 1) &
% 5.21/5.40    ~subpopulation(1, 1, 0) &
% 5.21/5.40    ~subpopulation(1, 1, 1)).
% 5.21/5.40  fof(interp, fi_functors, t = 1).
% 5.21/5.40  fof(interp, fi_functors, zero = 1).
% 5.21/5.40  % SZS output end FiniteModel for theBenchmark.p
% 5.21/5.40  % 4 lemma(s) from E
% 5.21/5.40  %     cnf(cl, axiom, in_environment(esk2_0, start_time(esk2_0))).
% 5.21/5.40  %     cnf(cl, axiom, cardinality_at_time(efficient_producers, esk3_0) = zero).
% 5.21/5.40  %     cnf(cl, axiom, in_environment(esk2_0, appear(first_movers, esk2_0))).
% 5.21/5.40  %     cnf(cl, axiom, in_environment(esk2_0, appear(an_organisation, esk2_0))).
% 5.21/5.40  % 29 pred(s)
% 5.21/5.40  % 18 func(s)
% 5.21/5.40  % 3 sort(s)
% 5.21/5.40  % 58 clause(s)
% 5.21/5.40  % Instantiating 1 (5030 ms)
% 5.21/5.40  % Solving (5031 ms)
% 5.21/5.40  % Instantiating 2 (5031 ms)
% 5.21/5.40  % Solving (5032 ms)
% 5.21/5.40  % 
% 5.21/5.40  % 1 model found (5032 ms)
%------------------------------------------------------------------------------