TSTP Solution File: MGT023-1 by SOS---2.0

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : SOS---2.0
% Problem  : MGT023-1 : TPTP v8.1.0. Released v2.4.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : sos-script %s

% Computer : n026.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 600s
% DateTime : Sun Jul 17 22:25:51 EDT 2022

% Result   : Unsatisfiable 0.85s 1.03s
% Output   : Refutation 0.85s
% Verified : 
% SZS Type : -

% Comments : 
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.12/0.12  % Problem  : MGT023-1 : TPTP v8.1.0. Released v2.4.0.
% 0.12/0.13  % Command  : sos-script %s
% 0.13/0.34  % Computer : n026.cluster.edu
% 0.13/0.34  % Model    : x86_64 x86_64
% 0.13/0.34  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.34  % Memory   : 8042.1875MB
% 0.13/0.34  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.13/0.34  % CPULimit : 300
% 0.13/0.34  % WCLimit  : 600
% 0.13/0.34  % DateTime : Thu Jun  9 10:39:02 EDT 2022
% 0.13/0.34  % CPUTime  : 
% 0.13/0.36  ----- Otter 3.2, August 2001 -----
% 0.13/0.36  The process was started by sandbox on n026.cluster.edu,
% 0.13/0.36  Thu Jun  9 10:39:02 2022
% 0.13/0.36  The command was "./sos".  The process ID is 583.
% 0.13/0.36  
% 0.13/0.36  set(prolog_style_variables).
% 0.13/0.36  set(auto).
% 0.13/0.36     dependent: set(auto1).
% 0.13/0.36     dependent: set(process_input).
% 0.13/0.36     dependent: clear(print_kept).
% 0.13/0.36     dependent: clear(print_new_demod).
% 0.13/0.36     dependent: clear(print_back_demod).
% 0.13/0.36     dependent: clear(print_back_sub).
% 0.13/0.36     dependent: set(control_memory).
% 0.13/0.36     dependent: assign(max_mem, 12000).
% 0.13/0.36     dependent: assign(pick_given_ratio, 4).
% 0.13/0.36     dependent: assign(stats_level, 1).
% 0.13/0.36     dependent: assign(pick_semantic_ratio, 3).
% 0.13/0.36     dependent: assign(sos_limit, 5000).
% 0.13/0.36     dependent: assign(max_weight, 60).
% 0.13/0.36  clear(print_given).
% 0.13/0.36  
% 0.13/0.36  list(usable).
% 0.13/0.36  
% 0.13/0.36  SCAN INPUT: prop=0, horn=0, equality=1, symmetry=0, max_lits=5.
% 0.13/0.36  
% 0.13/0.36  This ia a non-Horn set with equality.  The strategy will be
% 0.13/0.36  Knuth-Bendix, ordered hyper_res, ur_res, factoring, and
% 0.13/0.36  unit deletion, with positive clauses in sos and nonpositive
% 0.13/0.36  clauses in usable.
% 0.13/0.36  
% 0.13/0.36     dependent: set(knuth_bendix).
% 0.13/0.36     dependent: set(para_from).
% 0.13/0.36     dependent: set(para_into).
% 0.13/0.36     dependent: clear(para_from_right).
% 0.13/0.36     dependent: clear(para_into_right).
% 0.13/0.36     dependent: set(para_from_vars).
% 0.13/0.36     dependent: set(eq_units_both_ways).
% 0.13/0.36     dependent: set(dynamic_demod_all).
% 0.13/0.36     dependent: set(dynamic_demod).
% 0.13/0.36     dependent: set(order_eq).
% 0.13/0.36     dependent: set(back_demod).
% 0.13/0.36     dependent: set(lrpo).
% 0.13/0.36     dependent: set(hyper_res).
% 0.13/0.36     dependent: set(unit_deletion).
% 0.13/0.36     dependent: set(factor).
% 0.13/0.36  
% 0.13/0.36  ------------> process usable:
% 0.13/0.36  
% 0.13/0.36  ------------> process sos:
% 0.13/0.36    Following clause subsumed by 10 during input processing: 0 [copy,10,flip.1] {-} A=A.
% 0.13/0.36  
% 0.13/0.36  ======= end of input processing =======
% 0.13/0.38  
% 0.13/0.38  Model 1 (0.00 seconds, 0 Inserts)
% 0.13/0.38  
% 0.13/0.38  Stopped by limit on number of solutions
% 0.13/0.38  
% 0.13/0.38  
% 0.13/0.38  -------------- Softie stats --------------
% 0.13/0.38  
% 0.13/0.38  UPDATE_STOP: 300
% 0.13/0.38  SFINDER_TIME_LIMIT: 2
% 0.13/0.38  SHORT_CLAUSE_CUTOFF: 4
% 0.13/0.38  number of clauses in intial UL: 7
% 0.13/0.38  number of clauses initially in problem: 10
% 0.13/0.38  percentage of clauses intially in UL: 70
% 0.13/0.38  percentage of distinct symbols occuring in initial UL: 100
% 0.13/0.38  percent of all initial clauses that are short: 90
% 0.13/0.38  absolute distinct symbol count: 13
% 0.13/0.38     distinct predicate count: 6
% 0.13/0.38     distinct function count: 4
% 0.13/0.38     distinct constant count: 3
% 0.13/0.38  
% 0.13/0.38  ---------- no more Softie stats ----------
% 0.13/0.38  
% 0.13/0.38  
% 0.13/0.38  
% 0.13/0.38  =========== start of search ===========
% 0.85/1.03  
% 0.85/1.03  -------- PROOF -------- 
% 0.85/1.03  % SZS status Unsatisfiable
% 0.85/1.03  % SZS output start Refutation
% 0.85/1.03  
% 0.85/1.03  Stopped by limit on insertions
% 0.85/1.03  
% 0.85/1.03  ----> UNIT CONFLICT at   0.65 sec ----> 1217 [binary,1216.1,7.1] {-} $F.
% 0.85/1.03  
% 0.85/1.03  Length of proof is 11.  Level of proof is 8.
% 0.85/1.03  
% 0.85/1.03  ---------------- PROOF ----------------
% 0.85/1.03  % SZS status Unsatisfiable
% 0.85/1.03  % SZS output start Refutation
% 0.85/1.03  
% 0.85/1.03  1 [] {+} -environment(A)|greater(growth_rate(efficient_producers,B),growth_rate(first_movers,B))| -in_environment(A,B)|subpopulations(first_movers,efficient_producers,A,sk1(B,A))|B=critical_point(A).
% 0.85/1.03  2 [] {+} -environment(A)|greater(growth_rate(efficient_producers,B),growth_rate(first_movers,B))| -in_environment(A,B)|greater(sk1(B,A),B)|B=critical_point(A).
% 0.85/1.03  3 [] {+} -environment(A)|greater(growth_rate(efficient_producers,B),growth_rate(first_movers,B))| -in_environment(A,B)| -greater(growth_rate(efficient_producers,sk1(B,A)),growth_rate(first_movers,sk1(B,A)))|B=critical_point(A).
% 0.85/1.03  4 [] {+} -environment(A)| -stable(A)|in_environment(A,sk2(A)).
% 0.85/1.03  5 [] {+} -environment(A)| -stable(A)| -greater(growth_rate(efficient_producers,sk2(A)),growth_rate(first_movers,sk2(A))).
% 0.85/1.03  6 [] {+} -environment(A)| -stable(A)| -subpopulations(first_movers,efficient_producers,A,B)| -greater(B,sk2(A))|greater(growth_rate(efficient_producers,B),growth_rate(first_movers,B)).
% 0.85/1.03  7 [] {+} -in_environment(sk3,critical_point(sk3)).
% 0.85/1.03  8 [] {+} environment(sk3).
% 0.85/1.03  9 [] {-} stable(sk3).
% 0.85/1.03  14 [hyper,9,4,8] {+} in_environment(sk3,sk2(sk3)).
% 0.85/1.03  18 [hyper,14,2,8] {+} greater(growth_rate(efficient_producers,sk2(sk3)),growth_rate(first_movers,sk2(sk3)))|greater(sk1(sk2(sk3),sk3),sk2(sk3))|sk2(sk3)=critical_point(sk3).
% 0.85/1.03  19 [hyper,14,1,8] {+} greater(growth_rate(efficient_producers,sk2(sk3)),growth_rate(first_movers,sk2(sk3)))|subpopulations(first_movers,efficient_producers,sk3,sk1(sk2(sk3),sk3))|sk2(sk3)=critical_point(sk3).
% 0.85/1.03  181 [hyper,18,5,8,9] {+} greater(sk1(sk2(sk3),sk3),sk2(sk3))|sk2(sk3)=critical_point(sk3).
% 0.85/1.03  206 [para_from,181.2.1,14.1.2,unit_del,7] {+} greater(sk1(sk2(sk3),sk3),sk2(sk3)).
% 0.85/1.03  327 [hyper,19,5,8,9] {+} subpopulations(first_movers,efficient_producers,sk3,sk1(sk2(sk3),sk3))|sk2(sk3)=critical_point(sk3).
% 0.85/1.03  357 [para_from,327.2.1,14.1.2,unit_del,7] {+} subpopulations(first_movers,efficient_producers,sk3,sk1(sk2(sk3),sk3)).
% 0.85/1.03  358 [hyper,357,6,8,9,206] {-} greater(growth_rate(efficient_producers,sk1(sk2(sk3),sk3)),growth_rate(first_movers,sk1(sk2(sk3),sk3))).
% 0.85/1.03  445 [hyper,358,3,8,14] {+} greater(growth_rate(efficient_producers,sk2(sk3)),growth_rate(first_movers,sk2(sk3)))|sk2(sk3)=critical_point(sk3).
% 0.85/1.03  816,815 [hyper,445,5,8,9] {-} sk2(sk3)=critical_point(sk3).
% 0.85/1.03  1216 [back_demod,14,demod,816] {-} in_environment(sk3,critical_point(sk3)).
% 0.85/1.03  1217 [binary,1216.1,7.1] {-} $F.
% 0.85/1.03  
% 0.85/1.03  % SZS output end Refutation
% 0.85/1.03  ------------ end of proof -------------
% 0.85/1.03  
% 0.85/1.03  
% 0.85/1.03  Search stopped by max_proofs option.
% 0.85/1.03  
% 0.85/1.03  
% 0.85/1.03  Search stopped by max_proofs option.
% 0.85/1.03  
% 0.85/1.03  ============ end of search ============
% 0.85/1.03  
% 0.85/1.03  ----------- soft-scott stats ----------
% 0.85/1.03  
% 0.85/1.03  true clauses given          17      (68.0%)
% 0.85/1.03  false clauses given          8
% 0.85/1.03  
% 0.85/1.03        FALSE     TRUE
% 0.85/1.03    22  0         2
% 0.85/1.03    24  0         2
% 0.85/1.03    25  0         3
% 0.85/1.03    26  0         6
% 0.85/1.03    27  0         4
% 0.85/1.03    28  0         6
% 0.85/1.03    29  0         3
% 0.85/1.03    30  0         3
% 0.85/1.03    31  0         15
% 0.85/1.03    32  0         6
% 0.85/1.03    33  0         15
% 0.85/1.03    35  0         8
% 0.85/1.03    36  0         7
% 0.85/1.03    37  0         18
% 0.85/1.03    38  0         16
% 0.85/1.03    39  0         14
% 0.85/1.03    40  0         20
% 0.85/1.03    41  0         6
% 0.85/1.03    42  0         22
% 0.85/1.03    43  2         8
% 0.85/1.03    44  7         46
% 0.85/1.03    45  0         6
% 0.85/1.03    46  3         48
% 0.85/1.03    47  0         6
% 0.85/1.03    48  1         33
% 0.85/1.03    49  0         22
% 0.85/1.03    50  0         41
% 0.85/1.03    51  3         25
% 0.85/1.03    52  0         42
% 0.85/1.03    53  12        17
% 0.85/1.03    54  5         21
% 0.85/1.03    55  20        19
% 0.85/1.03    56  5         16
% 0.85/1.03    57  8         15
% 0.85/1.03    58  0         58
% 0.85/1.03    59  4         20
% 0.85/1.03    60  0         32
% 0.85/1.03  tot:  70        651      (90.3% true)
% 0.85/1.03  
% 0.85/1.03  
% 0.85/1.03  Model 1 (0.00 seconds, 0 Inserts)
% 0.85/1.03  
% 0.85/1.03  That finishes the proof of the theorem.
% 0.85/1.03  
% 0.85/1.03  Process 583 finished Thu Jun  9 10:39:03 2022
%------------------------------------------------------------------------------