TSTP Solution File: LCL887+1 by DarwinFM---1.4.5

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : DarwinFM---1.4.5
% Problem  : LCL887+1 : TPTP v8.1.0. Released v5.5.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : darwin -fd true -ppp true -pl 0 -to %d -pmtptp true %s

% Computer : n029.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 0s
% DateTime : Sun Jul 17 08:59:36 EDT 2022

% Result   : CounterSatisfiable 0.19s 0.42s
% Output   : FiniteModel 0.19s
% Verified : 
% SZS Type : FiniteModel
%            Domain size           :    3

% Comments : 
%------------------------------------------------------------------------------
fof(interpretation_domain,fi_domain,
    ! [X] :
      ( X = e1
      | X = e2
      | X = e3 ) ).

fof(interpretation_domain_distinct,fi_domain,
    ( e1 != e2
    & e1 != e3
    & e2 != e3 ) ).

fof(interpretation_terms,fi_functors,
    ( ! [X0,X1,X2] :
        ( '+'(X0,X1) = X2
      <=> ( ( X2 = e2
            & ~ ( X0 = e3
                & X1 = e3 )
            & ~ ( X0 = e3
                & X1 = e1 )
            & ~ ( X0 = e1
                & X1 = e3 )
            & ~ ( X0 = e1
                & X1 = e1 ) )
          | ( X0 = e1
            & X1 = e1
            & X2 = e1 )
          | ( X0 = e1
            & X1 = e3
            & X2 = e3 )
          | ( X0 = e3
            & X1 = e1
            & X2 = e3 )
          | ( X0 = e3
            & X1 = e3
            & X2 = e3 ) ) )
    & '0' = e1
    & '1' = e2
    & ! [X0,X1,X2] :
        ( '==>'(X0,X1) = X2
      <=> ( ( X1 = e1
            & X2 = e1 )
          | ( X2 = e1
            & X0 != e3
            & X0 != e1 )
          | ( X1 = e3
            & X2 = e1
            & X0 != e1 )
          | ( X0 = e1
            & X2 = e2
            & X1 != e3
            & X1 != e1 )
          | ( X0 = e1
            & X1 = e3
            & X2 = e3 )
          | ( X0 = e3
            & X2 = e2
            & X1 != e3
            & X1 != e1 ) ) )
    & esk1_0 = e3 ) ).

fof(interpretation_atoms,fi_predicates,
    ! [X0,X1] :
      ( '>='(X0,X1)
    <=> ( ( X1 = e3
          & X0 != e1 )
        | ( X1 = e2
          & X0 != e3
          & X0 != e1 )
        | ( X0 != e3
          & X0 != e1 )
        | X1 = e1
        | X1 = X0 ) ) ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.07/0.12  % Problem  : LCL887+1 : TPTP v8.1.0. Released v5.5.0.
% 0.07/0.13  % Command  : darwin -fd true -ppp true -pl 0 -to %d -pmtptp true %s
% 0.13/0.34  % Computer : n029.cluster.edu
% 0.13/0.34  % Model    : x86_64 x86_64
% 0.13/0.34  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.34  % Memory   : 8042.1875MB
% 0.13/0.34  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.13/0.34  % CPULimit : 300
% 0.13/0.34  % DateTime : Mon Jul  4 09:52:26 EDT 2022
% 0.13/0.34  % CPUTime  : 
% 0.13/0.35  Defaulting to tptp format.
% 0.19/0.42  SZS status CounterSatisfiable for /export/starexec/sandbox/benchmark/theBenchmark.p
% 0.19/0.42  
% 0.19/0.42  MODEL (TPTP):
% 0.19/0.42  SZS output start FiniteModel for /export/starexec/sandbox/benchmark/theBenchmark.p
% See solution above
%------------------------------------------------------------------------------