TSTP Solution File: LCL827_5 by Duper---1.0

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%------------------------------------------------------------------------------
% File     : Duper---1.0
% Problem  : LCL827_5 : TPTP v8.1.2. Released v6.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : duper %s

% Computer : n005.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Thu Aug 31 07:11:26 EDT 2023

% Result   : Theorem 3.75s 3.97s
% Output   : Proof 3.75s
% Verified : 
% SZS Type : -

% Comments : 
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.12  % Problem    : LCL827_5 : TPTP v8.1.2. Released v6.0.0.
% 0.12/0.13  % Command    : duper %s
% 0.13/0.34  % Computer : n005.cluster.edu
% 0.13/0.34  % Model    : x86_64 x86_64
% 0.13/0.34  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.34  % Memory   : 8042.1875MB
% 0.13/0.34  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.13/0.34  % CPULimit   : 300
% 0.13/0.34  % WCLimit    : 300
% 0.13/0.34  % DateTime   : Fri Aug 25 04:21:23 EDT 2023
% 0.13/0.34  % CPUTime    : 
% 3.75/3.97  SZS status Theorem for theBenchmark.p
% 3.75/3.97  SZS output start Proof for theBenchmark.p
% 3.75/3.97  Clause #2 (by assumption #[]): Eq
% 3.75/3.97    (And
% 3.75/3.97      (∀ (E1 : fun nat type) (T4 : type) (U4 : dB) (I1 : nat),
% 3.75/3.97        pp
% 3.75/3.97            (aa type bool
% 3.75/3.97              (aa dB (fun type bool)
% 3.75/3.97                (aa (fun nat type) (fun dB (fun type bool)) typing
% 3.75/3.97                  (aa type (fun nat type)
% 3.75/3.97                    (aa nat (fun type (fun nat type))
% 3.75/3.97                      (aa (fun nat type) (fun nat (fun type (fun nat type))) (shift type) E1) I1)
% 3.75/3.97                    t))
% 3.75/3.97                a)
% 3.75/3.97              T4) →
% 3.75/3.97          pp (aa dB bool it U4) →
% 3.75/3.97            pp (aa type bool (aa dB (fun type bool) (aa (fun nat type) (fun dB (fun type bool)) typing E1) U4) t) →
% 3.75/3.97              pp (aa dB bool it (aa nat dB (aa dB (fun nat dB) (aa dB (fun dB (fun nat dB)) subst a) U4) I1)))
% 3.75/3.97      (Exists fun X11 =>
% 3.75/3.97        pp
% 3.75/3.97          (aa type bool
% 3.75/3.97            (aa dB (fun type bool)
% 3.75/3.97              (aa (fun nat type) (fun dB (fun type bool)) typing
% 3.75/3.97                (aa type (fun nat type)
% 3.75/3.97                  (aa nat (fun type (fun nat type)) (aa (fun nat type) (fun nat (fun type (fun nat type))) (shift type) e)
% 3.75/3.97                    i)
% 3.75/3.97                  t))
% 3.75/3.97              a)
% 3.75/3.97            X11)))
% 3.75/3.97    True
% 3.75/3.97  Clause #114 (by assumption #[]): Eq
% 3.75/3.97    (∀ (U : type),
% 3.75/3.97      pp
% 3.75/3.97          (aa type bool
% 3.75/3.97            (aa dB (fun type bool)
% 3.75/3.97              (aa (fun nat type) (fun dB (fun type bool)) typing
% 3.75/3.97                (aa type (fun nat type)
% 3.75/3.97                  (aa nat (fun type (fun nat type)) (aa (fun nat type) (fun nat (fun type (fun nat type))) (shift type) e)
% 3.75/3.97                    i)
% 3.75/3.97                  t))
% 3.75/3.97              a)
% 3.75/3.97            U) →
% 3.75/3.97        thesis)
% 3.75/3.97    True
% 3.75/3.97  Clause #115 (by assumption #[]): Eq (Not thesis) True
% 3.75/3.97  Clause #116 (by clausification #[115]): Eq thesis False
% 3.75/3.97  Clause #118 (by clausification #[114]): ∀ (a_1 : type),
% 3.75/3.97    Eq
% 3.75/3.97      (pp
% 3.75/3.97          (aa type bool
% 3.75/3.97            (aa dB (fun type bool)
% 3.75/3.97              (aa (fun nat type) (fun dB (fun type bool)) typing
% 3.75/3.97                (aa type (fun nat type)
% 3.75/3.97                  (aa nat (fun type (fun nat type)) (aa (fun nat type) (fun nat (fun type (fun nat type))) (shift type) e)
% 3.75/3.97                    i)
% 3.75/3.97                  t))
% 3.75/3.97              a)
% 3.75/3.97            a_1) →
% 3.75/3.97        thesis)
% 3.75/3.97      True
% 3.75/3.97  Clause #119 (by clausification #[118]): ∀ (a_1 : type),
% 3.75/3.97    Or
% 3.75/3.97      (Eq
% 3.75/3.97        (pp
% 3.75/3.97          (aa type bool
% 3.75/3.97            (aa dB (fun type bool)
% 3.75/3.97              (aa (fun nat type) (fun dB (fun type bool)) typing
% 3.75/3.97                (aa type (fun nat type)
% 3.75/3.97                  (aa nat (fun type (fun nat type)) (aa (fun nat type) (fun nat (fun type (fun nat type))) (shift type) e)
% 3.75/3.97                    i)
% 3.75/3.97                  t))
% 3.75/3.97              a)
% 3.75/3.97            a_1))
% 3.75/3.97        False)
% 3.75/3.97      (Eq thesis True)
% 3.75/3.97  Clause #120 (by forward demodulation #[119, 116]): ∀ (a_1 : type),
% 3.75/3.97    Or
% 3.75/3.97      (Eq
% 3.75/3.97        (pp
% 3.75/3.97          (aa type bool
% 3.75/3.97            (aa dB (fun type bool)
% 3.75/3.97              (aa (fun nat type) (fun dB (fun type bool)) typing
% 3.75/3.97                (aa type (fun nat type)
% 3.75/3.97                  (aa nat (fun type (fun nat type)) (aa (fun nat type) (fun nat (fun type (fun nat type))) (shift type) e)
% 3.75/3.97                    i)
% 3.75/3.97                  t))
% 3.75/3.97              a)
% 3.75/3.97            a_1))
% 3.75/3.97        False)
% 3.75/3.97      (Eq False True)
% 3.75/3.97  Clause #121 (by clausification #[120]): ∀ (a_1 : type),
% 3.75/3.97    Eq
% 3.75/3.97      (pp
% 3.75/3.97        (aa type bool
% 3.75/3.97          (aa dB (fun type bool)
% 3.75/3.97            (aa (fun nat type) (fun dB (fun type bool)) typing
% 3.75/3.97              (aa type (fun nat type)
% 3.75/3.97                (aa nat (fun type (fun nat type)) (aa (fun nat type) (fun nat (fun type (fun nat type))) (shift type) e)
% 3.75/3.97                  i)
% 3.75/3.97                t))
% 3.75/3.97            a)
% 3.75/3.97          a_1))
% 3.75/3.97      False
% 3.75/3.97  Clause #142 (by clausification #[2]): Eq
% 3.75/3.97    (Exists fun X11 =>
% 3.75/3.97      pp
% 3.75/3.97        (aa type bool
% 3.75/3.97          (aa dB (fun type bool)
% 3.75/3.97            (aa (fun nat type) (fun dB (fun type bool)) typing
% 3.75/3.97              (aa type (fun nat type)
% 3.75/3.97                (aa nat (fun type (fun nat type)) (aa (fun nat type) (fun nat (fun type (fun nat type))) (shift type) e)
% 3.75/3.97                  i)
% 3.75/3.97                t))
% 3.75/3.97            a)
% 3.75/3.97          X11))
% 3.75/3.97    True
% 3.75/3.97  Clause #143 (by clausification #[142]): ∀ (a_1 : type),
% 3.75/3.97    Eq
% 3.75/3.97      (pp
% 3.75/3.97        (aa type bool
% 3.75/3.97          (aa dB (fun type bool)
% 3.75/3.97            (aa (fun nat type) (fun dB (fun type bool)) typing
% 3.75/3.97              (aa type (fun nat type)
% 3.75/3.97                (aa nat (fun type (fun nat type)) (aa (fun nat type) (fun nat (fun type (fun nat type))) (shift type) e)
% 3.75/3.97                  i)
% 3.75/3.97                t))
% 3.75/3.97            a)
% 3.75/3.97          (skS.0 0 a_1)))
% 3.75/3.97      True
% 3.75/3.97  Clause #144 (by superposition #[143, 121]): Eq True False
% 3.75/3.97  Clause #145 (by clausification #[144]): False
% 3.75/3.97  SZS output end Proof for theBenchmark.p
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