TSTP Solution File: LCL793_5 by Duper---1.0

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : Duper---1.0
% Problem  : LCL793_5 : TPTP v8.1.2. Released v6.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : duper %s

% Computer : n032.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Thu Aug 31 07:11:16 EDT 2023

% Result   : Theorem 6.11s 6.31s
% Output   : Proof 6.11s
% Verified : 
% SZS Type : -

% Comments : 
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.09  % Problem    : LCL793_5 : TPTP v8.1.2. Released v6.0.0.
% 0.00/0.10  % Command    : duper %s
% 0.11/0.29  % Computer : n032.cluster.edu
% 0.11/0.29  % Model    : x86_64 x86_64
% 0.11/0.29  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.11/0.29  % Memory   : 8042.1875MB
% 0.11/0.29  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.11/0.29  % CPULimit   : 300
% 0.11/0.29  % WCLimit    : 300
% 0.11/0.29  % DateTime   : Thu Aug 24 18:34:12 EDT 2023
% 0.11/0.29  % CPUTime    : 
% 6.11/6.31  SZS status Theorem for theBenchmark.p
% 6.11/6.31  SZS output start Proof for theBenchmark.p
% 6.11/6.31  Clause #2 (by assumption #[]): Eq (it u) True
% 6.11/6.31  Clause #4 (by assumption #[]): Eq (∀ (I : nat) (T : dB), it T → it (lift T I)) True
% 6.11/6.31  Clause #6 (by assumption #[]): Eq (∀ (I : nat) (T : dB), it T → it (app T (var I))) True
% 6.11/6.31  Clause #110 (by assumption #[]): Eq (Not (it (app (lift u (zero_zero nat)) (var (zero_zero nat))))) True
% 6.11/6.31  Clause #117 (by clausification #[4]): ∀ (a : nat), Eq (∀ (T : dB), it T → it (lift T a)) True
% 6.11/6.31  Clause #118 (by clausification #[117]): ∀ (a : dB) (a_1 : nat), Eq (it a → it (lift a a_1)) True
% 6.11/6.31  Clause #119 (by clausification #[118]): ∀ (a : dB) (a_1 : nat), Or (Eq (it a) False) (Eq (it (lift a a_1)) True)
% 6.11/6.31  Clause #122 (by superposition #[119, 2]): ∀ (a : nat), Or (Eq (it (lift u a)) True) (Eq False True)
% 6.11/6.31  Clause #125 (by clausification #[122]): ∀ (a : nat), Eq (it (lift u a)) True
% 6.11/6.31  Clause #127 (by clausification #[6]): ∀ (a : nat), Eq (∀ (T : dB), it T → it (app T (var a))) True
% 6.11/6.31  Clause #128 (by clausification #[127]): ∀ (a : dB) (a_1 : nat), Eq (it a → it (app a (var a_1))) True
% 6.11/6.31  Clause #129 (by clausification #[128]): ∀ (a : dB) (a_1 : nat), Or (Eq (it a) False) (Eq (it (app a (var a_1))) True)
% 6.11/6.31  Clause #134 (by superposition #[129, 125]): ∀ (a a_1 : nat), Or (Eq (it (app (lift u a) (var a_1))) True) (Eq False True)
% 6.11/6.31  Clause #374 (by clausification #[134]): ∀ (a a_1 : nat), Eq (it (app (lift u a) (var a_1))) True
% 6.11/6.31  Clause #1780 (by clausification #[110]): Eq (it (app (lift u (zero_zero nat)) (var (zero_zero nat)))) False
% 6.11/6.31  Clause #1781 (by superposition #[1780, 374]): Eq False True
% 6.11/6.31  Clause #1785 (by clausification #[1781]): False
% 6.11/6.31  SZS output end Proof for theBenchmark.p
%------------------------------------------------------------------------------