%------------------------------------------------------------------------------
% File     : Duper---1.0
% Problem  : LCL792_5 : TPTP v8.1.2. Released v6.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : duper %s

% Computer : n013.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Thu Aug 31 07:11:16 EDT 2023

% Result   : Theorem 3.72s 3.87s
% Output   : Proof 3.72s
% Verified : 
% SZS Type : -

% Comments : 
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.12  % Problem    : LCL792_5 : TPTP v8.1.2. Released v6.0.0.
% 0.00/0.13  % Command    : duper %s
% 0.18/0.34  % Computer : n013.cluster.edu
% 0.18/0.34  % Model    : x86_64 x86_64
% 0.18/0.34  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.18/0.34  % Memory   : 8042.1875MB
% 0.18/0.34  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.18/0.34  % CPULimit   : 300
% 0.18/0.34  % WCLimit    : 300
% 0.18/0.35  % DateTime   : Fri Aug 25 00:52:17 EDT 2023
% 0.18/0.35  % CPUTime    : 
% 3.72/3.87  SZS status Theorem for theBenchmark.p
% 3.72/3.87  SZS output start Proof for theBenchmark.p
% 3.72/3.87  Clause #2 (by assumption #[]): Eq (it u) True
% 3.72/3.87  Clause #3 (by assumption #[]): Eq (∀ (I : nat) (T : dB), it T → it (lift T I)) True
% 3.72/3.87  Clause #123 (by assumption #[]): Eq (Not (it (lift u (zero_zero nat)))) True
% 3.72/3.87  Clause #124 (by clausification #[3]): ∀ (a : nat), Eq (∀ (T : dB), it T → it (lift T a)) True
% 3.72/3.87  Clause #125 (by clausification #[124]): ∀ (a : dB) (a_1 : nat), Eq (it a → it (lift a a_1)) True
% 3.72/3.87  Clause #126 (by clausification #[125]): ∀ (a : dB) (a_1 : nat), Or (Eq (it a) False) (Eq (it (lift a a_1)) True)
% 3.72/3.87  Clause #129 (by superposition #[126, 2]): ∀ (a : nat), Or (Eq (it (lift u a)) True) (Eq False True)
% 3.72/3.87  Clause #142 (by clausification #[129]): ∀ (a : nat), Eq (it (lift u a)) True
% 3.72/3.87  Clause #146 (by clausification #[123]): Eq (it (lift u (zero_zero nat))) False
% 3.72/3.87  Clause #147 (by superposition #[146, 142]): Eq False True
% 3.72/3.87  Clause #148 (by clausification #[147]): False
% 3.72/3.87  SZS output end Proof for theBenchmark.p
%------------------------------------------------------------------------------