TSTP Solution File: LCL773_5 by Duper---1.0
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% File : Duper---1.0
% Problem : LCL773_5 : TPTP v8.1.2. Released v6.0.0.
% Transfm : none
% Format : tptp:raw
% Command : duper %s
% Computer : n032.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 300s
% DateTime : Thu Aug 31 07:11:10 EDT 2023
% Result : Theorem 7.05s 7.25s
% Output : Proof 7.05s
% Verified :
% SZS Type : -
% Comments :
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.10 % Problem : LCL773_5 : TPTP v8.1.2. Released v6.0.0.
% 0.00/0.11 % Command : duper %s
% 0.12/0.31 % Computer : n032.cluster.edu
% 0.12/0.31 % Model : x86_64 x86_64
% 0.12/0.31 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.31 % Memory : 8042.1875MB
% 0.12/0.31 % OS : Linux 3.10.0-693.el7.x86_64
% 0.12/0.31 % CPULimit : 300
% 0.12/0.31 % WCLimit : 300
% 0.12/0.31 % DateTime : Fri Aug 25 05:23:42 EDT 2023
% 0.12/0.31 % CPUTime :
% 7.05/7.25 SZS status Theorem for theBenchmark.p
% 7.05/7.25 SZS output start Proof for theBenchmark.p
% 7.05/7.25 Clause #1 (by assumption #[]): Eq (∀ (J I : nat) (R2 : dB), pp (aa dB bool it R2) → pp (aa dB bool it (subst R2 (var I) J))) True
% 7.05/7.25 Clause #109 (by assumption #[]): Eq (pp (aa dB bool it r)) True
% 7.05/7.25 Clause #111 (by assumption #[]): Eq (Not (pp (aa dB bool it (subst r (var i) (zero_zero nat))))) True
% 7.05/7.25 Clause #113 (by clausification #[1]): ∀ (a : nat), Eq (∀ (I : nat) (R2 : dB), pp (aa dB bool it R2) → pp (aa dB bool it (subst R2 (var I) a))) True
% 7.05/7.25 Clause #114 (by clausification #[113]): ∀ (a a_1 : nat), Eq (∀ (R2 : dB), pp (aa dB bool it R2) → pp (aa dB bool it (subst R2 (var a) a_1))) True
% 7.05/7.25 Clause #115 (by clausification #[114]): ∀ (a : dB) (a_1 a_2 : nat), Eq (pp (aa dB bool it a) → pp (aa dB bool it (subst a (var a_1) a_2))) True
% 7.05/7.25 Clause #116 (by clausification #[115]): ∀ (a : dB) (a_1 a_2 : nat), Or (Eq (pp (aa dB bool it a)) False) (Eq (pp (aa dB bool it (subst a (var a_1) a_2))) True)
% 7.05/7.25 Clause #119 (by superposition #[109, 116]): ∀ (a a_1 : nat), Or (Eq (pp (aa dB bool it (subst r (var a) a_1))) True) (Eq False True)
% 7.05/7.25 Clause #2273 (by clausification #[111]): Eq (pp (aa dB bool it (subst r (var i) (zero_zero nat)))) False
% 7.05/7.25 Clause #2357 (by clausification #[119]): ∀ (a a_1 : nat), Eq (pp (aa dB bool it (subst r (var a) a_1))) True
% 7.05/7.25 Clause #2361 (by superposition #[2357, 2273]): Eq True False
% 7.05/7.25 Clause #2392 (by clausification #[2361]): False
% 7.05/7.25 SZS output end Proof for theBenchmark.p
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