TSTP Solution File: LCL666+1.001 by Twee---2.4.2
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% File : Twee---2.4.2
% Problem : LCL666+1.001 : TPTP v8.1.2. Released v4.0.0.
% Transfm : none
% Format : tptp:raw
% Command : parallel-twee %s --tstp --conditional-encoding if --smaller --drop-non-horn --give-up-on-saturation --explain-encoding --formal-proof
% Computer : n017.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 300s
% DateTime : Thu Aug 31 08:19:58 EDT 2023
% Result : Theorem 0.21s 0.39s
% Output : Proof 0.21s
% Verified :
% SZS Type : -
% Comments :
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.08/0.13 % Problem : LCL666+1.001 : TPTP v8.1.2. Released v4.0.0.
% 0.08/0.14 % Command : parallel-twee %s --tstp --conditional-encoding if --smaller --drop-non-horn --give-up-on-saturation --explain-encoding --formal-proof
% 0.13/0.35 % Computer : n017.cluster.edu
% 0.13/0.35 % Model : x86_64 x86_64
% 0.13/0.35 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.35 % Memory : 8042.1875MB
% 0.13/0.35 % OS : Linux 3.10.0-693.el7.x86_64
% 0.13/0.35 % CPULimit : 300
% 0.13/0.35 % WCLimit : 300
% 0.13/0.36 % DateTime : Fri Aug 25 06:36:10 EDT 2023
% 0.13/0.36 % CPUTime :
% 0.21/0.39 Command-line arguments: --no-flatten-goal
% 0.21/0.39
% 0.21/0.39 % SZS status Theorem
% 0.21/0.39
% 0.21/0.39 % SZS output start Proof
% 0.21/0.39 Take the following subset of the input axioms:
% 0.21/0.39 fof(main, conjecture, ~?[X]: ~(~![Y]: (~r1(X, Y) | ~(p201(Y) & p101(Y))) | ~(p201(X) & p101(X)))).
% 0.21/0.39 fof(reflexivity, axiom, ![X2]: r1(X2, X2)).
% 0.21/0.39
% 0.21/0.39 Now clausify the problem and encode Horn clauses using encoding 3 of
% 0.21/0.39 http://www.cse.chalmers.se/~nicsma/papers/horn.pdf.
% 0.21/0.39 We repeatedly replace C & s=t => u=v by the two clauses:
% 0.21/0.39 fresh(y, y, x1...xn) = u
% 0.21/0.39 C => fresh(s, t, x1...xn) = v
% 0.21/0.39 where fresh is a fresh function symbol and x1..xn are the free
% 0.21/0.39 variables of u and v.
% 0.21/0.39 A predicate p(X) is encoded as p(X)=true (this is sound, because the
% 0.21/0.39 input problem has no model of domain size 1).
% 0.21/0.39
% 0.21/0.39 The encoding turns the above axioms into the following unit equations and goals:
% 0.21/0.39
% 0.21/0.39 Axiom 1 (main): p201(x) = true2.
% 0.21/0.39 Axiom 2 (main_1): p101(x) = true2.
% 0.21/0.39 Axiom 3 (reflexivity): r1(X, X) = true2.
% 0.21/0.39
% 0.21/0.39 Goal 1 (main_2): tuple(r1(x, X), p201(X), p101(X)) = tuple(true2, true2, true2).
% 0.21/0.39 The goal is true when:
% 0.21/0.39 X = x
% 0.21/0.39
% 0.21/0.39 Proof:
% 0.21/0.39 tuple(r1(x, x), p201(x), p101(x))
% 0.21/0.39 = { by axiom 1 (main) }
% 0.21/0.39 tuple(r1(x, x), true2, p101(x))
% 0.21/0.39 = { by axiom 3 (reflexivity) }
% 0.21/0.39 tuple(true2, true2, p101(x))
% 0.21/0.39 = { by axiom 2 (main_1) }
% 0.21/0.39 tuple(true2, true2, true2)
% 0.21/0.39 % SZS output end Proof
% 0.21/0.39
% 0.21/0.39 RESULT: Theorem (the conjecture is true).
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