TSTP Solution File: LCL666+1.001 by Geo-III---2018C

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : Geo-III---2018C
% Problem  : LCL666+1.001 : TPTP v8.1.0. Released v4.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : geo -tptp_input -nonempty -inputfile %s

% Computer : n007.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Sat Jul 23 06:09:46 EDT 2022

% Result   : Theorem 0.20s 0.33s
% Output   : Refutation 0.20s
% Verified : 
% SZS Type : -

% Comments : 
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.11  % Problem  : LCL666+1.001 : TPTP v8.1.0. Released v4.0.0.
% 0.11/0.12  % Command  : geo -tptp_input -nonempty -inputfile %s
% 0.13/0.33  % Computer : n007.cluster.edu
% 0.13/0.33  % Model    : x86_64 x86_64
% 0.13/0.33  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.33  % Memory   : 8042.1875MB
% 0.13/0.33  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.13/0.33  % CPULimit : 300
% 0.13/0.33  % WCLimit  : 300
% 0.20/0.33  % DateTime : Fri Jul 22 22:37:42 EDT 2022
% 0.20/0.33  % CPUTime  : 
% 0.20/0.33  GeoParameters:
% 0.20/0.33  
% 0.20/0.33  tptp_input =     1
% 0.20/0.33  tptp_output =    0
% 0.20/0.33  nonempty =       1
% 0.20/0.33  inputfile =      /export/starexec/sandbox/benchmark/theBenchmark.p
% 0.20/0.33  includepath =    /export/starexec/sandbox/solver/bin/../../benchmark/
% 0.20/0.33  
% 0.20/0.33  
% 0.20/0.33  % SZS status Theorem for /export/starexec/sandbox/benchmark/theBenchmark.p
% 0.20/0.33  % SZS output start Refutation for /export/starexec/sandbox/benchmark/theBenchmark.p
% 0.20/0.33  
% 0.20/0.33  RuleSystem INPUT:
% 0.20/0.33  
% 0.20/0.33  Initial Rules:
% 0.20/0.33  #0: input, references = 4, size of lhs = 1:
% 0.20/0.33     #-{F} V0 | r1-{T}(V0,V0)
% 0.20/0.33        (used 0 times, uses = {})
% 0.20/0.33  
% 0.20/0.33  #1: input, references = 4, size of lhs = 0:
% 0.20/0.33     FALSE | EXISTS V0: pppp0-{T}(V0)
% 0.20/0.33        (used 0 times, uses = {})
% 0.20/0.33  
% 0.20/0.33  #2: input, references = 4, size of lhs = 1:
% 0.20/0.33     pppp0-{F}(V0) | p101-{T}(V0)
% 0.20/0.33        (used 0 times, uses = {})
% 0.20/0.33  
% 0.20/0.33  #3: input, references = 4, size of lhs = 1:
% 0.20/0.33     pppp0-{F}(V0) | p201-{T}(V0)
% 0.20/0.33        (used 0 times, uses = {})
% 0.20/0.33  
% 0.20/0.33  #4: input, references = 4, size of lhs = 4:
% 0.20/0.33     pppp0-{F}(V0), r1-{F}(V0,V1), p201-{F}(V1), p101-{F}(V1) | FALSE
% 0.20/0.33        (used 0 times, uses = {})
% 0.20/0.33  
% 0.20/0.33  number of initial rules = 5
% 0.20/0.33  
% 0.20/0.33  Simplifiers:
% 0.20/0.33  #5: unsound, references = 3, size of lhs = 2:
% 0.20/0.33     r1-{F}(V0,V1), V1 == V0 | FALSE
% 0.20/0.33        (used 0 times, uses = {})
% 0.20/0.33  
% 0.20/0.33  #6: unsound, references = 3, size of lhs = 3:
% 0.20/0.33     p201-{F}(V0), p201-{F}(V1), V0 == V1 | FALSE
% 0.20/0.33        (used 0 times, uses = {})
% 0.20/0.33  
% 0.20/0.33  #7: unsound, references = 3, size of lhs = 3:
% 0.20/0.33     p101-{F}(V0), p101-{F}(V1), V0 == V1 | FALSE
% 0.20/0.33        (used 0 times, uses = {})
% 0.20/0.33  
% 0.20/0.33  #8: unsound, references = 3, size of lhs = 3:
% 0.20/0.33     pppp0-{F}(V0), pppp0-{F}(V1), V0 == V1 | FALSE
% 0.20/0.33        (used 0 times, uses = {})
% 0.20/0.33  
% 0.20/0.33  number of simplifiers = 4
% 0.20/0.33  
% 0.20/0.33  Learnt:
% 0.20/0.33  #13: exists( #1, #11 ), references = 1, size of lhs = 0:
% 0.20/0.33     FALSE | FALSE
% 0.20/0.33        (used 0 times, uses = {})
% 0.20/0.33  
% 0.20/0.33  number of learnt formulas = 1
% 0.20/0.33  
% 0.20/0.33  
% 0.20/0.33  % SZS output end Refutation for /export/starexec/sandbox/benchmark/theBenchmark.p
% 0.20/0.33  
% 0.20/0.33  randbase = 1
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