TSTP Solution File: LCL643+1.001 by DarwinFM---1.4.5

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : DarwinFM---1.4.5
% Problem  : LCL643+1.001 : TPTP v8.1.0. Released v4.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : darwin -fd true -ppp true -pl 0 -to %d -pmtptp true %s

% Computer : n004.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 0s
% DateTime : Sun Jul 17 08:56:42 EDT 2022

% Result   : CounterSatisfiable 0.19s 0.53s
% Output   : FiniteModel 0.19s
% Verified : 
% SZS Type : FiniteModel
%            Domain size           :    1

% Comments : 
%------------------------------------------------------------------------------
fof(interpretation_domain,fi_domain,
    ! [X] : X = e1 ).

fof(interpretation_terms,fi_functors,
    ( ! [X0] : esk10_1(X0) = e1
    & ! [X0] : esk11_1(X0) = e1
    & ! [X0] : esk12_1(X0) = e1
    & ! [X0] : esk13_1(X0) = e1
    & ! [X0] : esk14_1(X0) = e1
    & ! [X0] : esk15_1(X0) = e1
    & ! [X0] : esk16_1(X0) = e1
    & ! [X0,X1] : esk17_2(X0,X1) = e1
    & ! [X0,X1] : esk18_2(X0,X1) = e1
    & ! [X0,X1,X2,X3,X4] : esk19_5(X0,X1,X2,X3,X4) = e1
    & esk1_0 = e1
    & ! [X0,X1,X2,X3,X4] : esk20_5(X0,X1,X2,X3,X4) = e1
    & ! [X0,X1,X2] : esk21_3(X0,X1,X2) = e1
    & ! [X0,X1,X2] : esk22_3(X0,X1,X2) = e1
    & ! [X0,X1,X2] : esk23_3(X0,X1,X2) = e1
    & ! [X0,X1] : esk24_2(X0,X1) = e1
    & ! [X0,X1] : esk25_2(X0,X1) = e1
    & ! [X0,X1,X2] : esk26_3(X0,X1,X2) = e1
    & ! [X0,X1,X2] : esk27_3(X0,X1,X2) = e1
    & ! [X0] : esk2_1(X0) = e1
    & ! [X0] : esk3_1(X0) = e1
    & ! [X0] : esk4_1(X0) = e1
    & ! [X0] : esk5_1(X0) = e1
    & ! [X0] : esk6_1(X0) = e1
    & ! [X0] : esk7_1(X0) = e1
    & ! [X0,X1,X2] : esk8_3(X0,X1,X2) = e1
    & ! [X0,X1,X2] : esk9_3(X0,X1,X2) = e1 ) ).

fof(interpretation_atoms,fi_predicates,
    ( ! [X0] :
        ( epred1_1(X0)
      <=> $false )
    & ! [X0] :
        ( p1(X0)
      <=> $false )
    & ! [X0] :
        ( p2(X0)
      <=> $false )
    & ! [X0] :
        ( p3(X0)
      <=> $false )
    & ! [X0,X1] :
        ( r1(X0,X1)
      <=> $false ) ) ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.11/0.12  % Problem  : LCL643+1.001 : TPTP v8.1.0. Released v4.0.0.
% 0.11/0.13  % Command  : darwin -fd true -ppp true -pl 0 -to %d -pmtptp true %s
% 0.13/0.34  % Computer : n004.cluster.edu
% 0.13/0.34  % Model    : x86_64 x86_64
% 0.13/0.34  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.34  % Memory   : 8042.1875MB
% 0.13/0.34  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.13/0.34  % CPULimit : 300
% 0.13/0.34  % DateTime : Sun Jul  3 23:19:08 EDT 2022
% 0.13/0.35  % CPUTime  : 
% 0.13/0.35  Defaulting to tptp format.
% 0.19/0.53  SZS status CounterSatisfiable for /export/starexec/sandbox/benchmark/theBenchmark.p
% 0.19/0.53  
% 0.19/0.53  MODEL (TPTP):
% 0.19/0.53  SZS output start FiniteModel for /export/starexec/sandbox/benchmark/theBenchmark.p
% See solution above
%------------------------------------------------------------------------------