TSTP Solution File: LCL512+1 by SATCoP---0.1
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- Process Solution
%------------------------------------------------------------------------------
% File : SATCoP---0.1
% Problem : LCL512+1 : TPTP v8.1.0. Released v3.3.0.
% Transfm : none
% Format : tptp:raw
% Command : satcop --statistics %s
% Computer : n008.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 600s
% DateTime : Sun Jul 17 14:15:43 EDT 2022
% Result : Theorem 0.13s 0.35s
% Output : Proof 0.13s
% Verified :
% SZS Type : ERROR: Analysing output (MakeTreeStats fails)
% Comments :
%------------------------------------------------------------------------------
cnf(g0,plain,
~ equivalence_1,
inference(ground_cnf,[],[file('/export/starexec/sandbox/benchmark/theBenchmark.p',hilbert_equivalence_1)]) ).
cnf(g1,plain,
( ~ is_a_theorem(implies(equiv(sK26,sK27),implies(sK26,sK27)))
| equivalence_1 ),
inference(ground_cnf,[],[file('Axioms/LCL006+0.ax',equivalence_1)]) ).
cnf(g2,plain,
( ~ is_a_theorem(implies(and(sK13,sK14),sK13))
| and_1 ),
inference(ground_cnf,[],[file('Axioms/LCL006+0.ax',and_1)]) ).
cnf(g3,plain,
kn2,
inference(ground_cnf,[],[file('Axioms/LCL006+5.ax',rosser_kn2)]) ).
cnf(g4,plain,
sPE(implies(sK26,sK27),implies(sK26,sK27)),
inference(ground_cnf,[],[theory(equality)]) ).
cnf(g5,plain,
( ~ sPE(implies(and(implies(sK26,sK27),implies(sK27,sK26)),implies(sK26,sK27)),implies(equiv(sK26,sK27),implies(sK26,sK27)))
| ~ is_a_theorem(implies(and(implies(sK26,sK27),implies(sK27,sK26)),implies(sK26,sK27)))
| is_a_theorem(implies(equiv(sK26,sK27),implies(sK26,sK27))) ),
inference(ground_cnf,[],[theory(equality)]) ).
cnf(g6,plain,
( ~ sPE(implies(equiv(sK26,sK27),implies(sK26,sK27)),implies(and(implies(sK26,sK27),implies(sK27,sK26)),implies(sK26,sK27)))
| sPE(implies(and(implies(sK26,sK27),implies(sK27,sK26)),implies(sK26,sK27)),implies(equiv(sK26,sK27),implies(sK26,sK27))) ),
inference(ground_cnf,[],[theory(equality)]) ).
cnf(g7,plain,
( ~ sPE(equiv(sK26,sK27),and(implies(sK26,sK27),implies(sK27,sK26)))
| ~ sPE(implies(sK26,sK27),implies(sK26,sK27))
| sPE(implies(equiv(sK26,sK27),implies(sK26,sK27)),implies(and(implies(sK26,sK27),implies(sK27,sK26)),implies(sK26,sK27))) ),
inference(ground_cnf,[],[theory(equality)]) ).
cnf(g8,plain,
( ~ op_equiv
| sPE(equiv(sK26,sK27),and(implies(sK26,sK27),implies(sK27,sK26))) ),
inference(ground_cnf,[],[file('Axioms/LCL006+1.ax',op_equiv)]) ).
cnf(g9,plain,
op_equiv,
inference(ground_cnf,[],[file('Axioms/LCL006+5.ax',rosser_op_equiv)]) ).
cnf(g10,plain,
( ~ kn2
| is_a_theorem(implies(and(sK13,sK14),sK13)) ),
inference(ground_cnf,[],[file('Axioms/LCL006+0.ax',kn2)]) ).
cnf(g11,plain,
( ~ and_1
| is_a_theorem(implies(and(implies(sK26,sK27),implies(sK27,sK26)),implies(sK26,sK27))) ),
inference(ground_cnf,[],[file('Axioms/LCL006+0.ax',and_1)]) ).
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.03/0.11 % Problem : LCL512+1 : TPTP v8.1.0. Released v3.3.0.
% 0.03/0.12 % Command : satcop --statistics %s
% 0.13/0.33 % Computer : n008.cluster.edu
% 0.13/0.33 % Model : x86_64 x86_64
% 0.13/0.33 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.33 % Memory : 8042.1875MB
% 0.13/0.33 % OS : Linux 3.10.0-693.el7.x86_64
% 0.13/0.33 % CPULimit : 300
% 0.13/0.33 % WCLimit : 600
% 0.13/0.33 % DateTime : Mon Jul 4 09:27:53 EDT 2022
% 0.13/0.33 % CPUTime :
% 0.13/0.35 % symbols: 94
% 0.13/0.35 % clauses: 81
% 0.13/0.35 % start clauses: 1
% 0.13/0.35 % iterative deepening steps: 165
% 0.13/0.35 % maximum path limit: 5
% 0.13/0.35 % literal attempts: 8617
% 0.13/0.35 % depth failures: 5789
% 0.13/0.35 % regularity failures: 429
% 0.13/0.35 % tautology failures: 320
% 0.13/0.35 % reductions: 0
% 0.13/0.35 % extensions: 8482
% 0.13/0.35 % SAT variables: 4712
% 0.13/0.35 % SAT clauses: 5140
% 0.13/0.35 % WalkSAT solutions: 5139
% 0.13/0.35 % CDCL solutions: 0
% 0.13/0.35 % SZS status Theorem for theBenchmark
% 0.13/0.35 % SZS output start ListOfCNF for theBenchmark
% See solution above
%------------------------------------------------------------------------------