TSTP Solution File: LCL439-2 by SOS---2.0
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- Process Solution
%------------------------------------------------------------------------------
% File : SOS---2.0
% Problem : LCL439-2 : TPTP v8.1.0. Released v3.2.0.
% Transfm : none
% Format : tptp:raw
% Command : sos-script %s
% Computer : n008.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 600s
% DateTime : Sun Jul 17 14:30:15 EDT 2022
% Result : Unsatisfiable 0.15s 0.43s
% Output : Refutation 0.15s
% Verified :
% SZS Type : -
% Comments :
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.03/0.14 % Problem : LCL439-2 : TPTP v8.1.0. Released v3.2.0.
% 0.14/0.15 % Command : sos-script %s
% 0.15/0.36 % Computer : n008.cluster.edu
% 0.15/0.36 % Model : x86_64 x86_64
% 0.15/0.36 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.15/0.36 % Memory : 8042.1875MB
% 0.15/0.36 % OS : Linux 3.10.0-693.el7.x86_64
% 0.15/0.36 % CPULimit : 300
% 0.15/0.36 % WCLimit : 600
% 0.15/0.36 % DateTime : Sat Jul 2 20:12:38 EDT 2022
% 0.15/0.37 % CPUTime :
% 0.15/0.38 ----- Otter 3.2, August 2001 -----
% 0.15/0.38 The process was started by sandbox on n008.cluster.edu,
% 0.15/0.38 Sat Jul 2 20:12:38 2022
% 0.15/0.38 The command was "./sos". The process ID is 7880.
% 0.15/0.38
% 0.15/0.38 set(prolog_style_variables).
% 0.15/0.38 set(auto).
% 0.15/0.38 dependent: set(auto1).
% 0.15/0.38 dependent: set(process_input).
% 0.15/0.38 dependent: clear(print_kept).
% 0.15/0.38 dependent: clear(print_new_demod).
% 0.15/0.38 dependent: clear(print_back_demod).
% 0.15/0.38 dependent: clear(print_back_sub).
% 0.15/0.38 dependent: set(control_memory).
% 0.15/0.38 dependent: assign(max_mem, 12000).
% 0.15/0.38 dependent: assign(pick_given_ratio, 4).
% 0.15/0.38 dependent: assign(stats_level, 1).
% 0.15/0.38 dependent: assign(pick_semantic_ratio, 3).
% 0.15/0.38 dependent: assign(sos_limit, 5000).
% 0.15/0.38 dependent: assign(max_weight, 60).
% 0.15/0.38 clear(print_given).
% 0.15/0.38
% 0.15/0.38 list(usable).
% 0.15/0.38
% 0.15/0.38 SCAN INPUT: prop=0, horn=1, equality=0, symmetry=0, max_lits=3.
% 0.15/0.38
% 0.15/0.38 This is a Horn set without equality. The strategy will
% 0.15/0.38 be hyperresolution, with satellites in sos and nuclei
% 0.15/0.38 in usable.
% 0.15/0.38
% 0.15/0.38 dependent: set(hyper_res).
% 0.15/0.38 dependent: clear(order_hyper).
% 0.15/0.38
% 0.15/0.38 ------------> process usable:
% 0.15/0.38
% 0.15/0.38 ------------> process sos:
% 0.15/0.38
% 0.15/0.38 ======= end of input processing =======
% 0.15/0.43
% 0.15/0.43 Model 1 (0.00 seconds, 0 Inserts)
% 0.15/0.43
% 0.15/0.43 Stopped by limit on number of solutions
% 0.15/0.43
% 0.15/0.43
% 0.15/0.43 -------------- Softie stats --------------
% 0.15/0.43
% 0.15/0.43 UPDATE_STOP: 300
% 0.15/0.43 SFINDER_TIME_LIMIT: 2
% 0.15/0.43 SHORT_CLAUSE_CUTOFF: 4
% 0.15/0.43 number of clauses in intial UL: 5
% 0.15/0.43 number of clauses initially in problem: 7
% 0.15/0.43 percentage of clauses intially in UL: 71
% 0.15/0.43 percentage of distinct symbols occuring in initial UL: 100
% 0.15/0.43 percent of all initial clauses that are short: 85
% 0.15/0.43 absolute distinct symbol count: 10
% 0.15/0.43 distinct predicate count: 1
% 0.15/0.43 distinct function count: 4
% 0.15/0.43 distinct constant count: 5
% 0.15/0.43
% 0.15/0.43 ---------- no more Softie stats ----------
% 0.15/0.43
% 0.15/0.43
% 0.15/0.43
% 0.15/0.43 Model 2 (0.00 seconds, 0 Inserts)
% 0.15/0.43
% 0.15/0.43 Stopped by limit on number of solutions
% 0.15/0.43
% 0.15/0.43 =========== start of search ===========
% 0.15/0.43
% 0.15/0.43 -------- PROOF --------
% 0.15/0.43 % SZS status Unsatisfiable
% 0.15/0.43 % SZS output start Refutation
% 0.15/0.43
% 0.15/0.43 ----> UNIT CONFLICT at 0.02 sec ----> 29 [binary,28.1,5.1] {+} $F.
% 0.15/0.43
% 0.15/0.43 Length of proof is 4. Level of proof is 3.
% 0.15/0.43
% 0.15/0.43 ---------------- PROOF ----------------
% 0.15/0.43 % SZS status Unsatisfiable
% 0.15/0.43 % SZS output start Refutation
% 0.15/0.43
% 0.15/0.43 1 [] {+} -c_in(A,c_PropLog_Othms(c_insert(B,C,tc_PropLog_Opl(D)),D),tc_PropLog_Opl(D))|c_in(c_PropLog_Opl_Oop_A_N_62(B,A,D),c_PropLog_Othms(C,D),tc_PropLog_Opl(D)).
% 0.15/0.43 2 [] {+} -c_in(A,B,tc_PropLog_Opl(C))|c_in(A,c_PropLog_Othms(B,C),tc_PropLog_Opl(C)).
% 0.15/0.43 3 [] {+} -c_in(A,c_PropLog_Othms(B,C),tc_PropLog_Opl(C))| -c_in(c_PropLog_Opl_Oop_A_N_62(A,c_PropLog_Opl_Ofalse,C),c_PropLog_Othms(B,C),tc_PropLog_Opl(C))|c_in(D,c_PropLog_Othms(B,C),tc_PropLog_Opl(C)).
% 0.15/0.43 4 [] {+} -c_in(A,c_PropLog_Othms(B,C),tc_PropLog_Opl(C))|c_in(A,c_PropLog_Othms(c_insert(D,B,tc_PropLog_Opl(C)),C),tc_PropLog_Opl(C)).
% 0.15/0.43 5 [] {+} -c_in(c_PropLog_Opl_Oop_A_N_62(v_p,v_q,t_a),c_PropLog_Othms(v_H,t_a),tc_PropLog_Opl(t_a)).
% 0.15/0.43 6 [] {+} c_in(A,c_insert(A,B,C),C).
% 0.15/0.43 7 [] {-} c_in(c_PropLog_Opl_Oop_A_N_62(v_p,c_PropLog_Opl_Ofalse,t_a),c_PropLog_Othms(v_H,t_a),tc_PropLog_Opl(t_a)).
% 0.15/0.43 8 [hyper,6,2] {+} c_in(A,c_PropLog_Othms(c_insert(A,B,tc_PropLog_Opl(C)),C),tc_PropLog_Opl(C)).
% 0.15/0.43 9 [hyper,7,4] {-} c_in(c_PropLog_Opl_Oop_A_N_62(v_p,c_PropLog_Opl_Ofalse,t_a),c_PropLog_Othms(c_insert(A,v_H,tc_PropLog_Opl(t_a)),t_a),tc_PropLog_Opl(t_a)).
% 0.15/0.43 18 [hyper,8,3,9] {-} c_in(A,c_PropLog_Othms(c_insert(v_p,v_H,tc_PropLog_Opl(t_a)),t_a),tc_PropLog_Opl(t_a)).
% 0.15/0.43 28 [hyper,18,1] {-} c_in(c_PropLog_Opl_Oop_A_N_62(v_p,A,t_a),c_PropLog_Othms(v_H,t_a),tc_PropLog_Opl(t_a)).
% 0.15/0.43 29 [binary,28.1,5.1] {+} $F.
% 0.15/0.43
% 0.15/0.43 % SZS output end Refutation
% 0.15/0.43 ------------ end of proof -------------
% 0.15/0.43
% 0.15/0.43
% 0.15/0.43 Search stopped by max_proofs option.
% 0.15/0.43
% 0.15/0.43
% 0.15/0.43 Search stopped by max_proofs option.
% 0.15/0.43
% 0.15/0.43 ============ end of search ============
% 0.15/0.43
% 0.15/0.43 ----------- soft-scott stats ----------
% 0.15/0.43
% 0.15/0.43 true clauses given 1 (14.3%)
% 0.15/0.43 false clauses given 6
% 0.15/0.43
% 0.15/0.43 FALSE TRUE
% 0.15/0.43 10 0 1
% 0.15/0.43 13 2 1
% 0.15/0.43 14 1 0
% 0.15/0.43 15 1 1
% 0.15/0.43 16 1 0
% 0.15/0.43 17 1 0
% 0.15/0.43 18 2 0
% 0.15/0.43 19 1 0
% 0.15/0.43 20 1 0
% 0.15/0.43 tot: 10 3 (23.1% true)
% 0.15/0.43
% 0.15/0.43
% 0.15/0.43 Model 2 (0.00 seconds, 0 Inserts)
% 0.15/0.43
% 0.15/0.43 That finishes the proof of the theorem.
% 0.15/0.43
% 0.15/0.43 Process 7880 finished Sat Jul 2 20:12:38 2022
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