TSTP Solution File: LCL354+1 by Fampire---1.3

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : Fampire---1.3
% Problem  : LCL354+1 : TPTP v8.1.0. Released v2.3.0.
% Transfm  : none
% Format   : tptp
% Command  : FlotterOnTPTP.pl -f oldtptp -s vampire -t %d %s

% Computer : n021.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 600s
% DateTime : Sun Jul 17 10:28:42 EDT 2022

% Result   : Unknown 0.19s 0.45s
% Output   : None 
% Verified : 
% SZS Type : -

% Comments : 
%------------------------------------------------------------------------------
%----No solution output by system
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.12  % Problem  : LCL354+1 : TPTP v8.1.0. Released v2.3.0.
% 0.12/0.12  % Command  : FlotterOnTPTP.pl -f oldtptp -s vampire -t %d %s
% 0.12/0.33  % Computer : n021.cluster.edu
% 0.12/0.33  % Model    : x86_64 x86_64
% 0.12/0.33  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.33  % Memory   : 8042.1875MB
% 0.12/0.33  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.12/0.33  % CPULimit : 300
% 0.12/0.33  % WCLimit  : 600
% 0.12/0.33  % DateTime : Sun Jul  3 08:37:15 EDT 2022
% 0.12/0.33  % CPUTime  : 
% 0.12/0.34  cs: Command not found.
% 0.19/0.45  
% 0.19/0.45  ERROR: Cannot translate to DFG with tptp4X
% 0.19/0.45  %--------------------------------------------------------------------------
% 0.19/0.45  % File     : LCL354+1 : TPTP v8.0.0. Released v2.3.0.
% 0.19/0.45  % Domain   : Logic Calculi (Temporal)
% 0.19/0.45  % Problem  : Independence of an Axiom for Temporal Intervals
% 0.19/0.45  % Version  : [Zha98] axioms : Especial.
% 0.19/0.45  % English  : Shows that the 5th axiom of temporal intervals is not dependant
% 0.19/0.45  %            on the first three by building a model of the first three and
% 0.19/0.45  %            the negation of the 5th.
% 0.19/0.45  
% 0.19/0.45  % Refs     : [Zha98] Zhang (1998), Showing the Independence of An Axiom for
% 0.19/0.45  % Source   : [Zha98]
% 0.19/0.45  % Names    : - [Zha98]
% 0.19/0.45  
% 0.19/0.45  % Status   : Satisfiable
% 0.19/0.45  % Rating   : 0.33 v7.1.0, 0.00 v6.4.0, 0.33 v6.2.0, 0.40 v6.0.0, 0.50 v5.5.0, 0.33 v5.4.0, 0.57 v5.2.0, 0.50 v5.0.0, 0.33 v4.1.0, 0.50 v4.0.1, 0.33 v3.7.0, 0.67 v3.5.0, 0.33 v3.4.0, 0.60 v3.3.0, 0.67 v2.6.0, 0.50 v2.5.0, 0.33 v2.4.0
% 0.19/0.45  % Syntax   : Number of formulae    :    4 (   0 unt;   0 def)
% 0.19/0.45  %            Number of atoms       :   18 (   0 equ)
% 0.19/0.45  %            Maximal formula atoms :    7 (   4 avg)
% 0.19/0.45  %            Number of connectives :   15 (   1   ~;   0   |;   9   &)
% 0.19/0.45  %                                         (   0 <=>;   3  =>;   0  <=;   2 <~>)
% 0.19/0.45  %            Maximal formula depth :   11 (   9 avg)
% 0.19/0.45  %            Maximal term depth    :    1 (   1 avg)
% 0.19/0.45  %            Number of predicates  :    1 (   1 usr;   0 prp; 2-2 aty)
% 0.19/0.45  %            Number of functors    :    0 (   0 usr;   0 con; --- aty)
% 0.19/0.45  %            Number of variables   :   18 (  11   !;   7   ?)
% 0.19/0.45  % SPC      : FOF_SAT_RFO_NEQ
% 0.19/0.45  
% 0.19/0.45  % Comments :
% 0.19/0.45  %--------------------------------------------------------------------------
% 0.19/0.45  begin_problem(SomeProblem).
% 0.19/0.45  list_of_descriptions.
% 0.19/0.45  name({* BLAH *}).
% 0.19/0.45  author({* BLAH *}).
% 0.19/0.45  status(unknown).
% 0.19/0.45  description({* BLAH *}).
% 0.19/0.45  end_of_list.
% 0.19/0.45  list_of_symbols.
% 0.19/0.45  functions[(dummy_functor_never_used,0)].
% 0.19/0.45  predicates[(meets__dfg,2)].
% 0.19/0.45  end_of_list.
% 0.19/0.45  
% 0.19/0.45  list_of_formulae(axioms).
% 0.19/0.45  
% 0.19/0.45  formula(
% 0.19/0.45    forall([P,Q,R,S],
% 0.19/0.45     implies(
% 0.19/0.45      and(
% 0.19/0.45       meets__dfg(P,Q),
% 0.19/0.45       and(
% 0.19/0.45        meets__dfg(P,S),
% 0.19/0.45        meets__dfg(R,Q))),
% 0.19/0.45      meets__dfg(R,S))),
% 0.19/0.45  m1).
% 0.19/0.45  
% 0.19/0.45  formula(
% 0.19/0.45    forall([P,Q,R,S],
% 0.19/0.45     implies(
% 0.19/0.45      and(
% 0.19/0.45       meets__dfg(P,Q),
% 0.19/0.45       meets__dfg(R,S)),
% 0.19/0.45      ERROR: (JJ misuse): Not a DFG connective
%------------------------------------------------------------------------------