TSTP Solution File: LCL181+1 by Duper---1.0

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : Duper---1.0
% Problem  : LCL181+1 : TPTP v8.1.2. Released v2.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : duper %s

% Computer : n005.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Thu Aug 31 07:08:53 EDT 2023

% Result   : Theorem 3.32s 3.56s
% Output   : Proof 3.32s
% Verified : 
% SZS Type : -

% Comments : 
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.11/0.12  % Problem    : LCL181+1 : TPTP v8.1.2. Released v2.0.0.
% 0.12/0.13  % Command    : duper %s
% 0.13/0.34  % Computer : n005.cluster.edu
% 0.13/0.34  % Model    : x86_64 x86_64
% 0.13/0.34  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.34  % Memory   : 8042.1875MB
% 0.13/0.34  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.13/0.34  % CPULimit   : 300
% 0.13/0.34  % WCLimit    : 300
% 0.13/0.34  % DateTime   : Fri Aug 25 04:14:53 EDT 2023
% 0.13/0.34  % CPUTime    : 
% 3.32/3.56  SZS status Theorem for theBenchmark.p
% 3.32/3.56  SZS output start Proof for theBenchmark.p
% 3.32/3.56  Clause #0 (by assumption #[]): Eq (Not (Iff (Not p → q) (Not q → p))) True
% 3.32/3.56  Clause #1 (by clausification #[0]): Eq (Iff (Not p → q) (Not q → p)) False
% 3.32/3.56  Clause #2 (by clausification #[1]): Or (Eq (Not p → q) False) (Eq (Not q → p) False)
% 3.32/3.56  Clause #3 (by clausification #[1]): Or (Eq (Not p → q) True) (Eq (Not q → p) True)
% 3.32/3.56  Clause #4 (by clausification #[2]): Or (Eq (Not q → p) False) (Eq (Not p) True)
% 3.32/3.56  Clause #5 (by clausification #[2]): Or (Eq (Not q → p) False) (Eq q False)
% 3.32/3.56  Clause #7 (by clausification #[4]): Or (Eq (Not p) True) (Eq p False)
% 3.32/3.56  Clause #10 (by clausification #[7]): Or (Eq p False) (Eq p False)
% 3.32/3.56  Clause #11 (by eliminate duplicate literals #[10]): Eq p False
% 3.32/3.56  Clause #12 (by clausification #[5]): Or (Eq q False) (Eq (Not q) True)
% 3.32/3.56  Clause #14 (by clausification #[12]): Or (Eq q False) (Eq q False)
% 3.32/3.56  Clause #15 (by eliminate duplicate literals #[14]): Eq q False
% 3.32/3.56  Clause #17 (by clausification #[3]): Or (Eq (Not q → p) True) (Or (Eq (Not p) False) (Eq q True))
% 3.32/3.56  Clause #18 (by clausification #[17]): Or (Eq (Not p) False) (Or (Eq q True) (Or (Eq (Not q) False) (Eq p True)))
% 3.32/3.56  Clause #19 (by clausification #[18]): Or (Eq q True) (Or (Eq (Not q) False) (Or (Eq p True) (Eq p True)))
% 3.32/3.56  Clause #20 (by clausification #[19]): Or (Eq q True) (Or (Eq p True) (Or (Eq p True) (Eq q True)))
% 3.32/3.56  Clause #21 (by eliminate duplicate literals #[20]): Or (Eq q True) (Eq p True)
% 3.32/3.56  Clause #22 (by forward demodulation #[21, 15]): Or (Eq False True) (Eq p True)
% 3.32/3.56  Clause #23 (by clausification #[22]): Eq p True
% 3.32/3.56  Clause #24 (by superposition #[23, 11]): Eq True False
% 3.32/3.56  Clause #25 (by clausification #[24]): False
% 3.32/3.56  SZS output end Proof for theBenchmark.p
%------------------------------------------------------------------------------