TSTP Solution File: LCL117-1 by Otter---3.3

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : Otter---3.3
% Problem  : LCL117-1 : TPTP v8.1.0. Released v1.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : otter-tptp-script %s

% Computer : n014.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Wed Jul 27 13:03:37 EDT 2022

% Result   : Unsatisfiable 1.67s 1.88s
% Output   : Refutation 1.67s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :    4
%            Number of leaves      :    3
% Syntax   : Number of clauses     :    7 (   6 unt;   0 nHn;   3 RR)
%            Number of literals    :    9 (   0 equ;   3 neg)
%            Maximal clause size   :    3 (   1 avg)
%            Maximal term depth    :    5 (   2 avg)
%            Number of predicates  :    2 (   1 usr;   1 prp; 0-1 aty)
%            Number of functors    :    4 (   4 usr;   3 con; 0-2 aty)
%            Number of variables   :   14 (   0 sgn)

% Comments : 
%------------------------------------------------------------------------------
cnf(1,axiom,
    ( ~ is_a_theorem(e_quivalent(A,B))
    | ~ is_a_theorem(A)
    | is_a_theorem(B) ),
    file('LCL117-1.p',unknown),
    [] ).

cnf(2,axiom,
    ~ is_a_theorem(e_quivalent(e_quivalent(e_quivalent(a,b),e_quivalent(a,c)),e_quivalent(c,b))),
    file('LCL117-1.p',unknown),
    [] ).

cnf(3,axiom,
    is_a_theorem(e_quivalent(e_quivalent(A,B),e_quivalent(e_quivalent(C,B),e_quivalent(C,A)))),
    file('LCL117-1.p',unknown),
    [] ).

cnf(4,plain,
    is_a_theorem(e_quivalent(e_quivalent(A,e_quivalent(e_quivalent(B,C),e_quivalent(B,D))),e_quivalent(A,e_quivalent(D,C)))),
    inference(hyper,[status(thm)],[3,1,3]),
    [iquote('hyper,3,1,3')] ).

cnf(7,plain,
    is_a_theorem(e_quivalent(e_quivalent(A,B),e_quivalent(A,B))),
    inference(hyper,[status(thm)],[4,1,3]),
    [iquote('hyper,4,1,3')] ).

cnf(8,plain,
    is_a_theorem(e_quivalent(e_quivalent(e_quivalent(A,B),e_quivalent(A,C)),e_quivalent(C,B))),
    inference(hyper,[status(thm)],[7,1,4]),
    [iquote('hyper,7,1,4')] ).

cnf(9,plain,
    $false,
    inference(binary,[status(thm)],[8,2]),
    [iquote('binary,8.1,2.1')] ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.03/0.12  % Problem  : LCL117-1 : TPTP v8.1.0. Released v1.0.0.
% 0.03/0.12  % Command  : otter-tptp-script %s
% 0.12/0.33  % Computer : n014.cluster.edu
% 0.12/0.33  % Model    : x86_64 x86_64
% 0.12/0.33  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.33  % Memory   : 8042.1875MB
% 0.12/0.33  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.12/0.33  % CPULimit : 300
% 0.12/0.33  % WCLimit  : 300
% 0.12/0.33  % DateTime : Wed Jul 27 09:31:24 EDT 2022
% 0.12/0.33  % CPUTime  : 
% 1.67/1.88  ----- Otter 3.3f, August 2004 -----
% 1.67/1.88  The process was started by sandbox2 on n014.cluster.edu,
% 1.67/1.88  Wed Jul 27 09:31:24 2022
% 1.67/1.88  The command was "./otter".  The process ID is 28965.
% 1.67/1.88  
% 1.67/1.88  set(prolog_style_variables).
% 1.67/1.88  set(auto).
% 1.67/1.88     dependent: set(auto1).
% 1.67/1.88     dependent: set(process_input).
% 1.67/1.88     dependent: clear(print_kept).
% 1.67/1.88     dependent: clear(print_new_demod).
% 1.67/1.88     dependent: clear(print_back_demod).
% 1.67/1.88     dependent: clear(print_back_sub).
% 1.67/1.88     dependent: set(control_memory).
% 1.67/1.88     dependent: assign(max_mem, 12000).
% 1.67/1.88     dependent: assign(pick_given_ratio, 4).
% 1.67/1.88     dependent: assign(stats_level, 1).
% 1.67/1.88     dependent: assign(max_seconds, 10800).
% 1.67/1.88  clear(print_given).
% 1.67/1.88  
% 1.67/1.88  list(usable).
% 1.67/1.88  0 [] -is_a_theorem(e_quivalent(X,Y))| -is_a_theorem(X)|is_a_theorem(Y).
% 1.67/1.88  0 [] is_a_theorem(e_quivalent(e_quivalent(X,Y),e_quivalent(e_quivalent(Z,Y),e_quivalent(Z,X)))).
% 1.67/1.88  0 [] -is_a_theorem(e_quivalent(e_quivalent(e_quivalent(a,b),e_quivalent(a,c)),e_quivalent(c,b))).
% 1.67/1.88  end_of_list.
% 1.67/1.88  
% 1.67/1.88  SCAN INPUT: prop=0, horn=1, equality=0, symmetry=0, max_lits=3.
% 1.67/1.88  
% 1.67/1.88  This is a Horn set without equality.  The strategy will
% 1.67/1.88  be hyperresolution, with satellites in sos and nuclei
% 1.67/1.88  in usable.
% 1.67/1.88  
% 1.67/1.88     dependent: set(hyper_res).
% 1.67/1.88     dependent: clear(order_hyper).
% 1.67/1.88  
% 1.67/1.88  ------------> process usable:
% 1.67/1.88  ** KEPT (pick-wt=8): 1 [] -is_a_theorem(e_quivalent(A,B))| -is_a_theorem(A)|is_a_theorem(B).
% 1.67/1.88  ** KEPT (pick-wt=12): 2 [] -is_a_theorem(e_quivalent(e_quivalent(e_quivalent(a,b),e_quivalent(a,c)),e_quivalent(c,b))).
% 1.67/1.88  
% 1.67/1.88  ------------> process sos:
% 1.67/1.88  ** KEPT (pick-wt=12): 3 [] is_a_theorem(e_quivalent(e_quivalent(A,B),e_quivalent(e_quivalent(C,B),e_quivalent(C,A)))).
% 1.67/1.88  
% 1.67/1.88  ======= end of input processing =======
% 1.67/1.88  
% 1.67/1.88  =========== start of search ===========
% 1.67/1.88  
% 1.67/1.88  -------- PROOF -------- 
% 1.67/1.88  
% 1.67/1.88  ----> UNIT CONFLICT at   0.00 sec ----> 9 [binary,8.1,2.1] $F.
% 1.67/1.88  
% 1.67/1.88  Length of proof is 3.  Level of proof is 3.
% 1.67/1.88  
% 1.67/1.88  ---------------- PROOF ----------------
% 1.67/1.88  % SZS status Unsatisfiable
% 1.67/1.88  % SZS output start Refutation
% See solution above
% 1.67/1.88  ------------ end of proof -------------
% 1.67/1.88  
% 1.67/1.88  
% 1.67/1.88  Search stopped by max_proofs option.
% 1.67/1.88  
% 1.67/1.88  
% 1.67/1.88  Search stopped by max_proofs option.
% 1.67/1.88  
% 1.67/1.88  ============ end of search ============
% 1.67/1.88  
% 1.67/1.88  -------------- statistics -------------
% 1.67/1.88  clauses given                  3
% 1.67/1.88  clauses generated              8
% 1.67/1.88  clauses kept                   8
% 1.67/1.88  clauses forward subsumed       3
% 1.67/1.88  clauses back subsumed          0
% 1.67/1.88  Kbytes malloced              976
% 1.67/1.88  
% 1.67/1.88  ----------- times (seconds) -----------
% 1.67/1.88  user CPU time          0.00          (0 hr, 0 min, 0 sec)
% 1.67/1.88  system CPU time        0.00          (0 hr, 0 min, 0 sec)
% 1.67/1.88  wall-clock time        1             (0 hr, 0 min, 1 sec)
% 1.67/1.88  
% 1.67/1.88  That finishes the proof of the theorem.
% 1.67/1.88  
% 1.67/1.88  Process 28965 finished Wed Jul 27 09:31:25 2022
% 1.67/1.88  Otter interrupted
% 1.67/1.88  PROOF FOUND
%------------------------------------------------------------------------------