TSTP Solution File: LCL104-1 by Otter---3.3
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%------------------------------------------------------------------------------
% File : Otter---3.3
% Problem : LCL104-1 : TPTP v8.1.0. Released v1.0.0.
% Transfm : none
% Format : tptp:raw
% Command : otter-tptp-script %s
% Computer : n020.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 300s
% DateTime : Wed Jul 27 13:03:33 EDT 2022
% Result : Unsatisfiable 1.88s 2.06s
% Output : Refutation 1.88s
% Verified :
% SZS Type : Refutation
% Derivation depth : 7
% Number of leaves : 4
% Syntax : Number of clauses : 12 ( 11 unt; 0 nHn; 3 RR)
% Number of literals : 14 ( 0 equ; 3 neg)
% Maximal clause size : 3 ( 1 avg)
% Maximal term depth : 6 ( 2 avg)
% Number of predicates : 2 ( 1 usr; 1 prp; 0-1 aty)
% Number of functors : 5 ( 5 usr; 4 con; 0-2 aty)
% Number of variables : 35 ( 0 sgn)
% Comments :
%------------------------------------------------------------------------------
cnf(1,axiom,
( ~ is_a_theorem(e_quivalent(A,B))
| ~ is_a_theorem(A)
| is_a_theorem(B) ),
file('LCL104-1.p',unknown),
[] ).
cnf(2,axiom,
~ is_a_theorem(e_quivalent(e_quivalent(e_quivalent(a,b),c),e_quivalent(e_quivalent(e,b),e_quivalent(e_quivalent(a,e),c)))),
file('LCL104-1.p',unknown),
[] ).
cnf(3,axiom,
is_a_theorem(e_quivalent(A,e_quivalent(e_quivalent(e_quivalent(e_quivalent(B,C),e_quivalent(B,D)),e_quivalent(C,D)),A))),
file('LCL104-1.p',unknown),
[] ).
cnf(4,axiom,
is_a_theorem(e_quivalent(e_quivalent(e_quivalent(A,B),e_quivalent(e_quivalent(B,A),C)),C)),
file('LCL104-1.p',unknown),
[] ).
cnf(7,plain,
is_a_theorem(e_quivalent(e_quivalent(A,B),e_quivalent(e_quivalent(C,A),e_quivalent(C,B)))),
inference(hyper,[status(thm)],[4,1,3]),
[iquote('hyper,4,1,3')] ).
cnf(8,plain,
is_a_theorem(e_quivalent(e_quivalent(A,e_quivalent(B,C)),e_quivalent(A,e_quivalent(e_quivalent(D,B),e_quivalent(D,C))))),
inference(hyper,[status(thm)],[7,1,7]),
[iquote('hyper,7,1,7')] ).
cnf(11,plain,
is_a_theorem(e_quivalent(e_quivalent(A,e_quivalent(e_quivalent(B,C),e_quivalent(e_quivalent(C,B),D))),e_quivalent(A,D))),
inference(hyper,[status(thm)],[7,1,4]),
[iquote('hyper,7,1,4')] ).
cnf(27,plain,
is_a_theorem(e_quivalent(e_quivalent(e_quivalent(A,B),e_quivalent(A,C)),e_quivalent(B,C))),
inference(hyper,[status(thm)],[11,1,8]),
[iquote('hyper,11,1,8')] ).
cnf(32,plain,
is_a_theorem(e_quivalent(e_quivalent(A,e_quivalent(e_quivalent(B,C),e_quivalent(B,D))),e_quivalent(A,e_quivalent(C,D)))),
inference(hyper,[status(thm)],[27,1,7]),
[iquote('hyper,27,1,7')] ).
cnf(78,plain,
is_a_theorem(e_quivalent(e_quivalent(e_quivalent(e_quivalent(A,B),e_quivalent(A,C)),D),e_quivalent(e_quivalent(B,C),D))),
inference(hyper,[status(thm)],[32,1,3]),
[iquote('hyper,32,1,3')] ).
cnf(139,plain,
is_a_theorem(e_quivalent(e_quivalent(e_quivalent(A,B),C),e_quivalent(e_quivalent(D,B),e_quivalent(e_quivalent(A,D),C)))),
inference(hyper,[status(thm)],[78,1,78]),
[iquote('hyper,78,1,78')] ).
cnf(140,plain,
$false,
inference(binary,[status(thm)],[139,2]),
[iquote('binary,139.1,2.1')] ).
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.11/0.11 % Problem : LCL104-1 : TPTP v8.1.0. Released v1.0.0.
% 0.11/0.12 % Command : otter-tptp-script %s
% 0.12/0.33 % Computer : n020.cluster.edu
% 0.12/0.33 % Model : x86_64 x86_64
% 0.12/0.33 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.33 % Memory : 8042.1875MB
% 0.12/0.33 % OS : Linux 3.10.0-693.el7.x86_64
% 0.12/0.33 % CPULimit : 300
% 0.12/0.33 % WCLimit : 300
% 0.12/0.33 % DateTime : Wed Jul 27 09:27:38 EDT 2022
% 0.12/0.33 % CPUTime :
% 1.88/2.06 ----- Otter 3.3f, August 2004 -----
% 1.88/2.06 The process was started by sandbox on n020.cluster.edu,
% 1.88/2.06 Wed Jul 27 09:27:38 2022
% 1.88/2.06 The command was "./otter". The process ID is 26353.
% 1.88/2.06
% 1.88/2.06 set(prolog_style_variables).
% 1.88/2.06 set(auto).
% 1.88/2.06 dependent: set(auto1).
% 1.88/2.06 dependent: set(process_input).
% 1.88/2.06 dependent: clear(print_kept).
% 1.88/2.06 dependent: clear(print_new_demod).
% 1.88/2.06 dependent: clear(print_back_demod).
% 1.88/2.06 dependent: clear(print_back_sub).
% 1.88/2.06 dependent: set(control_memory).
% 1.88/2.06 dependent: assign(max_mem, 12000).
% 1.88/2.06 dependent: assign(pick_given_ratio, 4).
% 1.88/2.06 dependent: assign(stats_level, 1).
% 1.88/2.06 dependent: assign(max_seconds, 10800).
% 1.88/2.06 clear(print_given).
% 1.88/2.06
% 1.88/2.06 list(usable).
% 1.88/2.06 0 [] -is_a_theorem(e_quivalent(X,Y))| -is_a_theorem(X)|is_a_theorem(Y).
% 1.88/2.06 0 [] is_a_theorem(e_quivalent(X,e_quivalent(e_quivalent(e_quivalent(e_quivalent(Y,Z),e_quivalent(Y,U)),e_quivalent(Z,U)),X))).
% 1.88/2.06 0 [] is_a_theorem(e_quivalent(e_quivalent(e_quivalent(X,Y),e_quivalent(e_quivalent(Y,X),Z)),Z)).
% 1.88/2.06 0 [] -is_a_theorem(e_quivalent(e_quivalent(e_quivalent(a,b),c),e_quivalent(e_quivalent(e,b),e_quivalent(e_quivalent(a,e),c)))).
% 1.88/2.06 end_of_list.
% 1.88/2.06
% 1.88/2.06 SCAN INPUT: prop=0, horn=1, equality=0, symmetry=0, max_lits=3.
% 1.88/2.06
% 1.88/2.06 This is a Horn set without equality. The strategy will
% 1.88/2.06 be hyperresolution, with satellites in sos and nuclei
% 1.88/2.06 in usable.
% 1.88/2.06
% 1.88/2.06 dependent: set(hyper_res).
% 1.88/2.06 dependent: clear(order_hyper).
% 1.88/2.06
% 1.88/2.06 ------------> process usable:
% 1.88/2.06 ** KEPT (pick-wt=8): 1 [] -is_a_theorem(e_quivalent(A,B))| -is_a_theorem(A)|is_a_theorem(B).
% 1.88/2.06 ** KEPT (pick-wt=16): 2 [] -is_a_theorem(e_quivalent(e_quivalent(e_quivalent(a,b),c),e_quivalent(e_quivalent(e,b),e_quivalent(e_quivalent(a,e),c)))).
% 1.88/2.06
% 1.88/2.06 ------------> process sos:
% 1.88/2.06 ** KEPT (pick-wt=16): 3 [] is_a_theorem(e_quivalent(A,e_quivalent(e_quivalent(e_quivalent(e_quivalent(B,C),e_quivalent(B,D)),e_quivalent(C,D)),A))).
% 1.88/2.06 ** KEPT (pick-wt=12): 4 [] is_a_theorem(e_quivalent(e_quivalent(e_quivalent(A,B),e_quivalent(e_quivalent(B,A),C)),C)).
% 1.88/2.06
% 1.88/2.06 ======= end of input processing =======
% 1.88/2.06
% 1.88/2.06 =========== start of search ===========
% 1.88/2.06
% 1.88/2.06 -------- PROOF --------
% 1.88/2.06
% 1.88/2.06 ----> UNIT CONFLICT at 0.00 sec ----> 140 [binary,139.1,2.1] $F.
% 1.88/2.06
% 1.88/2.06 Length of proof is 7. Level of proof is 6.
% 1.88/2.06
% 1.88/2.06 ---------------- PROOF ----------------
% 1.88/2.06 % SZS status Unsatisfiable
% 1.88/2.06 % SZS output start Refutation
% See solution above
% 1.88/2.06 ------------ end of proof -------------
% 1.88/2.06
% 1.88/2.06
% 1.88/2.06 Search stopped by max_proofs option.
% 1.88/2.06
% 1.88/2.06
% 1.88/2.06 Search stopped by max_proofs option.
% 1.88/2.06
% 1.88/2.06 ============ end of search ============
% 1.88/2.06
% 1.88/2.06 -------------- statistics -------------
% 1.88/2.06 clauses given 23
% 1.88/2.06 clauses generated 275
% 1.88/2.06 clauses kept 139
% 1.88/2.06 clauses forward subsumed 140
% 1.88/2.06 clauses back subsumed 0
% 1.88/2.06 Kbytes malloced 976
% 1.88/2.06
% 1.88/2.06 ----------- times (seconds) -----------
% 1.88/2.06 user CPU time 0.00 (0 hr, 0 min, 0 sec)
% 1.88/2.06 system CPU time 0.00 (0 hr, 0 min, 0 sec)
% 1.88/2.06 wall-clock time 2 (0 hr, 0 min, 2 sec)
% 1.88/2.06
% 1.88/2.06 That finishes the proof of the theorem.
% 1.88/2.06
% 1.88/2.06 Process 26353 finished Wed Jul 27 09:27:40 2022
% 1.88/2.06 Otter interrupted
% 1.88/2.06 PROOF FOUND
%------------------------------------------------------------------------------