TSTP Solution File: LAT388+4 by Etableau---0.67
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%------------------------------------------------------------------------------
% File : Etableau---0.67
% Problem : LAT388+4 : TPTP v8.1.0. Released v4.0.0.
% Transfm : none
% Format : tptp:raw
% Command : etableau --auto --tsmdo --quicksat=10000 --tableau=1 --tableau-saturation=1 -s -p --tableau-cores=8 --cpu-limit=%d %s
% Computer : n009.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 600s
% DateTime : Sun Jul 17 04:51:57 EDT 2022
% Result : Theorem 0.13s 0.38s
% Output : CNFRefutation 0.13s
% Verified :
% SZS Type : Refutation
% Derivation depth : 4
% Number of leaves : 2
% Syntax : Number of formulae : 8 ( 3 unt; 0 def)
% Number of atoms : 100 ( 2 equ)
% Maximal formula atoms : 48 ( 12 avg)
% Number of connectives : 134 ( 42 ~; 46 |; 37 &)
% ( 0 <=>; 9 =>; 0 <=; 0 <~>)
% Maximal formula depth : 19 ( 9 avg)
% Maximal term depth : 2 ( 1 avg)
% Number of predicates : 7 ( 5 usr; 1 prp; 0-3 aty)
% Number of functors : 9 ( 9 usr; 4 con; 0-2 aty)
% Number of variables : 17 ( 1 sgn 14 !; 2 ?)
% Comments :
%------------------------------------------------------------------------------
fof(m__,conjecture,
? [X1] :
( ( aElementOf0(X1,xS)
& ( ( aElementOf0(X1,xS)
& ! [X2] :
( aElementOf0(X2,xT)
=> sdtlseqdt0(X2,X1) ) )
| aUpperBoundOfIn0(X1,xT,xS) )
& ! [X2] :
( ( aElementOf0(X2,xS)
& ! [X3] :
( aElementOf0(X3,xT)
=> sdtlseqdt0(X3,X2) )
& aUpperBoundOfIn0(X2,xT,xS) )
=> sdtlseqdt0(X1,X2) ) )
| aSupremumOfIn0(X1,xT,xS) ),
file('/export/starexec/sandbox/benchmark/theBenchmark.p',m__) ).
fof(m__1330,hypothesis,
( aElementOf0(xp,szDzozmdt0(xf))
& sdtlpdtrp0(xf,xp) = xp
& aFixedPointOf0(xp,xf)
& ! [X1] :
( aElementOf0(X1,xT)
=> sdtlseqdt0(X1,xp) )
& aUpperBoundOfIn0(xp,xT,xS)
& ! [X1] :
( ( ( aElementOf0(X1,xS)
& ! [X2] :
( aElementOf0(X2,xT)
=> sdtlseqdt0(X2,X1) ) )
| aUpperBoundOfIn0(X1,xT,xS) )
=> sdtlseqdt0(xp,X1) )
& aSupremumOfIn0(xp,xT,xS) ),
file('/export/starexec/sandbox/benchmark/theBenchmark.p',m__1330) ).
fof(c_0_2,negated_conjecture,
~ ? [X1] :
( ( aElementOf0(X1,xS)
& ( ( aElementOf0(X1,xS)
& ! [X2] :
( aElementOf0(X2,xT)
=> sdtlseqdt0(X2,X1) ) )
| aUpperBoundOfIn0(X1,xT,xS) )
& ! [X2] :
( ( aElementOf0(X2,xS)
& ! [X3] :
( aElementOf0(X3,xT)
=> sdtlseqdt0(X3,X2) )
& aUpperBoundOfIn0(X2,xT,xS) )
=> sdtlseqdt0(X1,X2) ) )
| aSupremumOfIn0(X1,xT,xS) ),
inference(assume_negation,[status(cth)],[m__]) ).
fof(c_0_3,hypothesis,
! [X90,X91] :
( aElementOf0(xp,szDzozmdt0(xf))
& sdtlpdtrp0(xf,xp) = xp
& aFixedPointOf0(xp,xf)
& ( ~ aElementOf0(X90,xT)
| sdtlseqdt0(X90,xp) )
& aUpperBoundOfIn0(xp,xT,xS)
& ( aElementOf0(esk15_1(X91),xT)
| ~ aElementOf0(X91,xS)
| sdtlseqdt0(xp,X91) )
& ( ~ sdtlseqdt0(esk15_1(X91),X91)
| ~ aElementOf0(X91,xS)
| sdtlseqdt0(xp,X91) )
& ( ~ aUpperBoundOfIn0(X91,xT,xS)
| sdtlseqdt0(xp,X91) )
& aSupremumOfIn0(xp,xT,xS) ),
inference(distribute,[status(thm)],[inference(shift_quantors,[status(thm)],[inference(skolemize,[status(esa)],[inference(variable_rename,[status(thm)],[inference(fof_nnf,[status(thm)],[m__1330])])])])]) ).
fof(c_0_4,negated_conjecture,
! [X93,X96,X97] :
( ( aElementOf0(esk17_1(X93),xS)
| aElementOf0(esk16_1(X93),xT)
| ~ aElementOf0(X93,xS)
| ~ aElementOf0(X93,xS) )
& ( ~ aElementOf0(X96,xT)
| sdtlseqdt0(X96,esk17_1(X93))
| aElementOf0(esk16_1(X93),xT)
| ~ aElementOf0(X93,xS)
| ~ aElementOf0(X93,xS) )
& ( aUpperBoundOfIn0(esk17_1(X93),xT,xS)
| aElementOf0(esk16_1(X93),xT)
| ~ aElementOf0(X93,xS)
| ~ aElementOf0(X93,xS) )
& ( ~ sdtlseqdt0(X93,esk17_1(X93))
| aElementOf0(esk16_1(X93),xT)
| ~ aElementOf0(X93,xS)
| ~ aElementOf0(X93,xS) )
& ( aElementOf0(esk17_1(X93),xS)
| ~ sdtlseqdt0(esk16_1(X93),X93)
| ~ aElementOf0(X93,xS)
| ~ aElementOf0(X93,xS) )
& ( ~ aElementOf0(X96,xT)
| sdtlseqdt0(X96,esk17_1(X93))
| ~ sdtlseqdt0(esk16_1(X93),X93)
| ~ aElementOf0(X93,xS)
| ~ aElementOf0(X93,xS) )
& ( aUpperBoundOfIn0(esk17_1(X93),xT,xS)
| ~ sdtlseqdt0(esk16_1(X93),X93)
| ~ aElementOf0(X93,xS)
| ~ aElementOf0(X93,xS) )
& ( ~ sdtlseqdt0(X93,esk17_1(X93))
| ~ sdtlseqdt0(esk16_1(X93),X93)
| ~ aElementOf0(X93,xS)
| ~ aElementOf0(X93,xS) )
& ( aElementOf0(esk17_1(X93),xS)
| ~ aUpperBoundOfIn0(X93,xT,xS)
| ~ aElementOf0(X93,xS) )
& ( ~ aElementOf0(X96,xT)
| sdtlseqdt0(X96,esk17_1(X93))
| ~ aUpperBoundOfIn0(X93,xT,xS)
| ~ aElementOf0(X93,xS) )
& ( aUpperBoundOfIn0(esk17_1(X93),xT,xS)
| ~ aUpperBoundOfIn0(X93,xT,xS)
| ~ aElementOf0(X93,xS) )
& ( ~ sdtlseqdt0(X93,esk17_1(X93))
| ~ aUpperBoundOfIn0(X93,xT,xS)
| ~ aElementOf0(X93,xS) )
& ~ aSupremumOfIn0(X97,xT,xS) ),
inference(distribute,[status(thm)],[inference(shift_quantors,[status(thm)],[inference(skolemize,[status(esa)],[inference(variable_rename,[status(thm)],[inference(shift_quantors,[status(thm)],[inference(fof_nnf,[status(thm)],[c_0_2])])])])])]) ).
cnf(c_0_5,hypothesis,
aSupremumOfIn0(xp,xT,xS),
inference(split_conjunct,[status(thm)],[c_0_3]) ).
cnf(c_0_6,negated_conjecture,
~ aSupremumOfIn0(X1,xT,xS),
inference(split_conjunct,[status(thm)],[c_0_4]) ).
cnf(c_0_7,hypothesis,
$false,
inference(sr,[status(thm)],[c_0_5,c_0_6]),
[proof] ).
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.12/0.12 % Problem : LAT388+4 : TPTP v8.1.0. Released v4.0.0.
% 0.12/0.13 % Command : etableau --auto --tsmdo --quicksat=10000 --tableau=1 --tableau-saturation=1 -s -p --tableau-cores=8 --cpu-limit=%d %s
% 0.13/0.34 % Computer : n009.cluster.edu
% 0.13/0.34 % Model : x86_64 x86_64
% 0.13/0.34 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.34 % Memory : 8042.1875MB
% 0.13/0.34 % OS : Linux 3.10.0-693.el7.x86_64
% 0.13/0.34 % CPULimit : 300
% 0.13/0.34 % WCLimit : 600
% 0.13/0.34 % DateTime : Wed Jun 29 11:25:52 EDT 2022
% 0.13/0.34 % CPUTime :
% 0.13/0.38 # No SInE strategy applied
% 0.13/0.38 # Auto-Mode selected heuristic G_E___208_C18C___F1_SE_CS_SP_PS_S5PRR_RG_S04AN
% 0.13/0.38 # and selection function SelectComplexExceptUniqMaxHorn.
% 0.13/0.38 #
% 0.13/0.38 # Presaturation interreduction done
% 0.13/0.38
% 0.13/0.38 # Proof found!
% 0.13/0.38 # SZS status Theorem
% 0.13/0.38 # SZS output start CNFRefutation
% See solution above
% 0.13/0.38 # Training examples: 0 positive, 0 negative
%------------------------------------------------------------------------------