TSTP Solution File: LAT388+4 by Duper---1.0
View Problem
- Process Solution
%------------------------------------------------------------------------------
% File : Duper---1.0
% Problem : LAT388+4 : TPTP v8.1.2. Released v4.0.0.
% Transfm : none
% Format : tptp:raw
% Command : duper %s
% Computer : n008.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 300s
% DateTime : Thu Aug 31 06:08:20 EDT 2023
% Result : Theorem 4.06s 4.29s
% Output : Proof 4.06s
% Verified :
% SZS Type : -
% Comments :
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.12 % Problem : LAT388+4 : TPTP v8.1.2. Released v4.0.0.
% 0.00/0.13 % Command : duper %s
% 0.13/0.35 % Computer : n008.cluster.edu
% 0.13/0.35 % Model : x86_64 x86_64
% 0.13/0.35 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.35 % Memory : 8042.1875MB
% 0.13/0.35 % OS : Linux 3.10.0-693.el7.x86_64
% 0.13/0.35 % CPULimit : 300
% 0.13/0.35 % WCLimit : 300
% 0.13/0.35 % DateTime : Thu Aug 24 06:32:17 EDT 2023
% 0.13/0.35 % CPUTime :
% 4.06/4.29 SZS status Theorem for theBenchmark.p
% 4.06/4.29 SZS output start Proof for theBenchmark.p
% 4.06/4.29 Clause #29 (by assumption #[]): Eq
% 4.06/4.29 (And
% 4.06/4.29 (And
% 4.06/4.29 (And
% 4.06/4.29 (And (And (And (aElementOf0 xp (szDzozmdt0 xf)) (Eq (sdtlpdtrp0 xf xp) xp)) (aFixedPointOf0 xp xf))
% 4.06/4.29 (∀ (W0 : Iota), aElementOf0 W0 xT → sdtlseqdt0 W0 xp))
% 4.06/4.29 (aUpperBoundOfIn0 xp xT xS))
% 4.06/4.29 (∀ (W0 : Iota),
% 4.06/4.29 Or (And (aElementOf0 W0 xS) (∀ (W1 : Iota), aElementOf0 W1 xT → sdtlseqdt0 W1 W0)) (aUpperBoundOfIn0 W0 xT xS) →
% 4.06/4.29 sdtlseqdt0 xp W0))
% 4.06/4.29 (aSupremumOfIn0 xp xT xS))
% 4.06/4.29 True
% 4.06/4.29 Clause #30 (by assumption #[]): Eq
% 4.06/4.29 (Not
% 4.06/4.29 (Exists fun W0 =>
% 4.06/4.29 Or
% 4.06/4.29 (And
% 4.06/4.29 (And (aElementOf0 W0 xS)
% 4.06/4.29 (Or (And (aElementOf0 W0 xS) (∀ (W1 : Iota), aElementOf0 W1 xT → sdtlseqdt0 W1 W0))
% 4.06/4.29 (aUpperBoundOfIn0 W0 xT xS)))
% 4.06/4.29 (∀ (W1 : Iota),
% 4.06/4.29 And (And (aElementOf0 W1 xS) (∀ (W2 : Iota), aElementOf0 W2 xT → sdtlseqdt0 W2 W1))
% 4.06/4.29 (aUpperBoundOfIn0 W1 xT xS) →
% 4.06/4.29 sdtlseqdt0 W0 W1))
% 4.06/4.29 (aSupremumOfIn0 W0 xT xS)))
% 4.06/4.29 True
% 4.06/4.29 Clause #343 (by clausification #[29]): Eq (aSupremumOfIn0 xp xT xS) True
% 4.06/4.29 Clause #354 (by clausification #[30]): Eq
% 4.06/4.29 (Exists fun W0 =>
% 4.06/4.29 Or
% 4.06/4.29 (And
% 4.06/4.29 (And (aElementOf0 W0 xS)
% 4.06/4.29 (Or (And (aElementOf0 W0 xS) (∀ (W1 : Iota), aElementOf0 W1 xT → sdtlseqdt0 W1 W0))
% 4.06/4.29 (aUpperBoundOfIn0 W0 xT xS)))
% 4.06/4.29 (∀ (W1 : Iota),
% 4.06/4.29 And (And (aElementOf0 W1 xS) (∀ (W2 : Iota), aElementOf0 W2 xT → sdtlseqdt0 W2 W1))
% 4.06/4.29 (aUpperBoundOfIn0 W1 xT xS) →
% 4.06/4.29 sdtlseqdt0 W0 W1))
% 4.06/4.29 (aSupremumOfIn0 W0 xT xS))
% 4.06/4.29 False
% 4.06/4.29 Clause #355 (by clausification #[354]): ∀ (a : Iota),
% 4.06/4.29 Eq
% 4.06/4.29 (Or
% 4.06/4.29 (And
% 4.06/4.29 (And (aElementOf0 a xS)
% 4.06/4.29 (Or (And (aElementOf0 a xS) (∀ (W1 : Iota), aElementOf0 W1 xT → sdtlseqdt0 W1 a)) (aUpperBoundOfIn0 a xT xS)))
% 4.06/4.29 (∀ (W1 : Iota),
% 4.06/4.29 And (And (aElementOf0 W1 xS) (∀ (W2 : Iota), aElementOf0 W2 xT → sdtlseqdt0 W2 W1))
% 4.06/4.29 (aUpperBoundOfIn0 W1 xT xS) →
% 4.06/4.29 sdtlseqdt0 a W1))
% 4.06/4.29 (aSupremumOfIn0 a xT xS))
% 4.06/4.29 False
% 4.06/4.29 Clause #356 (by clausification #[355]): ∀ (a : Iota), Eq (aSupremumOfIn0 a xT xS) False
% 4.06/4.29 Clause #358 (by superposition #[356, 343]): Eq False True
% 4.06/4.29 Clause #359 (by clausification #[358]): False
% 4.06/4.29 SZS output end Proof for theBenchmark.p
%------------------------------------------------------------------------------