TSTP Solution File: LAT388+4 by Duper---1.0

View Problem - Process Solution

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% File     : Duper---1.0
% Problem  : LAT388+4 : TPTP v8.1.2. Released v4.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : duper %s

% Computer : n008.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Thu Aug 31 06:08:20 EDT 2023

% Result   : Theorem 4.06s 4.29s
% Output   : Proof 4.06s
% Verified : 
% SZS Type : -

% Comments : 
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.12  % Problem    : LAT388+4 : TPTP v8.1.2. Released v4.0.0.
% 0.00/0.13  % Command    : duper %s
% 0.13/0.35  % Computer : n008.cluster.edu
% 0.13/0.35  % Model    : x86_64 x86_64
% 0.13/0.35  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.35  % Memory   : 8042.1875MB
% 0.13/0.35  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.13/0.35  % CPULimit   : 300
% 0.13/0.35  % WCLimit    : 300
% 0.13/0.35  % DateTime   : Thu Aug 24 06:32:17 EDT 2023
% 0.13/0.35  % CPUTime    : 
% 4.06/4.29  SZS status Theorem for theBenchmark.p
% 4.06/4.29  SZS output start Proof for theBenchmark.p
% 4.06/4.29  Clause #29 (by assumption #[]): Eq
% 4.06/4.29    (And
% 4.06/4.29      (And
% 4.06/4.29        (And
% 4.06/4.29          (And (And (And (aElementOf0 xp (szDzozmdt0 xf)) (Eq (sdtlpdtrp0 xf xp) xp)) (aFixedPointOf0 xp xf))
% 4.06/4.29            (∀ (W0 : Iota), aElementOf0 W0 xT → sdtlseqdt0 W0 xp))
% 4.06/4.29          (aUpperBoundOfIn0 xp xT xS))
% 4.06/4.29        (∀ (W0 : Iota),
% 4.06/4.29          Or (And (aElementOf0 W0 xS) (∀ (W1 : Iota), aElementOf0 W1 xT → sdtlseqdt0 W1 W0)) (aUpperBoundOfIn0 W0 xT xS) →
% 4.06/4.29            sdtlseqdt0 xp W0))
% 4.06/4.29      (aSupremumOfIn0 xp xT xS))
% 4.06/4.29    True
% 4.06/4.29  Clause #30 (by assumption #[]): Eq
% 4.06/4.29    (Not
% 4.06/4.29      (Exists fun W0 =>
% 4.06/4.29        Or
% 4.06/4.29          (And
% 4.06/4.29            (And (aElementOf0 W0 xS)
% 4.06/4.29              (Or (And (aElementOf0 W0 xS) (∀ (W1 : Iota), aElementOf0 W1 xT → sdtlseqdt0 W1 W0))
% 4.06/4.29                (aUpperBoundOfIn0 W0 xT xS)))
% 4.06/4.29            (∀ (W1 : Iota),
% 4.06/4.29              And (And (aElementOf0 W1 xS) (∀ (W2 : Iota), aElementOf0 W2 xT → sdtlseqdt0 W2 W1))
% 4.06/4.29                  (aUpperBoundOfIn0 W1 xT xS) →
% 4.06/4.29                sdtlseqdt0 W0 W1))
% 4.06/4.29          (aSupremumOfIn0 W0 xT xS)))
% 4.06/4.29    True
% 4.06/4.29  Clause #343 (by clausification #[29]): Eq (aSupremumOfIn0 xp xT xS) True
% 4.06/4.29  Clause #354 (by clausification #[30]): Eq
% 4.06/4.29    (Exists fun W0 =>
% 4.06/4.29      Or
% 4.06/4.29        (And
% 4.06/4.29          (And (aElementOf0 W0 xS)
% 4.06/4.29            (Or (And (aElementOf0 W0 xS) (∀ (W1 : Iota), aElementOf0 W1 xT → sdtlseqdt0 W1 W0))
% 4.06/4.29              (aUpperBoundOfIn0 W0 xT xS)))
% 4.06/4.29          (∀ (W1 : Iota),
% 4.06/4.29            And (And (aElementOf0 W1 xS) (∀ (W2 : Iota), aElementOf0 W2 xT → sdtlseqdt0 W2 W1))
% 4.06/4.29                (aUpperBoundOfIn0 W1 xT xS) →
% 4.06/4.29              sdtlseqdt0 W0 W1))
% 4.06/4.29        (aSupremumOfIn0 W0 xT xS))
% 4.06/4.29    False
% 4.06/4.29  Clause #355 (by clausification #[354]): ∀ (a : Iota),
% 4.06/4.29    Eq
% 4.06/4.29      (Or
% 4.06/4.29        (And
% 4.06/4.29          (And (aElementOf0 a xS)
% 4.06/4.29            (Or (And (aElementOf0 a xS) (∀ (W1 : Iota), aElementOf0 W1 xT → sdtlseqdt0 W1 a)) (aUpperBoundOfIn0 a xT xS)))
% 4.06/4.29          (∀ (W1 : Iota),
% 4.06/4.29            And (And (aElementOf0 W1 xS) (∀ (W2 : Iota), aElementOf0 W2 xT → sdtlseqdt0 W2 W1))
% 4.06/4.29                (aUpperBoundOfIn0 W1 xT xS) →
% 4.06/4.29              sdtlseqdt0 a W1))
% 4.06/4.29        (aSupremumOfIn0 a xT xS))
% 4.06/4.29      False
% 4.06/4.29  Clause #356 (by clausification #[355]): ∀ (a : Iota), Eq (aSupremumOfIn0 a xT xS) False
% 4.06/4.29  Clause #358 (by superposition #[356, 343]): Eq False True
% 4.06/4.29  Clause #359 (by clausification #[358]): False
% 4.06/4.29  SZS output end Proof for theBenchmark.p
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