TSTP Solution File: LAT387+1 by DarwinFM---1.4.5
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%------------------------------------------------------------------------------
% File : DarwinFM---1.4.5
% Problem : LAT387+1 : TPTP v8.1.0. Released v4.0.0.
% Transfm : none
% Format : tptp:raw
% Command : darwin -fd true -ppp true -pl 0 -to %d -pmtptp true %s
% Computer : n016.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 0s
% DateTime : Sun Jul 17 04:18:58 EDT 2022
% Result : CounterSatisfiable 0.19s 0.40s
% Output : FiniteModel 0.19s
% Verified :
% SZS Type : FiniteModel
% Domain size : 2
% Comments :
%------------------------------------------------------------------------------
fof(interpretation_domain,fi_domain,
! [X] :
( X = e1
| X = e2 ) ).
fof(interpretation_domain_distinct,fi_domain,
e1 != e2 ).
fof(interpretation_terms,fi_functors,
( ! [X0] : cS1142(X0) = e1
& ! [X0,X1,X2] : cS1241(X0,X1,X2) = e1
& ! [X0] : esk10_1(X0) = e1
& ! [X0] : esk11_1(X0) = e1
& ! [X0] : esk1_1(X0) = e1
& ! [X0,X1] : esk2_2(X0,X1) = e1
& ! [X0,X1,X2] : esk3_3(X0,X1,X2) = e1
& ! [X0,X1,X2] : esk4_3(X0,X1,X2) = e1
& ! [X0,X1,X2] : esk5_3(X0,X1,X2) = e1
& ! [X0,X1,X2] : esk6_3(X0,X1,X2) = e1
& ! [X0,X1] : esk7_2(X0,X1) = e1
& ! [X0,X1] : esk8_2(X0,X1) = e1
& ! [X0] : esk9_1(X0) = e1
& ! [X0,X1] : sdtlpdtrp0(X0,X1) = e1
& ! [X0,X1] :
( szDzozmdt0(X0) = X1
<=> ( ( X1 = e1
& X0 != e1 )
| ( X0 = e1
& X1 = e2 ) ) )
& ! [X0,X1] :
( szRzazndt0(X0) = X1
<=> ( ( X1 = e1
& X0 != e1 )
| ( X0 = e1
& X1 = e2 ) ) )
& xP = e1
& xS = e1
& xT = e1
& xU = e2
& xf = e1
& xp = e1 ) ).
fof(interpretation_atoms,fi_predicates,
( ! [X0] :
( aCompleteLattice0(X0)
<=> X0 = e2 )
& ! [X0] :
( aElement0(X0)
<=> X0 = e1 )
& ! [X0,X1] :
( aElementOf0(X0,X1)
<=> ( X0 = e1
& X1 = e2 ) )
& ! [X0,X1] :
( aFixedPointOf0(X0,X1)
<=> ( X0 = e1
& X1 = e1 ) )
& ! [X0] :
( aFunction0(X0)
<=> X0 = e1 )
& ! [X0,X1,X2] :
( aInfimumOfIn0(X0,X1,X2)
<=> ( ( X0 = e1
& X1 = e2
& X2 = e2 )
| ( X0 = e1
& X1 = e1
& X2 = e2 ) ) )
& ! [X0,X1,X2] :
( aLowerBoundOfIn0(X0,X1,X2)
<=> ( ( X0 = e1
& X1 = e2
& X2 = e2 )
| ( X0 = e1
& X1 = e1
& X2 = e2 ) ) )
& ! [X0] :
( aSet0(X0)
<=> X0 = e2 )
& ! [X0,X1] :
( aSubsetOf0(X0,X1)
<=> ( ( X0 = e2
& X1 = e2 )
| ( X0 = e1
& X1 = e1 ) ) )
& ! [X0,X1,X2] :
( aSupremumOfIn0(X0,X1,X2)
<=> ( X0 = e1
& X1 = e2
& X2 = e2 ) )
& ! [X0,X1,X2] :
( aUpperBoundOfIn0(X0,X1,X2)
<=> ( ( X0 = e1
& X1 = e2
& X2 = e2 )
| ( X0 = e1
& X1 = e1
& X2 = e2 ) ) )
& ! [X0] :
( isEmpty0(X0)
<=> $false )
& ! [X0] :
( isMonotone0(X0)
<=> X0 = e1 )
& ! [X0,X1] :
( isOn0(X0,X1)
<=> ( X0 = e1
& X1 = e2 ) )
& ! [X0,X1] :
( sdtlseqdt0(X0,X1)
<=> ( X0 = e1
& X1 = e1 ) ) ) ).
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.03/0.12 % Problem : LAT387+1 : TPTP v8.1.0. Released v4.0.0.
% 0.03/0.13 % Command : darwin -fd true -ppp true -pl 0 -to %d -pmtptp true %s
% 0.13/0.34 % Computer : n016.cluster.edu
% 0.13/0.34 % Model : x86_64 x86_64
% 0.13/0.34 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.34 % Memory : 8042.1875MB
% 0.13/0.34 % OS : Linux 3.10.0-693.el7.x86_64
% 0.13/0.34 % CPULimit : 300
% 0.13/0.34 % DateTime : Wed Jun 29 21:10:54 EDT 2022
% 0.13/0.34 % CPUTime :
% 0.13/0.34 Defaulting to tptp format.
% 0.19/0.40 SZS status CounterSatisfiable for /export/starexec/sandbox/benchmark/theBenchmark.p
% 0.19/0.40
% 0.19/0.40 MODEL (TPTP):
% 0.19/0.40 SZS output start FiniteModel for /export/starexec/sandbox/benchmark/theBenchmark.p
% See solution above
%------------------------------------------------------------------------------