%------------------------------------------------------------------------------
% File     : Etableau---0.67
% Problem  : LAT035-1 : TPTP v8.1.0. Released v2.4.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : etableau --auto --tsmdo --quicksat=10000 --tableau=1 --tableau-saturation=1 -s -p --tableau-cores=8 --cpu-limit=%d %s

% Computer : n021.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 600s
% DateTime : Sun Jul 17 04:48:36 EDT 2022

% Result   : Unsatisfiable 0.12s 0.37s
% Output   : CNFRefutation 0.12s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :    5
%            Number of leaves      :    5
% Syntax   : Number of clauses     :   14 (  11 unt;   0 nHn;  10 RR)
%            Number of literals    :   17 (  16 equ;   8 neg)
%            Maximal clause size   :    2 (   1 avg)
%            Maximal term depth    :    4 (   2 avg)
%            Number of predicates  :    2 (   0 usr;   1 prp; 0-2 aty)
%            Number of functors    :    8 (   8 usr;   4 con; 0-2 aty)
%            Number of variables   :    8 (   0 sgn)

% Comments : 
%------------------------------------------------------------------------------
cnf(comp_join_hemimorphism,negated_conjecture,
    ( f(k(join(aa,bb))) != join(f(k(aa)),f(k(bb)))
    | f(k(n0)) != n0 ),
    file('/export/starexec/sandbox/benchmark/theBenchmark.p',comp_join_hemimorphism) ).

cnf(k_on_bottom,axiom,
    k(n0) = n1,
    file('/export/starexec/sandbox/benchmark/theBenchmark.p',k_on_bottom) ).

cnf(f_on_top,axiom,
    f(n1) = n0,
    file('/export/starexec/sandbox/benchmark/theBenchmark.p',f_on_top) ).

cnf(f_on_meet,axiom,
    f(meet(X1,X2)) = join(f(X1),f(X2)),
    file('/export/starexec/sandbox/benchmark/theBenchmark.p',f_on_meet) ).

cnf(k_on_join,axiom,
    k(join(X1,X2)) = meet(k(X1),k(X2)),
    file('/export/starexec/sandbox/benchmark/theBenchmark.p',k_on_join) ).

cnf(c_0_5,negated_conjecture,
    ( f(k(join(aa,bb))) != join(f(k(aa)),f(k(bb)))
    | f(k(n0)) != n0 ),
    comp_join_hemimorphism ).

cnf(c_0_6,axiom,
    k(n0) = n1,
    k_on_bottom ).

cnf(c_0_7,negated_conjecture,
    ( join(f(k(aa)),f(k(bb))) != f(k(join(aa,bb)))
    | f(n1) != n0 ),
    inference(rw,[status(thm)],[c_0_5,c_0_6]) ).

cnf(c_0_8,axiom,
    f(n1) = n0,
    f_on_top ).

cnf(c_0_9,negated_conjecture,
    join(f(k(aa)),f(k(bb))) != f(k(join(aa,bb))),
    inference(cn,[status(thm)],[inference(rw,[status(thm)],[c_0_7,c_0_8])]) ).

cnf(c_0_10,axiom,
    f(meet(X1,X2)) = join(f(X1),f(X2)),
    f_on_meet ).

cnf(c_0_11,negated_conjecture,
    f(meet(k(aa),k(bb))) != f(k(join(aa,bb))),
    inference(rw,[status(thm)],[c_0_9,c_0_10]) ).

cnf(c_0_12,axiom,
    k(join(X1,X2)) = meet(k(X1),k(X2)),
    k_on_join ).

cnf(c_0_13,negated_conjecture,
    $false,
    inference(cn,[status(thm)],[inference(rw,[status(thm)],[c_0_11,c_0_12])]),
    [proof] ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.07/0.12  % Problem  : LAT035-1 : TPTP v8.1.0. Released v2.4.0.
% 0.07/0.13  % Command  : etableau --auto --tsmdo --quicksat=10000 --tableau=1 --tableau-saturation=1 -s -p --tableau-cores=8 --cpu-limit=%d %s
% 0.12/0.34  % Computer : n021.cluster.edu
% 0.12/0.34  % Model    : x86_64 x86_64
% 0.12/0.34  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.34  % Memory   : 8042.1875MB
% 0.12/0.34  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.12/0.34  % CPULimit : 300
% 0.12/0.34  % WCLimit  : 600
% 0.12/0.34  % DateTime : Wed Jun 29 19:56:12 EDT 2022
% 0.12/0.34  % CPUTime  : 
% 0.12/0.37  # No SInE strategy applied
% 0.12/0.37  # Auto-Mode selected heuristic G_E___208_C18_F1_SE_CS_SP_PS_S5PRR_RG_S04AN
% 0.12/0.37  # and selection function SelectComplexExceptUniqMaxHorn.
% 0.12/0.37  #
% 0.12/0.37  # Presaturation interreduction done
% 0.12/0.37  
% 0.12/0.37  # Proof found!
% 0.12/0.37  # SZS status Unsatisfiable
% 0.12/0.37  # SZS output start CNFRefutation
% See solution above
% 0.12/0.37  # Training examples: 0 positive, 0 negative
%------------------------------------------------------------------------------