TSTP Solution File: KRS254+1 by SPASS---3.9

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : SPASS---3.9
% Problem  : KRS254+1 : TPTP v8.1.0. Bugfixed v5.4.0.
% Transfm  : none
% Format   : tptp
% Command  : run_spass %d %s

% Computer : n029.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 600s
% DateTime : Sun Jul 17 03:30:59 EDT 2022

% Result   : Theorem 0.49s 0.68s
% Output   : Refutation 0.49s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :    4
%            Number of leaves      :    6
% Syntax   : Number of clauses     :   13 (   5 unt;   4 nHn;  13 RR)
%            Number of literals    :   22 (   0 equ;   8 neg)
%            Maximal clause size   :    3 (   1 avg)
%            Maximal term depth    :    2 (   1 avg)
%            Number of predicates  :    4 (   3 usr;   1 prp; 0-3 aty)
%            Number of functors    :    8 (   8 usr;   6 con; 0-2 aty)
%            Number of variables   :    0 (   0 sgn)

% Comments : 
%------------------------------------------------------------------------------
cnf(9,axiom,
    ~ mighta(unp,thm),
    file('KRS254+1.p',unknown),
    [] ).

cnf(20,axiom,
    ( ~ model(u,v)
    | status__dfg(v,w,unp) ),
    file('KRS254+1.p',unknown),
    [] ).

cnf(21,axiom,
    ( model(skf52(u),u)
    | status__dfg(v,u,unp) ),
    file('KRS254+1.p',unknown),
    [] ).

cnf(32,axiom,
    ( model(skf61(u,v),v)
    | status__dfg(v,u,thm) ),
    file('KRS254+1.p',unknown),
    [] ).

cnf(50,axiom,
    ( ~ model(skf61(u,v),u)
    | status__dfg(w,u,thm) ),
    file('KRS254+1.p',unknown),
    [] ).

cnf(92,axiom,
    ( ~ status__dfg(u,v,w)
    | ~ status__dfg(u,v,x)
    | mighta(x,w) ),
    file('KRS254+1.p',unknown),
    [] ).

cnf(112,plain,
    ( ~ status__dfg(u,v,thm)
    | ~ status__dfg(u,v,unp) ),
    inference(res,[status(thm),theory(equality)],[92,9]),
    [iquote('0:Res:92.2,9.0')] ).

cnf(142,plain,
    ( status__dfg(u,v,unp)
    | status__dfg(v,w,unp) ),
    inference(res,[status(thm),theory(equality)],[21,20]),
    [iquote('0:Res:21.0,20.0')] ).

cnf(152,plain,
    status__dfg(u,u,unp),
    inference(fac,[status(thm)],[142]),
    [iquote('0:Fac:142.0,142.1')] ).

cnf(341,plain,
    ( status__dfg(u,u,thm)
    | status__dfg(v,u,thm) ),
    inference(res,[status(thm),theory(equality)],[32,50]),
    [iquote('0:Res:32.0,50.0')] ).

cnf(342,plain,
    status__dfg(u,u,thm),
    inference(con,[status(thm)],[341]),
    [iquote('0:Con:341.1')] ).

cnf(361,plain,
    ~ status__dfg(u,u,thm),
    inference(res,[status(thm),theory(equality)],[152,112]),
    [iquote('0:Res:152.0,112.1')] ).

cnf(382,plain,
    $false,
    inference(mrr,[status(thm)],[361,342]),
    [iquote('0:MRR:361.0,342.0')] ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.08/0.14  % Problem  : KRS254+1 : TPTP v8.1.0. Bugfixed v5.4.0.
% 0.08/0.15  % Command  : run_spass %d %s
% 0.14/0.37  % Computer : n029.cluster.edu
% 0.14/0.37  % Model    : x86_64 x86_64
% 0.14/0.37  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.14/0.37  % Memory   : 8042.1875MB
% 0.14/0.37  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.14/0.37  % CPULimit : 300
% 0.14/0.37  % WCLimit  : 600
% 0.14/0.37  % DateTime : Tue Jun  7 14:46:05 EDT 2022
% 0.14/0.37  % CPUTime  : 
% 0.49/0.68  
% 0.49/0.68  SPASS V 3.9 
% 0.49/0.68  SPASS beiseite: Proof found.
% 0.49/0.68  % SZS status Theorem
% 0.49/0.68  Problem: /export/starexec/sandbox2/benchmark/theBenchmark.p 
% 0.49/0.68  SPASS derived 260 clauses, backtracked 0 clauses, performed 1 splits and kept 292 clauses.
% 0.49/0.68  SPASS allocated 87719 KBytes.
% 0.49/0.68  SPASS spent	0:00:00.29 on the problem.
% 0.49/0.68  		0:00:00.03 for the input.
% 0.49/0.68  		0:00:00.20 for the FLOTTER CNF translation.
% 0.49/0.68  		0:00:00.00 for inferences.
% 0.49/0.68  		0:00:00.00 for the backtracking.
% 0.49/0.68  		0:00:00.02 for the reduction.
% 0.49/0.68  
% 0.49/0.68  
% 0.49/0.68  Here is a proof with depth 3, length 13 :
% 0.49/0.68  % SZS output start Refutation
% See solution above
% 0.49/0.68  Formulae used in the proof : mighta_unp_thm unp thm mighta
% 0.49/0.68  
%------------------------------------------------------------------------------