TSTP Solution File: KRS127+1 by SOS---2.0

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : SOS---2.0
% Problem  : KRS127+1 : TPTP v8.1.0. Released v3.1.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : sos-script %s

% Computer : n022.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 600s
% DateTime : Sun Jul 17 03:29:50 EDT 2022

% Result   : Unsatisfiable 0.42s 0.61s
% Output   : Refutation 0.42s
% Verified : 
% SZS Type : -

% Comments : 
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.11/0.12  % Problem  : KRS127+1 : TPTP v8.1.0. Released v3.1.0.
% 0.11/0.13  % Command  : sos-script %s
% 0.12/0.34  % Computer : n022.cluster.edu
% 0.12/0.34  % Model    : x86_64 x86_64
% 0.12/0.34  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.34  % Memory   : 8042.1875MB
% 0.12/0.34  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.12/0.34  % CPULimit : 300
% 0.12/0.34  % WCLimit  : 600
% 0.12/0.34  % DateTime : Tue Jun  7 09:05:05 EDT 2022
% 0.12/0.34  % CPUTime  : 
% 0.12/0.36  ----- Otter 3.2, August 2001 -----
% 0.12/0.36  The process was started by sandbox2 on n022.cluster.edu,
% 0.12/0.36  Tue Jun  7 09:05:05 2022
% 0.12/0.36  The command was "./sos".  The process ID is 26720.
% 0.12/0.36  
% 0.12/0.36  set(prolog_style_variables).
% 0.12/0.36  set(auto).
% 0.12/0.36     dependent: set(auto1).
% 0.12/0.36     dependent: set(process_input).
% 0.12/0.36     dependent: clear(print_kept).
% 0.12/0.36     dependent: clear(print_new_demod).
% 0.12/0.36     dependent: clear(print_back_demod).
% 0.12/0.36     dependent: clear(print_back_sub).
% 0.12/0.36     dependent: set(control_memory).
% 0.12/0.36     dependent: assign(max_mem, 12000).
% 0.12/0.36     dependent: assign(pick_given_ratio, 4).
% 0.12/0.36     dependent: assign(stats_level, 1).
% 0.12/0.36     dependent: assign(pick_semantic_ratio, 3).
% 0.12/0.36     dependent: assign(sos_limit, 5000).
% 0.12/0.36     dependent: assign(max_weight, 60).
% 0.12/0.36  clear(print_given).
% 0.12/0.36  
% 0.12/0.36  formula_list(usable).
% 0.12/0.36  
% 0.12/0.36  SCAN INPUT: prop=0, horn=0, equality=1, symmetry=0, max_lits=6.
% 0.12/0.36  
% 0.12/0.36  This ia a non-Horn set with equality.  The strategy will be
% 0.12/0.36  Knuth-Bendix, ordered hyper_res, ur_res, factoring, and
% 0.12/0.36  unit deletion, with positive clauses in sos and nonpositive
% 0.12/0.36  clauses in usable.
% 0.12/0.36  
% 0.12/0.36     dependent: set(knuth_bendix).
% 0.12/0.36     dependent: set(para_from).
% 0.12/0.36     dependent: set(para_into).
% 0.12/0.36     dependent: clear(para_from_right).
% 0.12/0.36     dependent: clear(para_into_right).
% 0.12/0.36     dependent: set(para_from_vars).
% 0.12/0.36     dependent: set(eq_units_both_ways).
% 0.12/0.36     dependent: set(dynamic_demod_all).
% 0.12/0.36     dependent: set(dynamic_demod).
% 0.12/0.36     dependent: set(order_eq).
% 0.12/0.36     dependent: set(back_demod).
% 0.12/0.36     dependent: set(lrpo).
% 0.12/0.36     dependent: set(hyper_res).
% 0.12/0.36     dependent: set(unit_deletion).
% 0.12/0.36     dependent: set(factor).
% 0.12/0.36  
% 0.12/0.36  ------------> process usable:
% 0.12/0.36  13 back subsumes 5.
% 0.12/0.36  
% 0.12/0.36  ------------> process sos:
% 0.12/0.36  31 back subsumes 6.
% 0.12/0.36    Following clause subsumed by 35 during input processing: 0 [copy,35,flip.1] {-} A=A.
% 0.12/0.36  35 back subsumes 27.
% 0.12/0.36  
% 0.12/0.36  ======= end of input processing =======
% 0.12/0.40  
% 0.12/0.40  Model 1 (0.00 seconds, 0 Inserts)
% 0.12/0.40  
% 0.12/0.40  Stopped by limit on number of solutions
% 0.12/0.40  
% 0.12/0.40  
% 0.12/0.40  -------------- Softie stats --------------
% 0.12/0.40  
% 0.12/0.40  UPDATE_STOP: 300
% 0.12/0.40  SFINDER_TIME_LIMIT: 2
% 0.12/0.40  SHORT_CLAUSE_CUTOFF: 4
% 0.12/0.40  number of clauses in intial UL: 27
% 0.12/0.40  number of clauses initially in problem: 32
% 0.12/0.40  percentage of clauses intially in UL: 84
% 0.12/0.40  percentage of distinct symbols occuring in initial UL: 83
% 0.12/0.40  percent of all initial clauses that are short: 100
% 0.12/0.40  absolute distinct symbol count: 18
% 0.12/0.40     distinct predicate count: 11
% 0.12/0.40     distinct function count: 6
% 0.12/0.40     distinct constant count: 1
% 0.12/0.40  
% 0.12/0.40  ---------- no more Softie stats ----------
% 0.12/0.40  
% 0.12/0.40  
% 0.12/0.40  
% 0.12/0.40  Model 2 (0.00 seconds, 0 Inserts)
% 0.12/0.40  
% 0.12/0.40  Stopped by limit on number of solutions
% 0.12/0.40  
% 0.12/0.40  =========== start of search ===========
% 0.42/0.61  
% 0.42/0.61  -------- PROOF -------- 
% 0.42/0.61  % SZS status Theorem
% 0.42/0.61  % SZS output start Refutation
% 0.42/0.61  
% 0.42/0.61  Model 3 [ 1 1 237 ] (0.00 seconds, 523 Inserts)
% 0.42/0.61  
% 0.42/0.61  Stopped by limit on insertions
% 0.42/0.61  
% 0.42/0.61  Model 4 [ 2 1 254 ] (0.00 seconds, 250000 Inserts)
% 0.42/0.61  
% 0.42/0.61  Stopped by limit on insertions
% 0.42/0.61  
% 0.42/0.61  Model 5 [ 2 0 288 ] (0.00 seconds, 250000 Inserts)
% 0.42/0.61  
% 0.42/0.61  Model 6 [ 1 1 256 ] (0.00 seconds, 3454 Inserts)
% 0.42/0.61  
% 0.42/0.61  Model 7 [ 1 1 307 ] (0.00 seconds, 4110 Inserts)
% 0.42/0.61  
% 0.42/0.61  Stopped by limit on insertions
% 0.42/0.61  
% 0.42/0.61  Model 8 [ 2 0 292 ] (0.00 seconds, 250000 Inserts)
% 0.42/0.61  
% 0.42/0.61  -----> EMPTY CLAUSE at   0.22 sec ----> 63 [hyper,50,24,58] {-} $F.
% 0.42/0.61  
% 0.42/0.61  Length of proof is 8.  Level of proof is 3.
% 0.42/0.61  
% 0.42/0.61  ---------------- PROOF ----------------
% 0.42/0.61  % SZS status Theorem
% 0.42/0.61  % SZS output start Refutation
% 0.42/0.61  
% 0.42/0.61  15 [] {+} -cUnsatisfiable(A)|rr(A,$f1(A)).
% 0.42/0.61  16 [] {+} -cUnsatisfiable(A)|cc($f1(A)).
% 0.42/0.61  17 [] {+} -cUnsatisfiable(A)|rr(A,$f2(A)).
% 0.42/0.61  18 [] {+} -cUnsatisfiable(A)|cd($f2(A)).
% 0.42/0.61  19 [] {+} -cUnsatisfiable(A)| -rr(A,B)| -rr(A,C)|B=C.
% 0.42/0.61  23 [] {+} -cc(A)|cdxcomp(A).
% 0.42/0.61  24 [] {+} -cd(A)| -ra_Px1(A,B).
% 0.42/0.61  25 [] {+} -cdxcomp(A)|ra_Px1(A,$f6(A)).
% 0.42/0.61  34 [] {-} cUnsatisfiable(i2003_11_14_17_22_27794).
% 0.42/0.61  36 [hyper,34,18] {+} cd($f2(i2003_11_14_17_22_27794)).
% 0.42/0.61  37 [hyper,34,17] {+} rr(i2003_11_14_17_22_27794,$f2(i2003_11_14_17_22_27794)).
% 0.42/0.61  38 [hyper,34,16] {+} cc($f1(i2003_11_14_17_22_27794)).
% 0.42/0.61  39 [hyper,34,15] {+} rr(i2003_11_14_17_22_27794,$f1(i2003_11_14_17_22_27794)).
% 0.42/0.61  43 [hyper,38,23] {+} cdxcomp($f1(i2003_11_14_17_22_27794)).
% 0.42/0.61  50 [hyper,43,25] {+} ra_Px1($f1(i2003_11_14_17_22_27794),$f6($f1(i2003_11_14_17_22_27794))).
% 0.42/0.61  54,53 [hyper,39,19,34,37] {-} $f2(i2003_11_14_17_22_27794)=$f1(i2003_11_14_17_22_27794).
% 0.42/0.61  58 [back_demod,36,demod,54] {-} cd($f1(i2003_11_14_17_22_27794)).
% 0.42/0.61  63 [hyper,50,24,58] {-} $F.
% 0.42/0.61  
% 0.42/0.61  % SZS output end Refutation
% 0.42/0.61  ------------ end of proof -------------
% 0.42/0.61  
% 0.42/0.61  
% 0.42/0.61  Search stopped by max_proofs option.
% 0.42/0.61  
% 0.42/0.61  
% 0.42/0.61  Search stopped by max_proofs option.
% 0.42/0.61  
% 0.42/0.61  ============ end of search ============
% 0.42/0.61  
% 0.42/0.61  ----------- soft-scott stats ----------
% 0.42/0.61  
% 0.42/0.61  true clauses given           5      (35.7%)
% 0.42/0.61  false clauses given          9
% 0.42/0.61  
% 0.42/0.61        FALSE     TRUE
% 0.42/0.61     7  0         2
% 0.42/0.61     8  0         1
% 0.42/0.61    11  0         8
% 0.42/0.61    12  0         6
% 0.42/0.61    13  0         1
% 0.42/0.61    14  0         1
% 0.42/0.61    18  0         1
% 0.42/0.61  tot:  0         20      (100.0% true)
% 0.42/0.61  
% 0.42/0.61  
% 0.42/0.61  Model 8 [ 2 0 292 ] (0.00 seconds, 250000 Inserts)
% 0.42/0.61  
% 0.42/0.61  That finishes the proof of the theorem.
% 0.42/0.61  
% 0.42/0.61  Process 26720 finished Tue Jun  7 09:05:05 2022
%------------------------------------------------------------------------------