TSTP Solution File: KRS030+1 by Crossbow---0.1
View Problem
- Process Solution
%------------------------------------------------------------------------------
% File : Crossbow---0.1
% Problem : KRS030+1 : TPTP v8.1.0. Released v3.1.0.
% Transfm : none
% Format : tptp:raw
% Command : do_Crossbow---0.1 %s
% Computer : n018.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 600s
% DateTime : Sun Jul 17 02:43:05 EDT 2022
% Result : Satisfiable 5.20s 5.42s
% Output : FiniteModel 5.20s
% Verified :
% SZS Type : -
% Comments :
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.03/0.12 % Problem : KRS030+1 : TPTP v8.1.0. Released v3.1.0.
% 0.03/0.13 % Command : do_Crossbow---0.1 %s
% 0.13/0.33 % Computer : n018.cluster.edu
% 0.13/0.33 % Model : x86_64 x86_64
% 0.13/0.33 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.33 % Memory : 8042.1875MB
% 0.13/0.33 % OS : Linux 3.10.0-693.el7.x86_64
% 0.13/0.33 % CPULimit : 300
% 0.13/0.33 % WCLimit : 600
% 0.13/0.33 % DateTime : Tue Jun 7 12:17:51 EDT 2022
% 0.13/0.34 % CPUTime :
% 0.13/0.34 /export/starexec/sandbox/solver/bin
% 0.13/0.34 crossbow.opt
% 0.13/0.34 do_Crossbow---0.1
% 0.13/0.34 eprover
% 0.13/0.34 runsolver
% 0.13/0.34 starexec_run_Crossbow---0.1
% 5.20/5.42 % SZS status Satisfiable for theBenchmark.p
% 5.20/5.42 % SZS output start FiniteModel for theBenchmark.p
% 5.20/5.42 % domain size: 2
% 5.20/5.42 fof(interp, fi_domain, ![X] : (X = 0 | X = 1)).
% 5.20/5.42 fof(interp, fi_predicates, cSatisfiable(0) & cSatisfiable(1)).
% 5.20/5.42 fof(interp, fi_predicates, ~cowlNothing(0) & ~cowlNothing(1)).
% 5.20/5.42 fof(interp, fi_predicates, cp(0) & ~cp(1)).
% 5.20/5.42 fof(interp, fi_functors, esk1_1(0) = 1 & esk1_1(1) = 1).
% 5.20/5.42 fof(interp, fi_functors, esk2_1(0) = 0 & esk2_1(1) = 0).
% 5.20/5.42 fof(interp, fi_functors, i2003_11_14_17_15_26245 = 0).
% 5.20/5.42 fof(interp, fi_predicates, rf(0, 0) & ~rf(0, 1) & rf(1, 0) & ~rf(1, 1)).
% 5.20/5.42 fof(interp, fi_predicates, ~rf1(0, 0) & rf1(0, 1) & ~rf1(1, 0) & rf1(1, 1)).
% 5.20/5.42 fof(interp, fi_predicates, rinvF(0, 0) & rinvF(0, 1) & ~rinvF(1, 0) &
% 5.20/5.42 ~rinvF(1, 1)).
% 5.20/5.42 fof(interp, fi_predicates, ~rinvF1(0, 0) & ~rinvF1(0, 1) & rinvF1(1, 0) &
% 5.20/5.42 rinvF1(1, 1)).
% 5.20/5.42 fof(interp, fi_predicates, ~rinvS(0, 0) & ~rinvS(0, 1) & ~rinvS(1, 0) &
% 5.20/5.42 ~rinvS(1, 1)).
% 5.20/5.42 fof(interp, fi_predicates, ~rs(0, 0) & ~rs(0, 1) & ~rs(1, 0) & ~rs(1, 1)).
% 5.20/5.42 fof(interp, fi_predicates, ~xsd_integer(0) & ~xsd_integer(1)).
% 5.20/5.42 fof(interp, fi_predicates, xsd_string(0) & xsd_string(1)).
% 5.20/5.42 % SZS output end FiniteModel for theBenchmark.p
% 5.20/5.42 % 0 lemma(s) from E
% 5.20/5.42 % 11 pred(s)
% 5.20/5.42 % 3 func(s)
% 5.20/5.42 % 4 sort(s)
% 5.20/5.42 % 20 clause(s)
% 5.20/5.42 % Instantiating 1 (5053 ms)
% 5.20/5.42 % Solving (5053 ms)
% 5.20/5.42 % Instantiating 2 (5053 ms)
% 5.20/5.42 % Solving (5053 ms)
% 5.20/5.42 %
% 5.20/5.42 % 1 model found (5053 ms)
%------------------------------------------------------------------------------