TSTP Solution File: KLE180+1 by Crossbow---0.1
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% File : Crossbow---0.1
% Problem : KLE180+1 : TPTP v8.1.0. Released v6.4.0.
% Transfm : none
% Format : tptp:raw
% Command : do_Crossbow---0.1 %s
% Computer : n021.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 600s
% DateTime : Sun Jul 17 01:38:35 EDT 2022
% Result : Satisfiable 5.29s 5.51s
% Output : FiniteModel 5.29s
% Verified :
% SZS Type : -
% Comments :
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.05/0.14 % Problem : KLE180+1 : TPTP v8.1.0. Released v6.4.0.
% 0.05/0.15 % Command : do_Crossbow---0.1 %s
% 0.15/0.37 % Computer : n021.cluster.edu
% 0.15/0.37 % Model : x86_64 x86_64
% 0.15/0.37 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.15/0.37 % Memory : 8042.1875MB
% 0.15/0.37 % OS : Linux 3.10.0-693.el7.x86_64
% 0.15/0.37 % CPULimit : 300
% 0.15/0.37 % WCLimit : 600
% 0.15/0.37 % DateTime : Thu Jun 16 12:03:45 EDT 2022
% 0.15/0.37 % CPUTime :
% 0.15/0.38 /export/starexec/sandbox/solver/bin
% 0.15/0.38 crossbow.opt
% 0.15/0.38 do_Crossbow---0.1
% 0.15/0.38 eprover
% 0.15/0.38 runsolver
% 0.15/0.38 starexec_run_Crossbow---0.1
% 5.29/5.51 % SZS status Satisfiable for theBenchmark.p
% 5.29/5.51 % SZS output start FiniteModel for theBenchmark.p
% 5.29/5.51 % domain size: 1
% 5.29/5.51 fof(interp, fi_domain, ![X] : X = 0).
% 5.29/5.51 fof(interp, fi_functors, addition(0, 0) = 0).
% 5.29/5.51 fof(interp, fi_functors, antidomain(0) = 0).
% 5.29/5.51 fof(interp, fi_functors, coantidomain(0) = 0).
% 5.29/5.51 fof(interp, fi_functors, divergence(0) = 0).
% 5.29/5.51 fof(interp, fi_predicates, leq(0, 0)).
% 5.29/5.51 fof(interp, fi_functors, multiplication(0, 0) = 0).
% 5.29/5.51 fof(interp, fi_functors, omega(0) = 0).
% 5.29/5.51 fof(interp, fi_functors, one = 0).
% 5.29/5.51 fof(interp, fi_functors, star(0) = 0).
% 5.29/5.51 fof(interp, fi_functors, zero = 0).
% 5.29/5.51 % SZS output end FiniteModel for theBenchmark.p
% 5.29/5.51 % 20 lemma(s) from E
% 5.29/5.51 % cnf(cl, axiom, zero = omega(zero)).
% 5.29/5.51 % cnf(cl, axiom, coantidomain(A) = coantidomain(coantidomain(coantidomain(A)))).
% 5.29/5.51 % cnf(cl, axiom, leq(one, one)).
% 5.29/5.51 % cnf(cl, axiom, zero = coantidomain(one)).
% 5.29/5.51 % cnf(cl, axiom, zero = antidomain(one)).
% 5.29/5.51 % cnf(cl, axiom, one = coantidomain(zero)).
% 5.29/5.51 % cnf(cl, axiom, one = antidomain(zero)).
% 5.29/5.51 % cnf(cl, axiom, addition(A, B) = addition(A, addition(A, B))).
% 5.29/5.51 % cnf(cl, axiom, addition(A, B) = addition(A, addition(A, B))).
% 5.29/5.51 % cnf(cl, axiom, multiplication(A, omega(omega(A))) = omega(omega(A))).
% 5.29/5.51 % cnf(cl, axiom, addition(one, star(one)) = star(one)).
% 5.29/5.51 % cnf(cl, axiom, leq(star(one), star(one))).
% 5.29/5.51 % cnf(cl, axiom, multiplication(coantidomain(A), coantidomain(A)) = coantidomain(A)).
% 5.29/5.51 % cnf(cl, axiom, A = multiplication(A, coantidomain(coantidomain(A)))).
% 5.29/5.51 % cnf(cl, axiom, multiplication(antidomain(A), antidomain(A)) = antidomain(A)).
% 5.29/5.51 % cnf(cl, axiom, A = multiplication(antidomain(antidomain(A)), A)).
% 5.29/5.51 % cnf(cl, axiom, multiplication(A, omega(omega(omega(A)))) = omega(omega(omega(A)))).
% 5.29/5.51 % cnf(cl, axiom, leq(zero, A)).
% 5.29/5.51 % cnf(cl, axiom, one = star(zero)).
% 5.29/5.51 % cnf(cl, axiom, addition(one, antidomain(A)) = one).
% 5.29/5.51 % 52 pred(s)
% 5.29/5.51 % 10 func(s)
% 5.29/5.51 % 1 sort(s)
% 5.29/5.51 % 98 clause(s)
% 5.29/5.51 % Instantiating 1 (5095 ms)
% 5.29/5.51 % Solving (5095 ms)
% 5.29/5.51 %
% 5.29/5.51 % 1 model found (5095 ms)
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