TSTP Solution File: KLE136+1 by Crossbow---0.1
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%------------------------------------------------------------------------------
% File : Crossbow---0.1
% Problem : KLE136+1 : TPTP v8.1.0. Released v4.0.0.
% Transfm : none
% Format : tptp:raw
% Command : do_Crossbow---0.1 %s
% Computer : n021.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 600s
% DateTime : Sun Jul 17 01:38:20 EDT 2022
% Result : CounterSatisfiable 5.41s 5.61s
% Output : FiniteModel 5.41s
% Verified :
% SZS Type : -
% Comments :
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.07/0.12 % Problem : KLE136+1 : TPTP v8.1.0. Released v4.0.0.
% 0.07/0.13 % Command : do_Crossbow---0.1 %s
% 0.12/0.34 % Computer : n021.cluster.edu
% 0.12/0.34 % Model : x86_64 x86_64
% 0.12/0.34 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.34 % Memory : 8042.1875MB
% 0.12/0.34 % OS : Linux 3.10.0-693.el7.x86_64
% 0.12/0.34 % CPULimit : 300
% 0.12/0.34 % WCLimit : 600
% 0.12/0.34 % DateTime : Thu Jun 16 13:32:15 EDT 2022
% 0.12/0.35 % CPUTime :
% 0.12/0.35 /export/starexec/sandbox2/solver/bin
% 0.12/0.35 crossbow.opt
% 0.12/0.35 do_Crossbow---0.1
% 0.12/0.35 eprover
% 0.12/0.35 runsolver
% 0.12/0.35 starexec_run_Crossbow---0.1
% 5.41/5.61 % SZS status CounterSatisfiable for theBenchmark.p
% 5.41/5.61 % SZS output start FiniteModel for theBenchmark.p
% 5.41/5.61 % domain size: 4
% 5.41/5.61 fof(interp, fi_domain, ![X] : (X = 0 | X = 1 | X = 2 | X = 3)).
% 5.41/5.61 fof(interp, fi_functors, addition(0, 0) = 0 & addition(0, 1) = 1 &
% 5.41/5.61 addition(0, 2) = 2 &
% 5.41/5.61 addition(0, 3) = 3 &
% 5.41/5.61 addition(1, 0) = 1 &
% 5.41/5.61 addition(1, 1) = 1 &
% 5.41/5.61 addition(1, 2) = 1 &
% 5.41/5.61 addition(1, 3) = 1 &
% 5.41/5.61 addition(2, 0) = 2 &
% 5.41/5.61 addition(2, 1) = 1 &
% 5.41/5.61 addition(2, 2) = 2 &
% 5.41/5.61 addition(2, 3) = 3 &
% 5.41/5.61 addition(3, 0) = 3 &
% 5.41/5.61 addition(3, 1) = 1 &
% 5.41/5.61 addition(3, 2) = 3 &
% 5.41/5.61 addition(3, 3) = 3).
% 5.41/5.61 fof(interp, fi_functors, antidomain(0) = 1 & antidomain(1) = 0 &
% 5.41/5.61 antidomain(2) = 0 &
% 5.41/5.61 antidomain(3) = 0).
% 5.41/5.61 fof(interp, fi_functors, coantidomain(0) = 1 & coantidomain(1) = 0 &
% 5.41/5.61 coantidomain(2) = 0 &
% 5.41/5.61 coantidomain(3) = 0).
% 5.41/5.61 fof(interp, fi_functors, divergence(0) = 0 & divergence(1) = 1 &
% 5.41/5.61 divergence(2) = 1 &
% 5.41/5.61 divergence(3) = 1).
% 5.41/5.61 fof(interp, fi_functors, esk1_0 = 0).
% 5.41/5.61 fof(interp, fi_functors, esk2_0 = 0).
% 5.41/5.61 fof(interp, fi_predicates, leq(0, 0) & leq(0, 1) & leq(0, 2) & leq(0, 3) &
% 5.41/5.61 ~leq(1, 0) &
% 5.41/5.61 leq(1, 1) &
% 5.41/5.61 ~leq(1, 2) &
% 5.41/5.61 ~leq(1, 3) &
% 5.41/5.61 ~leq(2, 0) &
% 5.41/5.61 leq(2, 1) &
% 5.41/5.61 leq(2, 2) &
% 5.41/5.61 leq(2, 3) &
% 5.41/5.61 ~leq(3, 0) &
% 5.41/5.61 leq(3, 1) &
% 5.41/5.61 ~leq(3, 2) &
% 5.41/5.61 leq(3, 3)).
% 5.41/5.61 fof(interp, fi_functors, multiplication(0, 0) = 0 & multiplication(0, 1) = 0 &
% 5.41/5.61 multiplication(0, 2) = 0 &
% 5.41/5.61 multiplication(0, 3) = 0 &
% 5.41/5.61 multiplication(1, 0) = 0 &
% 5.41/5.61 multiplication(1, 1) = 1 &
% 5.41/5.61 multiplication(1, 2) = 2 &
% 5.41/5.61 multiplication(1, 3) = 3 &
% 5.41/5.61 multiplication(2, 0) = 0 &
% 5.41/5.61 multiplication(2, 1) = 2 &
% 5.41/5.61 multiplication(2, 2) = 2 &
% 5.41/5.61 multiplication(2, 3) = 2 &
% 5.41/5.61 multiplication(3, 0) = 0 &
% 5.41/5.61 multiplication(3, 1) = 3 &
% 5.41/5.61 multiplication(3, 2) = 2 &
% 5.41/5.61 multiplication(3, 3) = 2).
% 5.41/5.61 fof(interp, fi_functors, one = 1).
% 5.41/5.61 fof(interp, fi_functors, star(0) = 3 & star(1) = 3 & star(2) = 3 & star(3) = 3).
% 5.41/5.61 fof(interp, fi_functors, zero = 0).
% 5.41/5.61 % SZS output end FiniteModel for theBenchmark.p
% 5.41/5.61 % 20 lemma(s) from E
% 5.41/5.61 % cnf(cl, axiom, coantidomain(A) = coantidomain(coantidomain(coantidomain(A)))).
% 5.41/5.61 % cnf(cl, axiom, zero = divergence(zero)).
% 5.41/5.61 % cnf(cl, axiom, antidomain(A) = antidomain(antidomain(antidomain(A)))).
% 5.41/5.61 % cnf(cl, axiom, zero = coantidomain(one)).
% 5.41/5.61 % cnf(cl, axiom, zero = antidomain(one)).
% 5.41/5.61 % cnf(cl, axiom, one = coantidomain(zero)).
% 5.41/5.61 % cnf(cl, axiom, one = antidomain(zero)).
% 5.41/5.61 % cnf(cl, axiom, addition(A, B) = addition(A, addition(A, B))).
% 5.41/5.61 % cnf(cl, axiom, addition(A, B) = addition(A, addition(A, B))).
% 5.41/5.61 % cnf(cl, axiom, multiplication(coantidomain(A), coantidomain(A)) = coantidomain(A)).
% 5.41/5.61 % cnf(cl, axiom, A = multiplication(A, coantidomain(coantidomain(A)))).
% 5.41/5.61 % cnf(cl, axiom, multiplication(antidomain(A), antidomain(A)) = antidomain(A)).
% 5.41/5.61 % cnf(cl, axiom, A = multiplication(antidomain(antidomain(A)), A)).
% 5.41/5.61 % cnf(cl, axiom, multiplication(divergence(A), divergence(A)) = divergence(A)).
% 5.41/5.61 % cnf(cl, axiom, antidomain(antidomain(divergence(A))) = divergence(A)).
% 5.41/5.61 % cnf(cl, axiom, multiplication(A, divergence(A)) = multiplication(divergence(A), multiplication(A, divergence(A)))).
% 5.41/5.61 % cnf(cl, axiom, addition(one, antidomain(A)) = one).
% 5.41/5.61 % cnf(cl, axiom, addition(one, coantidomain(A)) = one).
% 5.41/5.61 % cnf(cl, axiom, multiplication(coantidomain(coantidomain(A)), coantidomain(A)) = zero).
% 5.41/5.61 % cnf(cl, axiom, multiplication(A, addition(A, one)) = multiplication(addition(A, one), A)).
% 5.41/5.61 % 38 pred(s)
% 5.41/5.61 % 16 func(s)
% 5.41/5.61 % 1 sort(s)
% 5.41/5.61 % 86 clause(s)
% 5.41/5.61 % Instantiating 1 (5221 ms)
% 5.41/5.61 % Solving (5222 ms)
% 5.41/5.61 % Instantiating 2 (5222 ms)
% 5.41/5.61 % Solving (5222 ms)
% 5.41/5.61 % Instantiating 3 (5222 ms)
% 5.41/5.61 % Solving (5228 ms)
% 5.41/5.61 % Instantiating 4 (5228 ms)
% 5.41/5.61 % Solving (5234 ms)
% 5.41/5.61 %
% 5.41/5.61 % 1 model found (5236 ms)
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