TSTP Solution File: KLE070+1 by Bliksem---1.12

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : Bliksem---1.12
% Problem  : KLE070+1 : TPTP v8.1.0. Released v4.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : bliksem %s

% Computer : n026.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 0s
% DateTime : Sun Jul 17 01:37:00 EDT 2022

% Result   : Theorem 0.85s 1.22s
% Output   : Refutation 0.85s
% Verified : 
% SZS Type : -

% Comments : 
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.08/0.14  % Problem  : KLE070+1 : TPTP v8.1.0. Released v4.0.0.
% 0.08/0.14  % Command  : bliksem %s
% 0.15/0.36  % Computer : n026.cluster.edu
% 0.15/0.36  % Model    : x86_64 x86_64
% 0.15/0.36  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.15/0.36  % Memory   : 8042.1875MB
% 0.15/0.36  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.15/0.36  % CPULimit : 300
% 0.15/0.36  % DateTime : Thu Jun 16 12:18:08 EDT 2022
% 0.15/0.36  % CPUTime  : 
% 0.85/1.22  *** allocated 10000 integers for termspace/termends
% 0.85/1.22  *** allocated 10000 integers for clauses
% 0.85/1.22  *** allocated 10000 integers for justifications
% 0.85/1.22  Bliksem 1.12
% 0.85/1.22  
% 0.85/1.22  
% 0.85/1.22  Automatic Strategy Selection
% 0.85/1.22  
% 0.85/1.22  
% 0.85/1.22  Clauses:
% 0.85/1.22  
% 0.85/1.22  { addition( X, Y ) = addition( Y, X ) }.
% 0.85/1.22  { addition( Z, addition( Y, X ) ) = addition( addition( Z, Y ), X ) }.
% 0.85/1.22  { addition( X, zero ) = X }.
% 0.85/1.22  { addition( X, X ) = X }.
% 0.85/1.22  { multiplication( X, multiplication( Y, Z ) ) = multiplication( 
% 0.85/1.22    multiplication( X, Y ), Z ) }.
% 0.85/1.22  { multiplication( X, one ) = X }.
% 0.85/1.22  { multiplication( one, X ) = X }.
% 0.85/1.22  { multiplication( X, addition( Y, Z ) ) = addition( multiplication( X, Y )
% 0.85/1.22    , multiplication( X, Z ) ) }.
% 0.85/1.22  { multiplication( addition( X, Y ), Z ) = addition( multiplication( X, Z )
% 0.85/1.22    , multiplication( Y, Z ) ) }.
% 0.85/1.22  { multiplication( X, zero ) = zero }.
% 0.85/1.22  { multiplication( zero, X ) = zero }.
% 0.85/1.22  { ! leq( X, Y ), addition( X, Y ) = Y }.
% 0.85/1.22  { ! addition( X, Y ) = Y, leq( X, Y ) }.
% 0.85/1.22  { addition( X, multiplication( domain( X ), X ) ) = multiplication( domain
% 0.85/1.22    ( X ), X ) }.
% 0.85/1.22  { domain( multiplication( X, Y ) ) = domain( multiplication( X, domain( Y )
% 0.85/1.22     ) ) }.
% 0.85/1.22  { addition( domain( X ), one ) = one }.
% 0.85/1.22  { domain( zero ) = zero }.
% 0.85/1.22  { domain( addition( X, Y ) ) = addition( domain( X ), domain( Y ) ) }.
% 0.85/1.22  { ! addition( domain( skol1 ), multiplication( domain( skol1 ), domain( 
% 0.85/1.22    skol2 ) ) ) = domain( skol1 ) }.
% 0.85/1.22  
% 0.85/1.22  percentage equality = 0.904762, percentage horn = 1.000000
% 0.85/1.22  This is a pure equality problem
% 0.85/1.22  
% 0.85/1.22  
% 0.85/1.22  
% 0.85/1.22  Options Used:
% 0.85/1.22  
% 0.85/1.22  useres =            1
% 0.85/1.22  useparamod =        1
% 0.85/1.22  useeqrefl =         1
% 0.85/1.22  useeqfact =         1
% 0.85/1.22  usefactor =         1
% 0.85/1.22  usesimpsplitting =  0
% 0.85/1.22  usesimpdemod =      5
% 0.85/1.22  usesimpres =        3
% 0.85/1.22  
% 0.85/1.22  resimpinuse      =  1000
% 0.85/1.22  resimpclauses =     20000
% 0.85/1.22  substype =          eqrewr
% 0.85/1.22  backwardsubs =      1
% 0.85/1.22  selectoldest =      5
% 0.85/1.22  
% 0.85/1.22  litorderings [0] =  split
% 0.85/1.22  litorderings [1] =  extend the termordering, first sorting on arguments
% 0.85/1.22  
% 0.85/1.22  termordering =      kbo
% 0.85/1.22  
% 0.85/1.22  litapriori =        0
% 0.85/1.22  termapriori =       1
% 0.85/1.22  litaposteriori =    0
% 0.85/1.22  termaposteriori =   0
% 0.85/1.22  demodaposteriori =  0
% 0.85/1.22  ordereqreflfact =   0
% 0.85/1.22  
% 0.85/1.22  litselect =         negord
% 0.85/1.22  
% 0.85/1.22  maxweight =         15
% 0.85/1.22  maxdepth =          30000
% 0.85/1.22  maxlength =         115
% 0.85/1.22  maxnrvars =         195
% 0.85/1.22  excuselevel =       1
% 0.85/1.22  increasemaxweight = 1
% 0.85/1.22  
% 0.85/1.22  maxselected =       10000000
% 0.85/1.22  maxnrclauses =      10000000
% 0.85/1.22  
% 0.85/1.22  showgenerated =    0
% 0.85/1.22  showkept =         0
% 0.85/1.22  showselected =     0
% 0.85/1.22  showdeleted =      0
% 0.85/1.22  showresimp =       1
% 0.85/1.22  showstatus =       2000
% 0.85/1.22  
% 0.85/1.22  prologoutput =     0
% 0.85/1.22  nrgoals =          5000000
% 0.85/1.22  totalproof =       1
% 0.85/1.22  
% 0.85/1.22  Symbols occurring in the translation:
% 0.85/1.22  
% 0.85/1.22  {}  [0, 0]      (w:1, o:2, a:1, s:1, b:0), 
% 0.85/1.22  .  [1, 2]      (w:1, o:21, a:1, s:1, b:0), 
% 0.85/1.22  !  [4, 1]      (w:0, o:15, a:1, s:1, b:0), 
% 0.85/1.22  =  [13, 2]      (w:1, o:0, a:0, s:1, b:0), 
% 0.85/1.22  ==>  [14, 2]      (w:1, o:0, a:0, s:1, b:0), 
% 0.85/1.22  addition  [37, 2]      (w:1, o:45, a:1, s:1, b:0), 
% 0.85/1.22  zero  [39, 0]      (w:1, o:9, a:1, s:1, b:0), 
% 0.85/1.22  multiplication  [40, 2]      (w:1, o:47, a:1, s:1, b:0), 
% 0.85/1.22  one  [41, 0]      (w:1, o:10, a:1, s:1, b:0), 
% 0.85/1.22  leq  [42, 2]      (w:1, o:46, a:1, s:1, b:0), 
% 0.85/1.22  domain  [44, 1]      (w:1, o:20, a:1, s:1, b:0), 
% 0.85/1.22  skol1  [46, 0]      (w:1, o:13, a:1, s:1, b:1), 
% 0.85/1.22  skol2  [47, 0]      (w:1, o:14, a:1, s:1, b:1).
% 0.85/1.22  
% 0.85/1.22  
% 0.85/1.22  Starting Search:
% 0.85/1.22  
% 0.85/1.22  *** allocated 15000 integers for clauses
% 0.85/1.22  *** allocated 22500 integers for clauses
% 0.85/1.22  *** allocated 33750 integers for clauses
% 0.85/1.22  *** allocated 50625 integers for clauses
% 0.85/1.22  
% 0.85/1.22  Bliksems!, er is een bewijs:
% 0.85/1.22  % SZS status Theorem
% 0.85/1.22  % SZS output start Refutation
% 0.85/1.22  
% 0.85/1.22  (0) {G0,W7,D3,L1,V2,M1} I { addition( X, Y ) = addition( Y, X ) }.
% 0.85/1.22  (5) {G0,W5,D3,L1,V1,M1} I { multiplication( X, one ) ==> X }.
% 0.85/1.22  (7) {G0,W13,D4,L1,V3,M1} I { addition( multiplication( X, Y ), 
% 0.85/1.22    multiplication( X, Z ) ) ==> multiplication( X, addition( Y, Z ) ) }.
% 0.85/1.22  (15) {G0,W6,D4,L1,V1,M1} I { addition( domain( X ), one ) ==> one }.
% 0.85/1.22  (18) {G0,W11,D5,L1,V0,M1} I { ! addition( domain( skol1 ), multiplication( 
% 0.85/1.22    domain( skol1 ), domain( skol2 ) ) ) ==> domain( skol1 ) }.
% 0.85/1.22  (20) {G1,W6,D4,L1,V1,M1} P(15,0) { addition( one, domain( X ) ) ==> one }.
% 0.85/1.22  (49) {G1,W11,D4,L1,V2,M1} P(5,7) { addition( X, multiplication( X, Y ) ) = 
% 0.85/1.22    multiplication( X, addition( one, Y ) ) }.
% 0.85/1.22  (712) {G2,W0,D0,L0,V0,M0} P(49,18);d(20);d(5);q {  }.
% 0.85/1.22  
% 0.85/1.22  
% 0.85/1.22  % SZS output end Refutation
% 0.85/1.22  found a proof!
% 0.85/1.22  
% 0.85/1.22  
% 0.85/1.22  Unprocessed initial clauses:
% 0.85/1.22  
% 0.85/1.22  (714) {G0,W7,D3,L1,V2,M1}  { addition( X, Y ) = addition( Y, X ) }.
% 0.85/1.22  (715) {G0,W11,D4,L1,V3,M1}  { addition( Z, addition( Y, X ) ) = addition( 
% 0.85/1.22    addition( Z, Y ), X ) }.
% 0.85/1.22  (716) {G0,W5,D3,L1,V1,M1}  { addition( X, zero ) = X }.
% 0.85/1.22  (717) {G0,W5,D3,L1,V1,M1}  { addition( X, X ) = X }.
% 0.85/1.22  (718) {G0,W11,D4,L1,V3,M1}  { multiplication( X, multiplication( Y, Z ) ) =
% 0.85/1.22     multiplication( multiplication( X, Y ), Z ) }.
% 0.85/1.22  (719) {G0,W5,D3,L1,V1,M1}  { multiplication( X, one ) = X }.
% 0.85/1.22  (720) {G0,W5,D3,L1,V1,M1}  { multiplication( one, X ) = X }.
% 0.85/1.22  (721) {G0,W13,D4,L1,V3,M1}  { multiplication( X, addition( Y, Z ) ) = 
% 0.85/1.22    addition( multiplication( X, Y ), multiplication( X, Z ) ) }.
% 0.85/1.22  (722) {G0,W13,D4,L1,V3,M1}  { multiplication( addition( X, Y ), Z ) = 
% 0.85/1.22    addition( multiplication( X, Z ), multiplication( Y, Z ) ) }.
% 0.85/1.22  (723) {G0,W5,D3,L1,V1,M1}  { multiplication( X, zero ) = zero }.
% 0.85/1.22  (724) {G0,W5,D3,L1,V1,M1}  { multiplication( zero, X ) = zero }.
% 0.85/1.22  (725) {G0,W8,D3,L2,V2,M2}  { ! leq( X, Y ), addition( X, Y ) = Y }.
% 0.85/1.22  (726) {G0,W8,D3,L2,V2,M2}  { ! addition( X, Y ) = Y, leq( X, Y ) }.
% 0.85/1.22  (727) {G0,W11,D5,L1,V1,M1}  { addition( X, multiplication( domain( X ), X )
% 0.85/1.22     ) = multiplication( domain( X ), X ) }.
% 0.85/1.22  (728) {G0,W10,D5,L1,V2,M1}  { domain( multiplication( X, Y ) ) = domain( 
% 0.85/1.22    multiplication( X, domain( Y ) ) ) }.
% 0.85/1.22  (729) {G0,W6,D4,L1,V1,M1}  { addition( domain( X ), one ) = one }.
% 0.85/1.22  (730) {G0,W4,D3,L1,V0,M1}  { domain( zero ) = zero }.
% 0.85/1.22  (731) {G0,W10,D4,L1,V2,M1}  { domain( addition( X, Y ) ) = addition( domain
% 0.85/1.22    ( X ), domain( Y ) ) }.
% 0.85/1.22  (732) {G0,W11,D5,L1,V0,M1}  { ! addition( domain( skol1 ), multiplication( 
% 0.85/1.22    domain( skol1 ), domain( skol2 ) ) ) = domain( skol1 ) }.
% 0.85/1.22  
% 0.85/1.22  
% 0.85/1.22  Total Proof:
% 0.85/1.22  
% 0.85/1.22  subsumption: (0) {G0,W7,D3,L1,V2,M1} I { addition( X, Y ) = addition( Y, X
% 0.85/1.22     ) }.
% 0.85/1.22  parent0: (714) {G0,W7,D3,L1,V2,M1}  { addition( X, Y ) = addition( Y, X )
% 0.85/1.22     }.
% 0.85/1.22  substitution0:
% 0.85/1.22     X := X
% 0.85/1.22     Y := Y
% 0.85/1.22  end
% 0.85/1.22  permutation0:
% 0.85/1.22     0 ==> 0
% 0.85/1.22  end
% 0.85/1.22  
% 0.85/1.22  subsumption: (5) {G0,W5,D3,L1,V1,M1} I { multiplication( X, one ) ==> X }.
% 0.85/1.22  parent0: (719) {G0,W5,D3,L1,V1,M1}  { multiplication( X, one ) = X }.
% 0.85/1.22  substitution0:
% 0.85/1.22     X := X
% 0.85/1.22  end
% 0.85/1.22  permutation0:
% 0.85/1.22     0 ==> 0
% 0.85/1.22  end
% 0.85/1.22  
% 0.85/1.22  eqswap: (744) {G0,W13,D4,L1,V3,M1}  { addition( multiplication( X, Y ), 
% 0.85/1.22    multiplication( X, Z ) ) = multiplication( X, addition( Y, Z ) ) }.
% 0.85/1.22  parent0[0]: (721) {G0,W13,D4,L1,V3,M1}  { multiplication( X, addition( Y, Z
% 0.85/1.22     ) ) = addition( multiplication( X, Y ), multiplication( X, Z ) ) }.
% 0.85/1.22  substitution0:
% 0.85/1.22     X := X
% 0.85/1.22     Y := Y
% 0.85/1.22     Z := Z
% 0.85/1.22  end
% 0.85/1.22  
% 0.85/1.22  subsumption: (7) {G0,W13,D4,L1,V3,M1} I { addition( multiplication( X, Y )
% 0.85/1.22    , multiplication( X, Z ) ) ==> multiplication( X, addition( Y, Z ) ) }.
% 0.85/1.22  parent0: (744) {G0,W13,D4,L1,V3,M1}  { addition( multiplication( X, Y ), 
% 0.85/1.22    multiplication( X, Z ) ) = multiplication( X, addition( Y, Z ) ) }.
% 0.85/1.22  substitution0:
% 0.85/1.22     X := X
% 0.85/1.22     Y := Y
% 0.85/1.22     Z := Z
% 0.85/1.22  end
% 0.85/1.22  permutation0:
% 0.85/1.22     0 ==> 0
% 0.85/1.22  end
% 0.85/1.22  
% 0.85/1.22  subsumption: (15) {G0,W6,D4,L1,V1,M1} I { addition( domain( X ), one ) ==> 
% 0.85/1.22    one }.
% 0.85/1.22  parent0: (729) {G0,W6,D4,L1,V1,M1}  { addition( domain( X ), one ) = one
% 0.85/1.22     }.
% 0.85/1.22  substitution0:
% 0.85/1.22     X := X
% 0.85/1.22  end
% 0.85/1.22  permutation0:
% 0.85/1.22     0 ==> 0
% 0.85/1.22  end
% 0.85/1.22  
% 0.85/1.22  subsumption: (18) {G0,W11,D5,L1,V0,M1} I { ! addition( domain( skol1 ), 
% 0.85/1.22    multiplication( domain( skol1 ), domain( skol2 ) ) ) ==> domain( skol1 )
% 0.85/1.22     }.
% 0.85/1.22  parent0: (732) {G0,W11,D5,L1,V0,M1}  { ! addition( domain( skol1 ), 
% 0.85/1.22    multiplication( domain( skol1 ), domain( skol2 ) ) ) = domain( skol1 )
% 0.85/1.22     }.
% 0.85/1.22  substitution0:
% 0.85/1.22  end
% 0.85/1.22  permutation0:
% 0.85/1.22     0 ==> 0
% 0.85/1.22  end
% 0.85/1.22  
% 0.85/1.22  eqswap: (778) {G0,W6,D4,L1,V1,M1}  { one ==> addition( domain( X ), one )
% 0.85/1.22     }.
% 0.85/1.22  parent0[0]: (15) {G0,W6,D4,L1,V1,M1} I { addition( domain( X ), one ) ==> 
% 0.85/1.22    one }.
% 0.85/1.22  substitution0:
% 0.85/1.22     X := X
% 0.85/1.22  end
% 0.85/1.22  
% 0.85/1.22  paramod: (779) {G1,W6,D4,L1,V1,M1}  { one ==> addition( one, domain( X ) )
% 0.85/1.22     }.
% 0.85/1.22  parent0[0]: (0) {G0,W7,D3,L1,V2,M1} I { addition( X, Y ) = addition( Y, X )
% 0.85/1.22     }.
% 0.85/1.22  parent1[0; 2]: (778) {G0,W6,D4,L1,V1,M1}  { one ==> addition( domain( X ), 
% 0.85/1.22    one ) }.
% 0.85/1.22  substitution0:
% 0.85/1.22     X := domain( X )
% 0.85/1.22     Y := one
% 0.85/1.22  end
% 0.85/1.22  substitution1:
% 0.85/1.22     X := X
% 0.85/1.22  end
% 0.85/1.22  
% 0.85/1.22  eqswap: (782) {G1,W6,D4,L1,V1,M1}  { addition( one, domain( X ) ) ==> one
% 0.85/1.22     }.
% 0.85/1.22  parent0[0]: (779) {G1,W6,D4,L1,V1,M1}  { one ==> addition( one, domain( X )
% 0.85/1.22     ) }.
% 0.85/1.22  substitution0:
% 0.85/1.22     X := X
% 0.85/1.22  end
% 0.85/1.22  
% 0.85/1.22  subsumption: (20) {G1,W6,D4,L1,V1,M1} P(15,0) { addition( one, domain( X )
% 0.85/1.22     ) ==> one }.
% 0.85/1.22  parent0: (782) {G1,W6,D4,L1,V1,M1}  { addition( one, domain( X ) ) ==> one
% 0.85/1.22     }.
% 0.85/1.22  substitution0:
% 0.85/1.22     X := X
% 0.85/1.22  end
% 0.85/1.22  permutation0:
% 0.85/1.22     0 ==> 0
% 0.85/1.22  end
% 0.85/1.22  
% 0.85/1.22  eqswap: (784) {G0,W13,D4,L1,V3,M1}  { multiplication( X, addition( Y, Z ) )
% 0.85/1.22     ==> addition( multiplication( X, Y ), multiplication( X, Z ) ) }.
% 0.85/1.22  parent0[0]: (7) {G0,W13,D4,L1,V3,M1} I { addition( multiplication( X, Y ), 
% 0.85/1.22    multiplication( X, Z ) ) ==> multiplication( X, addition( Y, Z ) ) }.
% 0.85/1.22  substitution0:
% 0.85/1.22     X := X
% 0.85/1.22     Y := Y
% 0.85/1.22     Z := Z
% 0.85/1.22  end
% 0.85/1.22  
% 0.85/1.22  paramod: (785) {G1,W11,D4,L1,V2,M1}  { multiplication( X, addition( one, Y
% 0.85/1.22     ) ) ==> addition( X, multiplication( X, Y ) ) }.
% 0.85/1.22  parent0[0]: (5) {G0,W5,D3,L1,V1,M1} I { multiplication( X, one ) ==> X }.
% 0.85/1.22  parent1[0; 7]: (784) {G0,W13,D4,L1,V3,M1}  { multiplication( X, addition( Y
% 0.85/1.22    , Z ) ) ==> addition( multiplication( X, Y ), multiplication( X, Z ) )
% 0.85/1.22     }.
% 0.85/1.22  substitution0:
% 0.85/1.22     X := X
% 0.85/1.22  end
% 0.85/1.22  substitution1:
% 0.85/1.22     X := X
% 0.85/1.22     Y := one
% 0.85/1.22     Z := Y
% 0.85/1.22  end
% 0.85/1.22  
% 0.85/1.22  eqswap: (787) {G1,W11,D4,L1,V2,M1}  { addition( X, multiplication( X, Y ) )
% 0.85/1.22     ==> multiplication( X, addition( one, Y ) ) }.
% 0.85/1.22  parent0[0]: (785) {G1,W11,D4,L1,V2,M1}  { multiplication( X, addition( one
% 0.85/1.22    , Y ) ) ==> addition( X, multiplication( X, Y ) ) }.
% 0.85/1.22  substitution0:
% 0.85/1.22     X := X
% 0.85/1.22     Y := Y
% 0.85/1.22  end
% 0.85/1.22  
% 0.85/1.22  subsumption: (49) {G1,W11,D4,L1,V2,M1} P(5,7) { addition( X, multiplication
% 0.85/1.22    ( X, Y ) ) = multiplication( X, addition( one, Y ) ) }.
% 0.85/1.22  parent0: (787) {G1,W11,D4,L1,V2,M1}  { addition( X, multiplication( X, Y )
% 0.85/1.22     ) ==> multiplication( X, addition( one, Y ) ) }.
% 0.85/1.22  substitution0:
% 0.85/1.22     X := X
% 0.85/1.22     Y := Y
% 0.85/1.22  end
% 0.85/1.22  permutation0:
% 0.85/1.22     0 ==> 0
% 0.85/1.22  end
% 0.85/1.22  
% 0.85/1.22  eqswap: (790) {G0,W11,D5,L1,V0,M1}  { ! domain( skol1 ) ==> addition( 
% 0.85/1.22    domain( skol1 ), multiplication( domain( skol1 ), domain( skol2 ) ) ) }.
% 0.85/1.22  parent0[0]: (18) {G0,W11,D5,L1,V0,M1} I { ! addition( domain( skol1 ), 
% 0.85/1.22    multiplication( domain( skol1 ), domain( skol2 ) ) ) ==> domain( skol1 )
% 0.85/1.22     }.
% 0.85/1.22  substitution0:
% 0.85/1.22  end
% 0.85/1.22  
% 0.85/1.22  paramod: (793) {G1,W10,D5,L1,V0,M1}  { ! domain( skol1 ) ==> multiplication
% 0.85/1.22    ( domain( skol1 ), addition( one, domain( skol2 ) ) ) }.
% 0.85/1.22  parent0[0]: (49) {G1,W11,D4,L1,V2,M1} P(5,7) { addition( X, multiplication
% 0.85/1.22    ( X, Y ) ) = multiplication( X, addition( one, Y ) ) }.
% 0.85/1.22  parent1[0; 4]: (790) {G0,W11,D5,L1,V0,M1}  { ! domain( skol1 ) ==> addition
% 0.85/1.22    ( domain( skol1 ), multiplication( domain( skol1 ), domain( skol2 ) ) )
% 0.85/1.22     }.
% 0.85/1.22  substitution0:
% 0.85/1.22     X := domain( skol1 )
% 0.85/1.22     Y := domain( skol2 )
% 0.85/1.22  end
% 0.85/1.22  substitution1:
% 0.85/1.22  end
% 0.85/1.22  
% 0.85/1.22  paramod: (794) {G2,W7,D4,L1,V0,M1}  { ! domain( skol1 ) ==> multiplication
% 0.85/1.22    ( domain( skol1 ), one ) }.
% 0.85/1.22  parent0[0]: (20) {G1,W6,D4,L1,V1,M1} P(15,0) { addition( one, domain( X ) )
% 0.85/1.22     ==> one }.
% 0.85/1.22  parent1[0; 7]: (793) {G1,W10,D5,L1,V0,M1}  { ! domain( skol1 ) ==> 
% 0.85/1.22    multiplication( domain( skol1 ), addition( one, domain( skol2 ) ) ) }.
% 0.85/1.22  substitution0:
% 0.85/1.22     X := skol2
% 0.85/1.22  end
% 0.85/1.22  substitution1:
% 0.85/1.22  end
% 0.85/1.22  
% 0.85/1.22  paramod: (795) {G1,W5,D3,L1,V0,M1}  { ! domain( skol1 ) ==> domain( skol1 )
% 0.85/1.22     }.
% 0.85/1.22  parent0[0]: (5) {G0,W5,D3,L1,V1,M1} I { multiplication( X, one ) ==> X }.
% 0.85/1.22  parent1[0; 4]: (794) {G2,W7,D4,L1,V0,M1}  { ! domain( skol1 ) ==> 
% 0.85/1.22    multiplication( domain( skol1 ), one ) }.
% 0.85/1.22  substitution0:
% 0.85/1.22     X := domain( skol1 )
% 0.85/1.22  end
% 0.85/1.22  substitution1:
% 0.85/1.22  end
% 0.85/1.22  
% 0.85/1.22  eqrefl: (796) {G0,W0,D0,L0,V0,M0}  {  }.
% 0.85/1.22  parent0[0]: (795) {G1,W5,D3,L1,V0,M1}  { ! domain( skol1 ) ==> domain( 
% 0.85/1.22    skol1 ) }.
% 0.85/1.22  substitution0:
% 0.85/1.22  end
% 0.85/1.22  
% 0.85/1.22  subsumption: (712) {G2,W0,D0,L0,V0,M0} P(49,18);d(20);d(5);q {  }.
% 0.85/1.22  parent0: (796) {G0,W0,D0,L0,V0,M0}  {  }.
% 0.85/1.22  substitution0:
% 0.85/1.22  end
% 0.85/1.22  permutation0:
% 0.85/1.22  end
% 0.85/1.22  
% 0.85/1.22  Proof check complete!
% 0.85/1.22  
% 0.85/1.22  Memory use:
% 0.85/1.22  
% 0.85/1.22  space for terms:        8344
% 0.85/1.22  space for clauses:      43945
% 0.85/1.22  
% 0.85/1.22  
% 0.85/1.22  clauses generated:      7275
% 0.85/1.22  clauses kept:           713
% 0.85/1.22  clauses selected:       154
% 0.85/1.22  clauses deleted:        2
% 0.85/1.22  clauses inuse deleted:  0
% 0.85/1.22  
% 0.85/1.22  subsentry:          8331
% 0.85/1.22  literals s-matched: 6530
% 0.85/1.22  literals matched:   6482
% 0.85/1.22  full subsumption:   418
% 0.85/1.22  
% 0.85/1.22  checksum:           531320817
% 0.85/1.22  
% 0.85/1.22  
% 0.85/1.22  Bliksem ended
%------------------------------------------------------------------------------