TSTP Solution File: KLE059+1 by SInE---0.4
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%------------------------------------------------------------------------------
% File : SInE---0.4
% Problem : KLE059+1 : TPTP v5.0.0. Released v4.0.0.
% Transfm : none
% Format : tptp:raw
% Command : Source/sine.py -e eprover -t %d %s
% Computer : art06.cs.miami.edu
% Model : i686 i686
% CPU : Intel(R) Pentium(R) 4 CPU 2.80GHz @ 2793MHz
% Memory : 2018MB
% OS : Linux 2.6.26.8-57.fc8
% CPULimit : 300s
% DateTime : Sat Dec 25 12:06:41 EST 2010
% Result : Theorem 0.17s
% Output : CNFRefutation 0.17s
% Verified :
% SZS Type : Refutation
% Derivation depth : 9
% Number of leaves : 3
% Syntax : Number of formulae : 18 ( 13 unt; 0 def)
% Number of atoms : 23 ( 20 equ)
% Maximal formula atoms : 2 ( 1 avg)
% Number of connectives : 11 ( 6 ~; 0 |; 3 &)
% ( 0 <=>; 2 =>; 0 <=; 0 <~>)
% Maximal formula depth : 5 ( 3 avg)
% Maximal term depth : 3 ( 2 avg)
% Number of predicates : 2 ( 0 usr; 1 prp; 0-2 aty)
% Number of functors : 4 ( 4 usr; 2 con; 0-2 aty)
% Number of variables : 20 ( 0 sgn 12 !; 4 ?)
% Comments :
%------------------------------------------------------------------------------
fof(2,axiom,
! [X1,X2] : addition(X1,X2) = addition(X2,X1),
file('/tmp/tmp_kByrL/sel_KLE059+1.p_1',additive_commutativity) ).
fof(9,axiom,
! [X4,X5] : domain(addition(X4,X5)) = addition(domain(X4),domain(X5)),
file('/tmp/tmp_kByrL/sel_KLE059+1.p_1',domain5) ).
fof(10,conjecture,
! [X4,X5] :
( addition(X4,X5) = X5
=> addition(domain(X4),domain(X5)) = domain(X5) ),
file('/tmp/tmp_kByrL/sel_KLE059+1.p_1',goals) ).
fof(11,negated_conjecture,
~ ! [X4,X5] :
( addition(X4,X5) = X5
=> addition(domain(X4),domain(X5)) = domain(X5) ),
inference(assume_negation,[status(cth)],[10]) ).
fof(14,plain,
! [X3,X4] : addition(X3,X4) = addition(X4,X3),
inference(variable_rename,[status(thm)],[2]) ).
cnf(15,plain,
addition(X1,X2) = addition(X2,X1),
inference(split_conjunct,[status(thm)],[14]) ).
fof(28,plain,
! [X6,X7] : domain(addition(X6,X7)) = addition(domain(X6),domain(X7)),
inference(variable_rename,[status(thm)],[9]) ).
cnf(29,plain,
domain(addition(X1,X2)) = addition(domain(X1),domain(X2)),
inference(split_conjunct,[status(thm)],[28]) ).
fof(30,negated_conjecture,
? [X4,X5] :
( addition(X4,X5) = X5
& addition(domain(X4),domain(X5)) != domain(X5) ),
inference(fof_nnf,[status(thm)],[11]) ).
fof(31,negated_conjecture,
? [X6,X7] :
( addition(X6,X7) = X7
& addition(domain(X6),domain(X7)) != domain(X7) ),
inference(variable_rename,[status(thm)],[30]) ).
fof(32,negated_conjecture,
( addition(esk1_0,esk2_0) = esk2_0
& addition(domain(esk1_0),domain(esk2_0)) != domain(esk2_0) ),
inference(skolemize,[status(esa)],[31]) ).
cnf(33,negated_conjecture,
addition(domain(esk1_0),domain(esk2_0)) != domain(esk2_0),
inference(split_conjunct,[status(thm)],[32]) ).
cnf(34,negated_conjecture,
addition(esk1_0,esk2_0) = esk2_0,
inference(split_conjunct,[status(thm)],[32]) ).
cnf(37,negated_conjecture,
addition(esk2_0,esk1_0) = esk2_0,
inference(rw,[status(thm)],[34,15,theory(equality)]) ).
cnf(38,negated_conjecture,
addition(domain(esk2_0),domain(esk1_0)) != domain(esk2_0),
inference(rw,[status(thm)],[33,15,theory(equality)]) ).
cnf(163,negated_conjecture,
$false,
inference(rw,[status(thm)],[inference(rw,[status(thm)],[38,29,theory(equality)]),37,theory(equality)]) ).
cnf(164,negated_conjecture,
$false,
inference(cn,[status(thm)],[163,theory(equality)]) ).
cnf(165,negated_conjecture,
$false,
164,
[proof] ).
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% % SZS status Started for /home/graph/tptp/TPTP/Problems/KLE/KLE059+1.p
% --creating new selector for [KLE001+0.ax, KLE001+5.ax]
% -running prover on /tmp/tmp_kByrL/sel_KLE059+1.p_1 with time limit 29
% -prover status Theorem
% Problem KLE059+1.p solved in phase 0.
% % SZS status Theorem for /home/graph/tptp/TPTP/Problems/KLE/KLE059+1.p
% % SZS status Ended for /home/graph/tptp/TPTP/Problems/KLE/KLE059+1.p
% Solved 1 out of 1.
% # Problem is unsatisfiable (or provable), constructing proof object
% # SZS status Theorem
% # SZS output start CNFRefutation.
% See solution above
% # SZS output end CNFRefutation
%
%------------------------------------------------------------------------------