%------------------------------------------------------------------------------
% File     : Etableau---0.67
% Problem  : KLE059+1 : TPTP v8.1.0. Released v4.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : etableau --auto --tsmdo --quicksat=10000 --tableau=1 --tableau-saturation=1 -s -p --tableau-cores=8 --cpu-limit=%d %s

% Computer : n020.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 600s
% DateTime : Sun Jul 17 01:56:53 EDT 2022

% Result   : Theorem 0.13s 0.36s
% Output   : CNFRefutation 0.13s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :    4
%            Number of leaves      :    2
% Syntax   : Number of formulae    :    9 (   6 unt;   0 def)
%            Number of atoms       :   12 (  11 equ)
%            Maximal formula atoms :    2 (   1 avg)
%            Number of connectives :    6 (   3   ~;   0   |;   1   &)
%                                         (   0 <=>;   2  =>;   0  <=;   0 <~>)
%            Maximal formula depth :    5 (   3 avg)
%            Maximal term depth    :    3 (   2 avg)
%            Number of predicates  :    2 (   0 usr;   1 prp; 0-2 aty)
%            Number of functors    :    4 (   4 usr;   2 con; 0-2 aty)
%            Number of variables   :   10 (   0 sgn   8   !;   0   ?)

% Comments : 
%------------------------------------------------------------------------------
fof(goals,conjecture,
    ! [X4,X5] :
      ( addition(X4,X5) = X5
     => addition(domain(X4),domain(X5)) = domain(X5) ),
    file('/export/starexec/sandbox2/benchmark/theBenchmark.p',goals) ).

fof(domain5,axiom,
    ! [X4,X5] : domain(addition(X4,X5)) = addition(domain(X4),domain(X5)),
    file('/export/starexec/sandbox2/benchmark/Axioms/KLE001+5.ax',domain5) ).

fof(c_0_2,negated_conjecture,
    ~ ! [X4,X5] :
        ( addition(X4,X5) = X5
       => addition(domain(X4),domain(X5)) = domain(X5) ),
    inference(assume_negation,[status(cth)],[goals]) ).

fof(c_0_3,negated_conjecture,
    ( addition(esk1_0,esk2_0) = esk2_0
    & addition(domain(esk1_0),domain(esk2_0)) != domain(esk2_0) ),
    inference(skolemize,[status(esa)],[inference(variable_rename,[status(thm)],[inference(fof_nnf,[status(thm)],[c_0_2])])]) ).

fof(c_0_4,plain,
    ! [X32,X33] : domain(addition(X32,X33)) = addition(domain(X32),domain(X33)),
    inference(variable_rename,[status(thm)],[domain5]) ).

cnf(c_0_5,negated_conjecture,
    addition(domain(esk1_0),domain(esk2_0)) != domain(esk2_0),
    inference(split_conjunct,[status(thm)],[c_0_3]) ).

cnf(c_0_6,plain,
    domain(addition(X1,X2)) = addition(domain(X1),domain(X2)),
    inference(split_conjunct,[status(thm)],[c_0_4]) ).

cnf(c_0_7,negated_conjecture,
    addition(esk1_0,esk2_0) = esk2_0,
    inference(split_conjunct,[status(thm)],[c_0_3]) ).

cnf(c_0_8,negated_conjecture,
    $false,
    inference(cn,[status(thm)],[inference(rw,[status(thm)],[inference(rw,[status(thm)],[c_0_5,c_0_6]),c_0_7])]),
    [proof] ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.10/0.12  % Problem  : KLE059+1 : TPTP v8.1.0. Released v4.0.0.
% 0.10/0.12  % Command  : etableau --auto --tsmdo --quicksat=10000 --tableau=1 --tableau-saturation=1 -s -p --tableau-cores=8 --cpu-limit=%d %s
% 0.13/0.33  % Computer : n020.cluster.edu
% 0.13/0.33  % Model    : x86_64 x86_64
% 0.13/0.33  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.33  % Memory   : 8042.1875MB
% 0.13/0.33  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.13/0.33  % CPULimit : 300
% 0.13/0.33  % WCLimit  : 600
% 0.13/0.33  % DateTime : Thu Jun 16 08:22:49 EDT 2022
% 0.13/0.33  % CPUTime  : 
% 0.13/0.36  # No SInE strategy applied
% 0.13/0.36  # Auto-Mode selected heuristic G_E___208_C12_11_nc_F1_SE_CS_SP_PS_S5PRR_RG_S04AN
% 0.13/0.36  # and selection function SelectComplexExceptUniqMaxHorn.
% 0.13/0.36  #
% 0.13/0.36  # Presaturation interreduction done
% 0.13/0.36  
% 0.13/0.36  # Proof found!
% 0.13/0.36  # SZS status Theorem
% 0.13/0.36  # SZS output start CNFRefutation
% See solution above
% 0.13/0.36  # Training examples: 0 positive, 0 negative
%------------------------------------------------------------------------------