TSTP Solution File: KLE051+1 by Duper---1.0

View Problem - Process Solution

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% File     : Duper---1.0
% Problem  : KLE051+1 : TPTP v8.1.2. Released v4.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : duper %s

% Computer : n003.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Thu Aug 31 05:28:27 EDT 2023

% Result   : Theorem 4.63s 4.79s
% Output   : Proof 4.63s
% Verified : 
% SZS Type : -

% Comments : 
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.03/0.12  % Problem    : KLE051+1 : TPTP v8.1.2. Released v4.0.0.
% 0.12/0.13  % Command    : duper %s
% 0.13/0.34  % Computer : n003.cluster.edu
% 0.13/0.34  % Model    : x86_64 x86_64
% 0.13/0.34  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.34  % Memory   : 8042.1875MB
% 0.13/0.34  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.13/0.34  % CPULimit   : 300
% 0.13/0.34  % WCLimit    : 300
% 0.13/0.34  % DateTime   : Tue Aug 29 11:47:26 EDT 2023
% 0.13/0.34  % CPUTime    : 
% 4.63/4.79  SZS status Theorem for theBenchmark.p
% 4.63/4.79  SZS output start Proof for theBenchmark.p
% 4.63/4.79  Clause #3 (by assumption #[]): Eq (∀ (A : Iota), Eq (addition A A) A) True
% 4.63/4.79  Clause #17 (by assumption #[]): Eq (Not (∀ (X0 : Iota), Eq (addition X0 X0) X0)) True
% 4.63/4.79  Clause #25 (by clausification #[3]): ∀ (a : Iota), Eq (Eq (addition a a) a) True
% 4.63/4.79  Clause #26 (by clausification #[25]): ∀ (a : Iota), Eq (addition a a) a
% 4.63/4.79  Clause #210 (by clausification #[17]): Eq (∀ (X0 : Iota), Eq (addition X0 X0) X0) False
% 4.63/4.79  Clause #211 (by clausification #[210]): ∀ (a : Iota), Eq (Not (Eq (addition (skS.0 0 a) (skS.0 0 a)) (skS.0 0 a))) True
% 4.63/4.79  Clause #212 (by clausification #[211]): ∀ (a : Iota), Eq (Eq (addition (skS.0 0 a) (skS.0 0 a)) (skS.0 0 a)) False
% 4.63/4.79  Clause #213 (by clausification #[212]): ∀ (a : Iota), Ne (addition (skS.0 0 a) (skS.0 0 a)) (skS.0 0 a)
% 4.63/4.79  Clause #214 (by forward demodulation #[213, 26]): ∀ (a : Iota), Ne (skS.0 0 a) (skS.0 0 a)
% 4.63/4.79  Clause #215 (by eliminate resolved literals #[214]): False
% 4.63/4.79  SZS output end Proof for theBenchmark.p
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