TSTP Solution File: KLE051+1 by Duper---1.0
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% File : Duper---1.0
% Problem : KLE051+1 : TPTP v8.1.2. Released v4.0.0.
% Transfm : none
% Format : tptp:raw
% Command : duper %s
% Computer : n003.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 300s
% DateTime : Thu Aug 31 05:28:27 EDT 2023
% Result : Theorem 4.63s 4.79s
% Output : Proof 4.63s
% Verified :
% SZS Type : -
% Comments :
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.03/0.12 % Problem : KLE051+1 : TPTP v8.1.2. Released v4.0.0.
% 0.12/0.13 % Command : duper %s
% 0.13/0.34 % Computer : n003.cluster.edu
% 0.13/0.34 % Model : x86_64 x86_64
% 0.13/0.34 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.34 % Memory : 8042.1875MB
% 0.13/0.34 % OS : Linux 3.10.0-693.el7.x86_64
% 0.13/0.34 % CPULimit : 300
% 0.13/0.34 % WCLimit : 300
% 0.13/0.34 % DateTime : Tue Aug 29 11:47:26 EDT 2023
% 0.13/0.34 % CPUTime :
% 4.63/4.79 SZS status Theorem for theBenchmark.p
% 4.63/4.79 SZS output start Proof for theBenchmark.p
% 4.63/4.79 Clause #3 (by assumption #[]): Eq (∀ (A : Iota), Eq (addition A A) A) True
% 4.63/4.79 Clause #17 (by assumption #[]): Eq (Not (∀ (X0 : Iota), Eq (addition X0 X0) X0)) True
% 4.63/4.79 Clause #25 (by clausification #[3]): ∀ (a : Iota), Eq (Eq (addition a a) a) True
% 4.63/4.79 Clause #26 (by clausification #[25]): ∀ (a : Iota), Eq (addition a a) a
% 4.63/4.79 Clause #210 (by clausification #[17]): Eq (∀ (X0 : Iota), Eq (addition X0 X0) X0) False
% 4.63/4.79 Clause #211 (by clausification #[210]): ∀ (a : Iota), Eq (Not (Eq (addition (skS.0 0 a) (skS.0 0 a)) (skS.0 0 a))) True
% 4.63/4.79 Clause #212 (by clausification #[211]): ∀ (a : Iota), Eq (Eq (addition (skS.0 0 a) (skS.0 0 a)) (skS.0 0 a)) False
% 4.63/4.79 Clause #213 (by clausification #[212]): ∀ (a : Iota), Ne (addition (skS.0 0 a) (skS.0 0 a)) (skS.0 0 a)
% 4.63/4.79 Clause #214 (by forward demodulation #[213, 26]): ∀ (a : Iota), Ne (skS.0 0 a) (skS.0 0 a)
% 4.63/4.79 Clause #215 (by eliminate resolved literals #[214]): False
% 4.63/4.79 SZS output end Proof for theBenchmark.p
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