TSTP Solution File: KLE051+1 by Bliksem---1.12

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : Bliksem---1.12
% Problem  : KLE051+1 : TPTP v8.1.0. Released v4.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : bliksem %s

% Computer : n013.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 0s
% DateTime : Sun Jul 17 01:36:55 EDT 2022

% Result   : Theorem 0.75s 1.14s
% Output   : Refutation 0.75s
% Verified : 
% SZS Type : -

% Comments : 
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.08/0.13  % Problem  : KLE051+1 : TPTP v8.1.0. Released v4.0.0.
% 0.08/0.14  % Command  : bliksem %s
% 0.14/0.36  % Computer : n013.cluster.edu
% 0.14/0.36  % Model    : x86_64 x86_64
% 0.14/0.36  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.14/0.36  % Memory   : 8042.1875MB
% 0.14/0.36  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.14/0.36  % CPULimit : 300
% 0.14/0.36  % DateTime : Thu Jun 16 11:32:44 EDT 2022
% 0.14/0.36  % CPUTime  : 
% 0.75/1.14  *** allocated 10000 integers for termspace/termends
% 0.75/1.14  *** allocated 10000 integers for clauses
% 0.75/1.14  *** allocated 10000 integers for justifications
% 0.75/1.14  Bliksem 1.12
% 0.75/1.14  
% 0.75/1.14  
% 0.75/1.14  Automatic Strategy Selection
% 0.75/1.14  
% 0.75/1.14  
% 0.75/1.14  Clauses:
% 0.75/1.14  
% 0.75/1.14  { addition( X, Y ) = addition( Y, X ) }.
% 0.75/1.14  { addition( Z, addition( Y, X ) ) = addition( addition( Z, Y ), X ) }.
% 0.75/1.14  { addition( X, zero ) = X }.
% 0.75/1.14  { addition( X, X ) = X }.
% 0.75/1.14  { multiplication( X, multiplication( Y, Z ) ) = multiplication( 
% 0.75/1.14    multiplication( X, Y ), Z ) }.
% 0.75/1.14  { multiplication( X, one ) = X }.
% 0.75/1.14  { multiplication( one, X ) = X }.
% 0.75/1.14  { multiplication( X, addition( Y, Z ) ) = addition( multiplication( X, Y )
% 0.75/1.14    , multiplication( X, Z ) ) }.
% 0.75/1.14  { multiplication( addition( X, Y ), Z ) = addition( multiplication( X, Z )
% 0.75/1.14    , multiplication( Y, Z ) ) }.
% 0.75/1.14  { multiplication( X, zero ) = zero }.
% 0.75/1.14  { multiplication( zero, X ) = zero }.
% 0.75/1.14  { ! leq( X, Y ), addition( X, Y ) = Y }.
% 0.75/1.14  { ! addition( X, Y ) = Y, leq( X, Y ) }.
% 0.75/1.14  { addition( X, multiplication( domain( X ), X ) ) = multiplication( domain
% 0.75/1.14    ( X ), X ) }.
% 0.75/1.14  { domain( multiplication( X, Y ) ) = domain( multiplication( X, domain( Y )
% 0.75/1.14     ) ) }.
% 0.75/1.14  { addition( domain( X ), one ) = one }.
% 0.75/1.14  { domain( zero ) = zero }.
% 0.75/1.14  { domain( addition( X, Y ) ) = addition( domain( X ), domain( Y ) ) }.
% 0.75/1.14  { ! addition( skol1, skol1 ) = skol1 }.
% 0.75/1.14  
% 0.75/1.14  percentage equality = 0.904762, percentage horn = 1.000000
% 0.75/1.14  This is a pure equality problem
% 0.75/1.14  
% 0.75/1.14  
% 0.75/1.14  
% 0.75/1.14  Options Used:
% 0.75/1.14  
% 0.75/1.14  useres =            1
% 0.75/1.14  useparamod =        1
% 0.75/1.14  useeqrefl =         1
% 0.75/1.14  useeqfact =         1
% 0.75/1.14  usefactor =         1
% 0.75/1.14  usesimpsplitting =  0
% 0.75/1.14  usesimpdemod =      5
% 0.75/1.14  usesimpres =        3
% 0.75/1.14  
% 0.75/1.14  resimpinuse      =  1000
% 0.75/1.14  resimpclauses =     20000
% 0.75/1.14  substype =          eqrewr
% 0.75/1.14  backwardsubs =      1
% 0.75/1.14  selectoldest =      5
% 0.75/1.14  
% 0.75/1.14  litorderings [0] =  split
% 0.75/1.14  litorderings [1] =  extend the termordering, first sorting on arguments
% 0.75/1.14  
% 0.75/1.14  termordering =      kbo
% 0.75/1.14  
% 0.75/1.14  litapriori =        0
% 0.75/1.14  termapriori =       1
% 0.75/1.14  litaposteriori =    0
% 0.75/1.14  termaposteriori =   0
% 0.75/1.14  demodaposteriori =  0
% 0.75/1.14  ordereqreflfact =   0
% 0.75/1.14  
% 0.75/1.14  litselect =         negord
% 0.75/1.14  
% 0.75/1.14  maxweight =         15
% 0.75/1.14  maxdepth =          30000
% 0.75/1.14  maxlength =         115
% 0.75/1.14  maxnrvars =         195
% 0.75/1.14  excuselevel =       1
% 0.75/1.14  increasemaxweight = 1
% 0.75/1.14  
% 0.75/1.14  maxselected =       10000000
% 0.75/1.14  maxnrclauses =      10000000
% 0.75/1.14  
% 0.75/1.14  showgenerated =    0
% 0.75/1.14  showkept =         0
% 0.75/1.14  showselected =     0
% 0.75/1.14  showdeleted =      0
% 0.75/1.14  showresimp =       1
% 0.75/1.14  showstatus =       2000
% 0.75/1.14  
% 0.75/1.14  prologoutput =     0
% 0.75/1.14  nrgoals =          5000000
% 0.75/1.14  totalproof =       1
% 0.75/1.14  
% 0.75/1.14  Symbols occurring in the translation:
% 0.75/1.14  
% 0.75/1.14  {}  [0, 0]      (w:1, o:2, a:1, s:1, b:0), 
% 0.75/1.14  .  [1, 2]      (w:1, o:20, a:1, s:1, b:0), 
% 0.75/1.14  !  [4, 1]      (w:0, o:14, a:1, s:1, b:0), 
% 0.75/1.14  =  [13, 2]      (w:1, o:0, a:0, s:1, b:0), 
% 0.75/1.14  ==>  [14, 2]      (w:1, o:0, a:0, s:1, b:0), 
% 0.75/1.14  addition  [37, 2]      (w:1, o:44, a:1, s:1, b:0), 
% 0.75/1.14  zero  [39, 0]      (w:1, o:9, a:1, s:1, b:0), 
% 0.75/1.14  multiplication  [40, 2]      (w:1, o:46, a:1, s:1, b:0), 
% 0.75/1.14  one  [41, 0]      (w:1, o:10, a:1, s:1, b:0), 
% 0.75/1.14  leq  [42, 2]      (w:1, o:45, a:1, s:1, b:0), 
% 0.75/1.14  domain  [44, 1]      (w:1, o:19, a:1, s:1, b:0), 
% 0.75/1.14  skol1  [46, 0]      (w:1, o:13, a:1, s:1, b:1).
% 0.75/1.14  
% 0.75/1.14  
% 0.75/1.14  Starting Search:
% 0.75/1.14  
% 0.75/1.14  
% 0.75/1.14  Bliksems!, er is een bewijs:
% 0.75/1.14  % SZS status Theorem
% 0.75/1.14  % SZS output start Refutation
% 0.75/1.14  
% 0.75/1.14  (3) {G0,W5,D3,L1,V1,M1} I { addition( X, X ) ==> X }.
% 0.75/1.14  (18) {G1,W0,D0,L0,V0,M0} I;d(3);q {  }.
% 0.75/1.14  
% 0.75/1.14  
% 0.75/1.14  % SZS output end Refutation
% 0.75/1.14  found a proof!
% 0.75/1.14  
% 0.75/1.14  
% 0.75/1.14  Unprocessed initial clauses:
% 0.75/1.14  
% 0.75/1.14  (20) {G0,W7,D3,L1,V2,M1}  { addition( X, Y ) = addition( Y, X ) }.
% 0.75/1.14  (21) {G0,W11,D4,L1,V3,M1}  { addition( Z, addition( Y, X ) ) = addition( 
% 0.75/1.14    addition( Z, Y ), X ) }.
% 0.75/1.14  (22) {G0,W5,D3,L1,V1,M1}  { addition( X, zero ) = X }.
% 0.75/1.14  (23) {G0,W5,D3,L1,V1,M1}  { addition( X, X ) = X }.
% 0.75/1.14  (24) {G0,W11,D4,L1,V3,M1}  { multiplication( X, multiplication( Y, Z ) ) = 
% 0.75/1.14    multiplication( multiplication( X, Y ), Z ) }.
% 0.75/1.14  (25) {G0,W5,D3,L1,V1,M1}  { multiplication( X, one ) = X }.
% 0.75/1.14  (26) {G0,W5,D3,L1,V1,M1}  { multiplication( one, X ) = X }.
% 0.75/1.14  (27) {G0,W13,D4,L1,V3,M1}  { multiplication( X, addition( Y, Z ) ) = 
% 0.75/1.14    addition( multiplication( X, Y ), multiplication( X, Z ) ) }.
% 0.75/1.14  (28) {G0,W13,D4,L1,V3,M1}  { multiplication( addition( X, Y ), Z ) = 
% 0.75/1.14    addition( multiplication( X, Z ), multiplication( Y, Z ) ) }.
% 0.75/1.14  (29) {G0,W5,D3,L1,V1,M1}  { multiplication( X, zero ) = zero }.
% 0.75/1.14  (30) {G0,W5,D3,L1,V1,M1}  { multiplication( zero, X ) = zero }.
% 0.75/1.14  (31) {G0,W8,D3,L2,V2,M2}  { ! leq( X, Y ), addition( X, Y ) = Y }.
% 0.75/1.14  (32) {G0,W8,D3,L2,V2,M2}  { ! addition( X, Y ) = Y, leq( X, Y ) }.
% 0.75/1.14  (33) {G0,W11,D5,L1,V1,M1}  { addition( X, multiplication( domain( X ), X )
% 0.75/1.14     ) = multiplication( domain( X ), X ) }.
% 0.75/1.14  (34) {G0,W10,D5,L1,V2,M1}  { domain( multiplication( X, Y ) ) = domain( 
% 0.75/1.14    multiplication( X, domain( Y ) ) ) }.
% 0.75/1.14  (35) {G0,W6,D4,L1,V1,M1}  { addition( domain( X ), one ) = one }.
% 0.75/1.14  (36) {G0,W4,D3,L1,V0,M1}  { domain( zero ) = zero }.
% 0.75/1.14  (37) {G0,W10,D4,L1,V2,M1}  { domain( addition( X, Y ) ) = addition( domain
% 0.75/1.14    ( X ), domain( Y ) ) }.
% 0.75/1.14  (38) {G0,W5,D3,L1,V0,M1}  { ! addition( skol1, skol1 ) = skol1 }.
% 0.75/1.14  
% 0.75/1.14  
% 0.75/1.14  Total Proof:
% 0.75/1.14  
% 0.75/1.14  subsumption: (3) {G0,W5,D3,L1,V1,M1} I { addition( X, X ) ==> X }.
% 0.75/1.14  parent0: (23) {G0,W5,D3,L1,V1,M1}  { addition( X, X ) = X }.
% 0.75/1.14  substitution0:
% 0.75/1.14     X := X
% 0.75/1.14  end
% 0.75/1.14  permutation0:
% 0.75/1.14     0 ==> 0
% 0.75/1.14  end
% 0.75/1.14  
% 0.75/1.14  paramod: (81) {G1,W3,D2,L1,V0,M1}  { ! skol1 = skol1 }.
% 0.75/1.14  parent0[0]: (3) {G0,W5,D3,L1,V1,M1} I { addition( X, X ) ==> X }.
% 0.75/1.14  parent1[0; 2]: (38) {G0,W5,D3,L1,V0,M1}  { ! addition( skol1, skol1 ) = 
% 0.75/1.14    skol1 }.
% 0.75/1.14  substitution0:
% 0.75/1.14     X := skol1
% 0.75/1.14  end
% 0.75/1.14  substitution1:
% 0.75/1.14  end
% 0.75/1.14  
% 0.75/1.14  eqrefl: (82) {G0,W0,D0,L0,V0,M0}  {  }.
% 0.75/1.14  parent0[0]: (81) {G1,W3,D2,L1,V0,M1}  { ! skol1 = skol1 }.
% 0.75/1.14  substitution0:
% 0.75/1.14  end
% 0.75/1.14  
% 0.75/1.14  subsumption: (18) {G1,W0,D0,L0,V0,M0} I;d(3);q {  }.
% 0.75/1.14  parent0: (82) {G0,W0,D0,L0,V0,M0}  {  }.
% 0.75/1.14  substitution0:
% 0.75/1.14  end
% 0.75/1.14  permutation0:
% 0.75/1.14  end
% 0.75/1.14  
% 0.75/1.14  Proof check complete!
% 0.75/1.14  
% 0.75/1.14  Memory use:
% 0.75/1.14  
% 0.75/1.14  space for terms:        534
% 0.75/1.14  space for clauses:      1727
% 0.75/1.14  
% 0.75/1.14  
% 0.75/1.14  clauses generated:      19
% 0.75/1.14  clauses kept:           19
% 0.75/1.14  clauses selected:       0
% 0.75/1.14  clauses deleted:        0
% 0.75/1.14  clauses inuse deleted:  0
% 0.75/1.14  
% 0.75/1.14  subsentry:          132
% 0.75/1.14  literals s-matched: 49
% 0.75/1.14  literals matched:   49
% 0.75/1.14  full subsumption:   0
% 0.75/1.14  
% 0.75/1.14  checksum:           -1072595084
% 0.75/1.14  
% 0.75/1.14  
% 0.75/1.14  Bliksem ended
%------------------------------------------------------------------------------