TSTP Solution File: ITP209_2 by Duper---1.0
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% File : Duper---1.0
% Problem : ITP209_2 : TPTP v8.1.2. Released v8.0.0.
% Transfm : none
% Format : tptp:raw
% Command : duper %s
% Computer : n008.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 300s
% DateTime : Thu Aug 31 03:39:19 EDT 2023
% Result : Theorem 3.83s 4.01s
% Output : Proof 3.83s
% Verified :
% SZS Type : -
% Comments :
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.12 % Problem : ITP209_2 : TPTP v8.1.2. Released v8.0.0.
% 0.00/0.13 % Command : duper %s
% 0.14/0.35 % Computer : n008.cluster.edu
% 0.14/0.35 % Model : x86_64 x86_64
% 0.14/0.35 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.14/0.35 % Memory : 8042.1875MB
% 0.14/0.35 % OS : Linux 3.10.0-693.el7.x86_64
% 0.14/0.35 % CPULimit : 300
% 0.14/0.35 % WCLimit : 300
% 0.14/0.35 % DateTime : Sun Aug 27 11:20:02 EDT 2023
% 0.14/0.35 % CPUTime :
% 3.83/4.01 SZS status Theorem for theBenchmark.p
% 3.83/4.01 SZS output start Proof for theBenchmark.p
% 3.83/4.01 Clause #1 (by assumption #[]): Eq (∀ (A2 B2 : a), Eq (aa a a (aa a (fun a a) f A2) B2) (aa a a (aa a (fun a a) f B2) A2)) True
% 3.83/4.01 Clause #2 (by assumption #[]): Eq
% 3.83/4.01 (∀ (A2 B2 C : a),
% 3.83/4.01 Eq (aa a a (aa a (fun a a) f A2) (aa a a (aa a (fun a a) f B2) C))
% 3.83/4.01 (aa a a (aa a (fun a a) f B2) (aa a a (aa a (fun a a) f A2) C)))
% 3.83/4.01 True
% 3.83/4.01 Clause #14 (by assumption #[]): Eq
% 3.83/4.01 (Not
% 3.83/4.01 (Eq (aa a a (aa a (fun a a) f (aa a a (aa a (fun a a) f a2) b)) c)
% 3.83/4.01 (aa a a (aa a (fun a a) f (aa a a (aa a (fun a a) f a2) c)) b)))
% 3.83/4.01 True
% 3.83/4.01 Clause #39 (by clausification #[1]): ∀ (a_1 : a), Eq (∀ (B2 : a), Eq (aa a a (aa a (fun a a) f a_1) B2) (aa a a (aa a (fun a a) f B2) a_1)) True
% 3.83/4.01 Clause #40 (by clausification #[39]): ∀ (a_1 a_2 : a), Eq (Eq (aa a a (aa a (fun a a) f a_1) a_2) (aa a a (aa a (fun a a) f a_2) a_1)) True
% 3.83/4.01 Clause #41 (by clausification #[40]): ∀ (a_1 a_2 : a), Eq (aa a a (aa a (fun a a) f a_1) a_2) (aa a a (aa a (fun a a) f a_2) a_1)
% 3.83/4.01 Clause #54 (by clausification #[14]): Eq
% 3.83/4.01 (Eq (aa a a (aa a (fun a a) f (aa a a (aa a (fun a a) f a2) b)) c)
% 3.83/4.01 (aa a a (aa a (fun a a) f (aa a a (aa a (fun a a) f a2) c)) b))
% 3.83/4.01 False
% 3.83/4.01 Clause #55 (by clausification #[54]): Ne (aa a a (aa a (fun a a) f (aa a a (aa a (fun a a) f a2) b)) c)
% 3.83/4.01 (aa a a (aa a (fun a a) f (aa a a (aa a (fun a a) f a2) c)) b)
% 3.83/4.01 Clause #56 (by forward demodulation #[55, 41]): Ne (aa a a (aa a (fun a a) f c) (aa a a (aa a (fun a a) f a2) b))
% 3.83/4.01 (aa a a (aa a (fun a a) f (aa a a (aa a (fun a a) f a2) c)) b)
% 3.83/4.01 Clause #57 (by forward demodulation #[56, 41]): Ne (aa a a (aa a (fun a a) f c) (aa a a (aa a (fun a a) f b) a2))
% 3.83/4.01 (aa a a (aa a (fun a a) f (aa a a (aa a (fun a a) f a2) c)) b)
% 3.83/4.01 Clause #58 (by forward demodulation #[57, 41]): Ne (aa a a (aa a (fun a a) f c) (aa a a (aa a (fun a a) f b) a2))
% 3.83/4.01 (aa a a (aa a (fun a a) f b) (aa a a (aa a (fun a a) f a2) c))
% 3.83/4.01 Clause #59 (by forward demodulation #[58, 41]): Ne (aa a a (aa a (fun a a) f c) (aa a a (aa a (fun a a) f b) a2))
% 3.83/4.01 (aa a a (aa a (fun a a) f b) (aa a a (aa a (fun a a) f c) a2))
% 3.83/4.01 Clause #68 (by clausification #[2]): ∀ (a_1 : a),
% 3.83/4.01 Eq
% 3.83/4.01 (∀ (B2 C : a),
% 3.83/4.01 Eq (aa a a (aa a (fun a a) f a_1) (aa a a (aa a (fun a a) f B2) C))
% 3.83/4.01 (aa a a (aa a (fun a a) f B2) (aa a a (aa a (fun a a) f a_1) C)))
% 3.83/4.01 True
% 3.83/4.01 Clause #69 (by clausification #[68]): ∀ (a_1 a_2 : a),
% 3.83/4.01 Eq
% 3.83/4.01 (∀ (C : a),
% 3.83/4.01 Eq (aa a a (aa a (fun a a) f a_1) (aa a a (aa a (fun a a) f a_2) C))
% 3.83/4.01 (aa a a (aa a (fun a a) f a_2) (aa a a (aa a (fun a a) f a_1) C)))
% 3.83/4.01 True
% 3.83/4.01 Clause #70 (by clausification #[69]): ∀ (a_1 a_2 a_3 : a),
% 3.83/4.01 Eq
% 3.83/4.01 (Eq (aa a a (aa a (fun a a) f a_1) (aa a a (aa a (fun a a) f a_2) a_3))
% 3.83/4.01 (aa a a (aa a (fun a a) f a_2) (aa a a (aa a (fun a a) f a_1) a_3)))
% 3.83/4.01 True
% 3.83/4.01 Clause #71 (by clausification #[70]): ∀ (a_1 a_2 a_3 : a),
% 3.83/4.01 Eq (aa a a (aa a (fun a a) f a_1) (aa a a (aa a (fun a a) f a_2) a_3))
% 3.83/4.01 (aa a a (aa a (fun a a) f a_2) (aa a a (aa a (fun a a) f a_1) a_3))
% 3.83/4.01 Clause #72 (by backward contextual literal cutting #[71, 59]): False
% 3.83/4.01 SZS output end Proof for theBenchmark.p
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