TSTP Solution File: ITP209^1 by Duper---1.0

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% File     : Duper---1.0
% Problem  : ITP209^1 : TPTP v8.1.2. Released v8.1.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : duper %s

% Computer : n004.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Thu Aug 31 03:39:19 EDT 2023

% Result   : Theorem 3.58s 3.82s
% Output   : Proof 3.58s
% Verified : 
% SZS Type : -

% Comments : 
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.13  % Problem    : ITP209^1 : TPTP v8.1.2. Released v8.1.0.
% 0.14/0.14  % Command    : duper %s
% 0.14/0.35  % Computer : n004.cluster.edu
% 0.14/0.35  % Model    : x86_64 x86_64
% 0.14/0.35  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.14/0.35  % Memory   : 8042.1875MB
% 0.14/0.35  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.14/0.35  % CPULimit   : 300
% 0.14/0.35  % WCLimit    : 300
% 0.14/0.35  % DateTime   : Sun Aug 27 11:33:52 EDT 2023
% 0.14/0.36  % CPUTime    : 
% 3.58/3.82  SZS status Theorem for theBenchmark.p
% 3.58/3.82  SZS output start Proof for theBenchmark.p
% 3.58/3.82  Clause #1 (by assumption #[]): Eq (∀ (A B : a), Eq (f A B) (f B A)) True
% 3.58/3.82  Clause #2 (by assumption #[]): Eq (∀ (A B C : a), Eq (f A (f B C)) (f B (f A C))) True
% 3.58/3.82  Clause #10 (by assumption #[]): Eq (Not (Eq (f (f a2 b) c) (f (f a2 c) b))) True
% 3.58/3.82  Clause #37 (by clausification #[1]): ∀ (a_1 : a), Eq (∀ (B : a), Eq (f a_1 B) (f B a_1)) True
% 3.58/3.82  Clause #38 (by clausification #[37]): ∀ (a_1 a_2 : a), Eq (Eq (f a_1 a_2) (f a_2 a_1)) True
% 3.58/3.82  Clause #39 (by clausification #[38]): ∀ (a_1 a_2 : a), Eq (f a_1 a_2) (f a_2 a_1)
% 3.58/3.82  Clause #57 (by clausification #[10]): Eq (Eq (f (f a2 b) c) (f (f a2 c) b)) False
% 3.58/3.82  Clause #58 (by clausification #[57]): Ne (f (f a2 b) c) (f (f a2 c) b)
% 3.58/3.82  Clause #59 (by forward demodulation #[58, 39]): Ne (f c (f a2 b)) (f (f a2 c) b)
% 3.58/3.82  Clause #60 (by forward demodulation #[59, 39]): Ne (f c (f b a2)) (f (f a2 c) b)
% 3.58/3.82  Clause #61 (by forward demodulation #[60, 39]): Ne (f c (f b a2)) (f b (f a2 c))
% 3.58/3.82  Clause #62 (by forward demodulation #[61, 39]): Ne (f c (f b a2)) (f b (f c a2))
% 3.58/3.82  Clause #63 (by clausification #[2]): ∀ (a_1 : a), Eq (∀ (B C : a), Eq (f a_1 (f B C)) (f B (f a_1 C))) True
% 3.58/3.82  Clause #64 (by clausification #[63]): ∀ (a_1 a_2 : a), Eq (∀ (C : a), Eq (f a_1 (f a_2 C)) (f a_2 (f a_1 C))) True
% 3.58/3.82  Clause #65 (by clausification #[64]): ∀ (a_1 a_2 a_3 : a), Eq (Eq (f a_1 (f a_2 a_3)) (f a_2 (f a_1 a_3))) True
% 3.58/3.82  Clause #66 (by clausification #[65]): ∀ (a_1 a_2 a_3 : a), Eq (f a_1 (f a_2 a_3)) (f a_2 (f a_1 a_3))
% 3.58/3.82  Clause #67 (by backward contextual literal cutting #[66, 62]): False
% 3.58/3.82  SZS output end Proof for theBenchmark.p
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