TSTP Solution File: ITP128^2 by Duper---1.0

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%------------------------------------------------------------------------------
% File     : Duper---1.0
% Problem  : ITP128^2 : TPTP v8.1.2. Released v7.5.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : duper %s

% Computer : n015.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Thu Aug 31 03:38:53 EDT 2023

% Result   : Theorem 4.42s 4.62s
% Output   : Proof 4.42s
% Verified : 
% SZS Type : -

% Comments : 
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.14  % Problem    : ITP128^2 : TPTP v8.1.2. Released v7.5.0.
% 0.00/0.15  % Command    : duper %s
% 0.16/0.36  % Computer : n015.cluster.edu
% 0.16/0.36  % Model    : x86_64 x86_64
% 0.16/0.36  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.16/0.36  % Memory   : 8042.1875MB
% 0.16/0.36  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.16/0.36  % CPULimit   : 300
% 0.16/0.36  % WCLimit    : 300
% 0.16/0.36  % DateTime   : Sun Aug 27 16:48:54 EDT 2023
% 0.16/0.36  % CPUTime    : 
% 4.42/4.62  SZS status Theorem for theBenchmark.p
% 4.42/4.62  SZS output start Proof for theBenchmark.p
% 4.42/4.62  Clause #0 (by assumption #[]): Eq (finite100568337ommute a c f1) True
% 4.42/4.62  Clause #276 (by assumption #[]): Eq (Not (finite100568337ommute a c f1)) True
% 4.42/4.62  Clause #411 (by clausification #[276]): Eq (finite100568337ommute a c f1) False
% 4.42/4.62  Clause #412 (by superposition #[411, 0]): Eq False True
% 4.42/4.62  Clause #413 (by clausification #[412]): False
% 4.42/4.62  SZS output end Proof for theBenchmark.p
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