TSTP Solution File: ITP128^2 by Duper---1.0
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%------------------------------------------------------------------------------
% File : Duper---1.0
% Problem : ITP128^2 : TPTP v8.1.2. Released v7.5.0.
% Transfm : none
% Format : tptp:raw
% Command : duper %s
% Computer : n015.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 300s
% DateTime : Thu Aug 31 03:38:53 EDT 2023
% Result : Theorem 4.42s 4.62s
% Output : Proof 4.42s
% Verified :
% SZS Type : -
% Comments :
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.14 % Problem : ITP128^2 : TPTP v8.1.2. Released v7.5.0.
% 0.00/0.15 % Command : duper %s
% 0.16/0.36 % Computer : n015.cluster.edu
% 0.16/0.36 % Model : x86_64 x86_64
% 0.16/0.36 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.16/0.36 % Memory : 8042.1875MB
% 0.16/0.36 % OS : Linux 3.10.0-693.el7.x86_64
% 0.16/0.36 % CPULimit : 300
% 0.16/0.36 % WCLimit : 300
% 0.16/0.36 % DateTime : Sun Aug 27 16:48:54 EDT 2023
% 0.16/0.36 % CPUTime :
% 4.42/4.62 SZS status Theorem for theBenchmark.p
% 4.42/4.62 SZS output start Proof for theBenchmark.p
% 4.42/4.62 Clause #0 (by assumption #[]): Eq (finite100568337ommute a c f1) True
% 4.42/4.62 Clause #276 (by assumption #[]): Eq (Not (finite100568337ommute a c f1)) True
% 4.42/4.62 Clause #411 (by clausification #[276]): Eq (finite100568337ommute a c f1) False
% 4.42/4.62 Clause #412 (by superposition #[411, 0]): Eq False True
% 4.42/4.62 Clause #413 (by clausification #[412]): False
% 4.42/4.62 SZS output end Proof for theBenchmark.p
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