TSTP Solution File: ITP033^2 by Duper---1.0

View Problem - Process Solution

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% File     : Duper---1.0
% Problem  : ITP033^2 : TPTP v8.1.2. Released v7.5.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : duper %s

% Computer : n029.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Thu Aug 31 03:38:26 EDT 2023

% Result   : Theorem 7.38s 7.58s
% Output   : Proof 7.38s
% Verified : 
% SZS Type : -

% Comments : 
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.10  % Problem    : ITP033^2 : TPTP v8.1.2. Released v7.5.0.
% 0.00/0.11  % Command    : duper %s
% 0.10/0.31  % Computer : n029.cluster.edu
% 0.10/0.31  % Model    : x86_64 x86_64
% 0.10/0.31  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.10/0.31  % Memory   : 8042.1875MB
% 0.10/0.31  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.10/0.31  % CPULimit   : 300
% 0.10/0.31  % WCLimit    : 300
% 0.10/0.31  % DateTime   : Sun Aug 27 13:09:25 EDT 2023
% 0.10/0.31  % CPUTime    : 
% 7.38/7.58  SZS status Theorem for theBenchmark.p
% 7.38/7.58  SZS output start Proof for theBenchmark.p
% 7.38/7.58  Clause #1 (by assumption #[]): Eq (binary1610619414edTree a h (binary210054475elle_T a t1 x t2)) True
% 7.38/7.58  Clause #3 (by assumption #[]): Eq
% 7.38/7.58    (∀ (A : Type) (H : A → int) (T1 : binary1291135688e_Tree A) (X : A) (T2 : binary1291135688e_Tree A),
% 7.38/7.58      binary1610619414edTree A H (binary210054475elle_T A T1 X T2) → binary1610619414edTree A H T1)
% 7.38/7.58    True
% 7.38/7.58  Clause #257 (by assumption #[]): Eq (Not (binary1610619414edTree a h t1)) True
% 7.38/7.58  Clause #265 (by clausification #[257]): Eq (binary1610619414edTree a h t1) False
% 7.38/7.58  Clause #271 (by clausification #[3]): ∀ (a : Type),
% 7.38/7.58    Eq
% 7.38/7.58      (∀ (H : a → int) (T1 : binary1291135688e_Tree a) (X : a) (T2 : binary1291135688e_Tree a),
% 7.38/7.58        binary1610619414edTree a H (binary210054475elle_T a T1 X T2) → binary1610619414edTree a H T1)
% 7.38/7.58      True
% 7.38/7.58  Clause #272 (by clausification #[271]): ∀ (a : Type) (a_1 : a → int),
% 7.38/7.58    Eq
% 7.38/7.58      (∀ (T1 : binary1291135688e_Tree a) (X : a) (T2 : binary1291135688e_Tree a),
% 7.38/7.58        binary1610619414edTree a a_1 (binary210054475elle_T a T1 X T2) → binary1610619414edTree a a_1 T1)
% 7.38/7.58      True
% 7.38/7.58  Clause #273 (by clausification #[272]): ∀ (a : Type) (a_1 : a → int) (a_2 : binary1291135688e_Tree a),
% 7.38/7.58    Eq
% 7.38/7.58      (∀ (X : a) (T2 : binary1291135688e_Tree a),
% 7.38/7.58        binary1610619414edTree a a_1 (binary210054475elle_T a a_2 X T2) → binary1610619414edTree a a_1 a_2)
% 7.38/7.58      True
% 7.38/7.58  Clause #274 (by clausification #[273]): ∀ (a : Type) (a_1 : a → int) (a_2 : binary1291135688e_Tree a) (a_3 : a),
% 7.38/7.58    Eq
% 7.38/7.58      (∀ (T2 : binary1291135688e_Tree a),
% 7.38/7.58        binary1610619414edTree a a_1 (binary210054475elle_T a a_2 a_3 T2) → binary1610619414edTree a a_1 a_2)
% 7.38/7.58      True
% 7.38/7.58  Clause #275 (by clausification #[274]): ∀ (a : Type) (a_1 : a → int) (a_2 : binary1291135688e_Tree a) (a_3 : a) (a_4 : binary1291135688e_Tree a),
% 7.38/7.58    Eq (binary1610619414edTree a a_1 (binary210054475elle_T a a_2 a_3 a_4) → binary1610619414edTree a a_1 a_2) True
% 7.38/7.58  Clause #276 (by clausification #[275]): ∀ (a : Type) (a_1 : a → int) (a_2 : binary1291135688e_Tree a) (a_3 : a) (a_4 : binary1291135688e_Tree a),
% 7.38/7.58    Or (Eq (binary1610619414edTree a a_1 (binary210054475elle_T a a_2 a_3 a_4)) False)
% 7.38/7.58      (Eq (binary1610619414edTree a a_1 a_2) True)
% 7.38/7.58  Clause #277 (by superposition #[276, 1]): Or (Eq (binary1610619414edTree a (fun x => h x) t1) True) (Eq False True)
% 7.38/7.58  Clause #605 (by betaEtaReduce #[277]): Or (Eq (binary1610619414edTree a h t1) True) (Eq False True)
% 7.38/7.58  Clause #606 (by clausification #[605]): Eq (binary1610619414edTree a h t1) True
% 7.38/7.58  Clause #607 (by superposition #[606, 265]): Eq True False
% 7.38/7.58  Clause #612 (by clausification #[607]): False
% 7.38/7.58  SZS output end Proof for theBenchmark.p
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