%------------------------------------------------------------------------------
% File     : Twee---2.4.2
% Problem  : ITP001_2 : TPTP v8.1.2. Bugfixed v7.5.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : parallel-twee %s --tstp --conditional-encoding if --smaller --drop-non-horn --give-up-on-saturation --explain-encoding --formal-proof

% Computer : n023.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Thu Aug 31 04:15:36 EDT 2023

% Result   : Timeout 0.47s 300.04s
% Output   : None 
% Verified : 
% SZS Type : -

% Comments : 
%------------------------------------------------------------------------------
%----No solution output by system
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.11/0.12  % Problem  : ITP001_2 : TPTP v8.1.2. Bugfixed v7.5.0.
% 0.11/0.13  % Command  : parallel-twee %s --tstp --conditional-encoding if --smaller --drop-non-horn --give-up-on-saturation --explain-encoding --formal-proof
% 0.13/0.34  % Computer : n023.cluster.edu
% 0.13/0.34  % Model    : x86_64 x86_64
% 0.13/0.34  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.34  % Memory   : 8042.1875MB
% 0.13/0.34  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.13/0.34  % CPULimit : 300
% 0.13/0.34  % WCLimit  : 300
% 0.13/0.34  % DateTime : Sun Aug 27 13:57:26 EDT 2023
% 0.13/0.34  % CPUTime  : 
% 0.13/0.40  TThe problem contains the following clause, which isT nhote  ap runobilte emq ucaolnittayi:n
% 0.13/0.40  s the following clause,T whhei cphr iobsl enomt  cao nutnaiitn se qtuTahlehi tefy o:plr
% 0.13/0.40  loobwlienmg  ccolantusaei,n sw htichhe  ifso lnlootw ian gu ncilta ueqsue,a lwihtiy:ch
% 0.13/0.40   is not a unit equality:
% 0.13/0.40  hThe problem contains the following clause, which is not a unit equality:
% 0.13/0.40  e problem conThe problem contains the following clause, which is not a unit equality:
% 0.13/0.40  tains the following clause, which is not a unit equality:
% 0.13/0.40  The problem contains the following clause, which is not a unit equality:
% 0.13/0.41    cnf  c nf(types1,( types1, aaxiom, ~mem(X2, X) | mem('to_$i'(X2), X)).
% 0.13/0.41  
% 0.13/0.41  Twee only han dl esc nufni(tt yeqpueasl1,x axiom, ~mem (Xc2n,f (X ty pec)sn1 f|, (mteymp(e'st o1a_,x$iio'm(,X2 ) ~,am xeXm)()X.2
% 0.13/0.41  , 
% 0.13/0.41  XT)w e|e  omnelmy (h'antdol_e$si 'u(nXi2t) e,q uXa)l)it.y 
% 0.13/0.41  pr
% 0.13/0.41  obTlewmese. 
% 0.13/0.41  only handles unit equality problems.
% 0.13/0.41  iity problems.
% 0.13/0.41  om, ~me imo(mX,2,  ~Xm)e m|(X 2m,e m(X)'t o|_ $mie'm(X(2')t,o_ $Xi)')(.X
% 0.13/0.41  2),
% 0.13/0.41   TXw)e)e .on
% 0.13/0.41  ly
% 0.13/0.41   hTawnedel eosn luyn ihta nedqlueasl iutnyi tp reoqbulaelmist.y
% 0.13/0.41   problems.
% 0.13/0.41   cnf(types1, axiom, ~mem(X2, X) | m  cnf(types1,e axiom, ~mem(X2, X) | mem('to_$i'(X2), X)).
% 0.13/0.41  
% 0.13/0.41  Twee only handles unit equality problems.
% 0.13/0.41  m('to_$i'(X2), X)).
% 0.13/0.41  
% 0.13/0.41  Twee only handles unit equality problems.
% 0.20/0.41    cnf(types1, axiom, ~mem(X2, X) | mem('to_$i2'(X2), X)).
% 0.20/0.41  
% 0.20/0.41  Twee only handles unit equality problems.
% 0.47/300.04  Alarm clock
%------------------------------------------------------------------------------