TSTP Solution File: HWV030-1 by Twee---2.4.2

View Problem - Process Solution

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% File     : Twee---2.4.2
% Problem  : HWV030-1 : TPTP v8.1.2. Released v2.5.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : parallel-twee %s --tstp --conditional-encoding if --smaller --drop-non-horn --give-up-on-saturation --explain-encoding --formal-proof

% Computer : n016.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Thu Aug 31 02:31:39 EDT 2023

% Result   : Unsatisfiable 0.19s 0.42s
% Output   : Proof 0.19s
% Verified : 
% SZS Type : -

% Comments : 
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.03/0.12  % Problem  : HWV030-1 : TPTP v8.1.2. Released v2.5.0.
% 0.03/0.12  % Command  : parallel-twee %s --tstp --conditional-encoding if --smaller --drop-non-horn --give-up-on-saturation --explain-encoding --formal-proof
% 0.12/0.33  % Computer : n016.cluster.edu
% 0.12/0.33  % Model    : x86_64 x86_64
% 0.12/0.33  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.33  % Memory   : 8042.1875MB
% 0.12/0.33  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.12/0.33  % CPULimit : 300
% 0.12/0.33  % WCLimit  : 300
% 0.12/0.33  % DateTime : Tue Aug 29 17:13:46 EDT 2023
% 0.12/0.33  % CPUTime  : 
% 0.19/0.42  Command-line arguments: --kbo-weight0 --lhs-weight 5 --flip-ordering --normalise-queue-percent 10 --cp-renormalise-threshold 10 --goal-heuristic
% 0.19/0.42  
% 0.19/0.42  % SZS status Unsatisfiable
% 0.19/0.42  
% 0.19/0.42  % SZS output start Proof
% 0.19/0.42  Take the following subset of the input axioms:
% 0.19/0.42    fof(axiom_27, axiom, ![X_t_37]: (~p_Reset(X_t_37) | wr_level(plus(X_t_37, n1))=n0)).
% 0.19/0.42    fof(quest_1, negated_conjecture, p_Reset(t_139)).
% 0.19/0.42    fof(quest_2, negated_conjecture, ~gt(fifo_length, wr_level(plus(t_139, n1)))).
% 0.19/0.42    fof(quest_3, negated_conjecture, gt(fifo_length, n0)).
% 0.19/0.42  
% 0.19/0.42  Now clausify the problem and encode Horn clauses using encoding 3 of
% 0.19/0.42  http://www.cse.chalmers.se/~nicsma/papers/horn.pdf.
% 0.19/0.42  We repeatedly replace C & s=t => u=v by the two clauses:
% 0.19/0.42    fresh(y, y, x1...xn) = u
% 0.19/0.42    C => fresh(s, t, x1...xn) = v
% 0.19/0.42  where fresh is a fresh function symbol and x1..xn are the free
% 0.19/0.42  variables of u and v.
% 0.19/0.42  A predicate p(X) is encoded as p(X)=true (this is sound, because the
% 0.19/0.42  input problem has no model of domain size 1).
% 0.19/0.42  
% 0.19/0.42  The encoding turns the above axioms into the following unit equations and goals:
% 0.19/0.42  
% 0.19/0.42  Axiom 1 (quest_3): gt(fifo_length, n0) = true2.
% 0.19/0.42  Axiom 2 (quest_1): p_Reset(t_139) = true2.
% 0.19/0.42  Axiom 3 (axiom_27): fresh8(X, X, Y) = n0.
% 0.19/0.42  Axiom 4 (axiom_27): fresh8(p_Reset(X), true2, X) = wr_level(plus(X, n1)).
% 0.19/0.42  
% 0.19/0.42  Goal 1 (quest_2): gt(fifo_length, wr_level(plus(t_139, n1))) = true2.
% 0.19/0.42  Proof:
% 0.19/0.42    gt(fifo_length, wr_level(plus(t_139, n1)))
% 0.19/0.42  = { by axiom 4 (axiom_27) R->L }
% 0.19/0.42    gt(fifo_length, fresh8(p_Reset(t_139), true2, t_139))
% 0.19/0.42  = { by axiom 2 (quest_1) }
% 0.19/0.42    gt(fifo_length, fresh8(true2, true2, t_139))
% 0.19/0.42  = { by axiom 3 (axiom_27) }
% 0.19/0.42    gt(fifo_length, n0)
% 0.19/0.42  = { by axiom 1 (quest_3) }
% 0.19/0.42    true2
% 0.19/0.42  % SZS output end Proof
% 0.19/0.42  
% 0.19/0.42  RESULT: Unsatisfiable (the axioms are contradictory).
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