TSTP Solution File: HWV011-3 by Twee---2.4.2
View Problem
- Process Solution
%------------------------------------------------------------------------------
% File : Twee---2.4.2
% Problem : HWV011-3 : TPTP v8.1.2. Released v2.5.0.
% Transfm : none
% Format : tptp:raw
% Command : parallel-twee %s --tstp --conditional-encoding if --smaller --drop-non-horn --give-up-on-saturation --explain-encoding --formal-proof
% Computer : n015.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 300s
% DateTime : Thu Aug 31 02:31:33 EDT 2023
% Result : Unsatisfiable 0.20s 0.50s
% Output : Proof 0.20s
% Verified :
% SZS Type : -
% Comments :
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.12 % Problem : HWV011-3 : TPTP v8.1.2. Released v2.5.0.
% 0.00/0.13 % Command : parallel-twee %s --tstp --conditional-encoding if --smaller --drop-non-horn --give-up-on-saturation --explain-encoding --formal-proof
% 0.12/0.34 % Computer : n015.cluster.edu
% 0.12/0.34 % Model : x86_64 x86_64
% 0.12/0.34 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.34 % Memory : 8042.1875MB
% 0.12/0.34 % OS : Linux 3.10.0-693.el7.x86_64
% 0.12/0.34 % CPULimit : 300
% 0.12/0.34 % WCLimit : 300
% 0.12/0.34 % DateTime : Tue Aug 29 15:17:26 EDT 2023
% 0.12/0.34 % CPUTime :
% 0.20/0.50 Command-line arguments: --no-flatten-goal
% 0.20/0.50
% 0.20/0.50 % SZS status Unsatisfiable
% 0.20/0.50
% 0.20/0.50 % SZS output start Proof
% 0.20/0.50 Take the following subset of the input axioms:
% 0.20/0.50 fof(axiom_5, axiom, ![T_0]: fwork_DOTfifo_DOTrtl_DOTlevel_(T_0)=fwork_DOTfifo_DOTrtl_DOTint__level_(T_0)).
% 0.20/0.50 fof(axiom_6, axiom, ![T_1]: (p__pred_(fwork_DOTfifo_DOTrtl_DOTfull_(T_1)) | fwork_DOTfifo_DOTrtl_DOTint__level_(T_1)!=fwork_DOTfifo_DOTrtl_DOTfifo__length_)).
% 0.20/0.50 fof(quest_1, negated_conjecture, fwork_DOTfifo_DOTrtl_DOTlevel_(t_206)=fwork_DOTfifo_DOTrtl_DOTfifo__length_).
% 0.20/0.50 fof(quest_2, negated_conjecture, ~p__pred_(fwork_DOTfifo_DOTrtl_DOTfull_(t_206))).
% 0.20/0.50
% 0.20/0.50 Now clausify the problem and encode Horn clauses using encoding 3 of
% 0.20/0.50 http://www.cse.chalmers.se/~nicsma/papers/horn.pdf.
% 0.20/0.50 We repeatedly replace C & s=t => u=v by the two clauses:
% 0.20/0.50 fresh(y, y, x1...xn) = u
% 0.20/0.50 C => fresh(s, t, x1...xn) = v
% 0.20/0.50 where fresh is a fresh function symbol and x1..xn are the free
% 0.20/0.50 variables of u and v.
% 0.20/0.50 A predicate p(X) is encoded as p(X)=true (this is sound, because the
% 0.20/0.50 input problem has no model of domain size 1).
% 0.20/0.50
% 0.20/0.50 The encoding turns the above axioms into the following unit equations and goals:
% 0.20/0.50
% 0.20/0.50 Axiom 1 (quest_1): fwork_DOTfifo_DOTrtl_DOTlevel_(t_206) = fwork_DOTfifo_DOTrtl_DOTfifo__length_.
% 0.20/0.50 Axiom 2 (axiom_5): fwork_DOTfifo_DOTrtl_DOTlevel_(X) = fwork_DOTfifo_DOTrtl_DOTint__level_(X).
% 0.20/0.50 Axiom 3 (axiom_6): fresh17(X, X, Y) = true2.
% 0.20/0.50 Axiom 4 (axiom_6): fresh17(fwork_DOTfifo_DOTrtl_DOTint__level_(X), fwork_DOTfifo_DOTrtl_DOTfifo__length_, X) = p__pred_(fwork_DOTfifo_DOTrtl_DOTfull_(X)).
% 0.20/0.50
% 0.20/0.50 Goal 1 (quest_2): p__pred_(fwork_DOTfifo_DOTrtl_DOTfull_(t_206)) = true2.
% 0.20/0.50 Proof:
% 0.20/0.50 p__pred_(fwork_DOTfifo_DOTrtl_DOTfull_(t_206))
% 0.20/0.50 = { by axiom 4 (axiom_6) R->L }
% 0.20/0.50 fresh17(fwork_DOTfifo_DOTrtl_DOTint__level_(t_206), fwork_DOTfifo_DOTrtl_DOTfifo__length_, t_206)
% 0.20/0.50 = { by axiom 2 (axiom_5) R->L }
% 0.20/0.50 fresh17(fwork_DOTfifo_DOTrtl_DOTlevel_(t_206), fwork_DOTfifo_DOTrtl_DOTfifo__length_, t_206)
% 0.20/0.50 = { by axiom 1 (quest_1) }
% 0.20/0.50 fresh17(fwork_DOTfifo_DOTrtl_DOTfifo__length_, fwork_DOTfifo_DOTrtl_DOTfifo__length_, t_206)
% 0.20/0.50 = { by axiom 3 (axiom_6) }
% 0.20/0.50 true2
% 0.20/0.50 % SZS output end Proof
% 0.20/0.50
% 0.20/0.50 RESULT: Unsatisfiable (the axioms are contradictory).
%------------------------------------------------------------------------------