TSTP Solution File: HEN003-5 by Bliksem---1.12

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : Bliksem---1.12
% Problem  : HEN003-5 : TPTP v8.1.0. Released v1.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : bliksem %s

% Computer : n015.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 0s
% DateTime : Sat Jul 16 12:47:00 EDT 2022

% Result   : Unsatisfiable 0.75s 1.15s
% Output   : Refutation 0.75s
% Verified : 
% SZS Type : -

% Comments : 
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.06/0.12  % Problem  : HEN003-5 : TPTP v8.1.0. Released v1.0.0.
% 0.06/0.13  % Command  : bliksem %s
% 0.13/0.34  % Computer : n015.cluster.edu
% 0.13/0.34  % Model    : x86_64 x86_64
% 0.13/0.34  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.34  % Memory   : 8042.1875MB
% 0.13/0.34  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.13/0.34  % CPULimit : 300
% 0.13/0.34  % DateTime : Fri Jul  1 14:48:13 EDT 2022
% 0.13/0.34  % CPUTime  : 
% 0.75/1.15  *** allocated 10000 integers for termspace/termends
% 0.75/1.15  *** allocated 10000 integers for clauses
% 0.75/1.15  *** allocated 10000 integers for justifications
% 0.75/1.15  Bliksem 1.12
% 0.75/1.15  
% 0.75/1.15  
% 0.75/1.15  Automatic Strategy Selection
% 0.75/1.15  
% 0.75/1.15  Clauses:
% 0.75/1.15  [
% 0.75/1.15     [ =( divide( divide( X, Y ), X ), zero ) ],
% 0.75/1.15     [ =( divide( divide( divide( X, Y ), divide( Z, Y ) ), divide( divide( X
% 0.75/1.15    , Z ), Y ) ), zero ) ],
% 0.75/1.15     [ =( divide( zero, X ), zero ) ],
% 0.75/1.15     [ ~( =( divide( X, Y ), zero ) ), ~( =( divide( Y, X ), zero ) ), =( X, 
% 0.75/1.15    Y ) ],
% 0.75/1.15     [ =( divide( X, identity ), zero ) ],
% 0.75/1.15     [ ~( =( divide( a, a ), zero ) ) ]
% 0.75/1.15  ] .
% 0.75/1.15  
% 0.75/1.15  
% 0.75/1.15  percentage equality = 1.000000, percentage horn = 1.000000
% 0.75/1.15  This is a pure equality problem
% 0.75/1.15  
% 0.75/1.15  
% 0.75/1.15  
% 0.75/1.15  Options Used:
% 0.75/1.15  
% 0.75/1.15  useres =            1
% 0.75/1.15  useparamod =        1
% 0.75/1.15  useeqrefl =         1
% 0.75/1.15  useeqfact =         1
% 0.75/1.15  usefactor =         1
% 0.75/1.15  usesimpsplitting =  0
% 0.75/1.15  usesimpdemod =      5
% 0.75/1.15  usesimpres =        3
% 0.75/1.15  
% 0.75/1.15  resimpinuse      =  1000
% 0.75/1.15  resimpclauses =     20000
% 0.75/1.15  substype =          eqrewr
% 0.75/1.15  backwardsubs =      1
% 0.75/1.15  selectoldest =      5
% 0.75/1.15  
% 0.75/1.15  litorderings [0] =  split
% 0.75/1.15  litorderings [1] =  extend the termordering, first sorting on arguments
% 0.75/1.15  
% 0.75/1.15  termordering =      kbo
% 0.75/1.15  
% 0.75/1.15  litapriori =        0
% 0.75/1.15  termapriori =       1
% 0.75/1.15  litaposteriori =    0
% 0.75/1.15  termaposteriori =   0
% 0.75/1.15  demodaposteriori =  0
% 0.75/1.15  ordereqreflfact =   0
% 0.75/1.15  
% 0.75/1.15  litselect =         negord
% 0.75/1.15  
% 0.75/1.15  maxweight =         15
% 0.75/1.15  maxdepth =          30000
% 0.75/1.15  maxlength =         115
% 0.75/1.15  maxnrvars =         195
% 0.75/1.15  excuselevel =       1
% 0.75/1.15  increasemaxweight = 1
% 0.75/1.15  
% 0.75/1.15  maxselected =       10000000
% 0.75/1.15  maxnrclauses =      10000000
% 0.75/1.15  
% 0.75/1.15  showgenerated =    0
% 0.75/1.15  showkept =         0
% 0.75/1.15  showselected =     0
% 0.75/1.15  showdeleted =      0
% 0.75/1.15  showresimp =       1
% 0.75/1.15  showstatus =       2000
% 0.75/1.15  
% 0.75/1.15  prologoutput =     1
% 0.75/1.15  nrgoals =          5000000
% 0.75/1.15  totalproof =       1
% 0.75/1.15  
% 0.75/1.15  Symbols occurring in the translation:
% 0.75/1.15  
% 0.75/1.15  {}  [0, 0]      (w:1, o:2, a:1, s:1, b:0), 
% 0.75/1.15  .  [1, 2]      (w:1, o:20, a:1, s:1, b:0), 
% 0.75/1.15  !  [4, 1]      (w:0, o:15, a:1, s:1, b:0), 
% 0.75/1.15  =  [13, 2]      (w:1, o:0, a:0, s:1, b:0), 
% 0.75/1.15  ==>  [14, 2]      (w:1, o:0, a:0, s:1, b:0), 
% 0.75/1.15  divide  [41, 2]      (w:1, o:45, a:1, s:1, b:0), 
% 0.75/1.15  zero  [42, 0]      (w:1, o:11, a:1, s:1, b:0), 
% 0.75/1.15  identity  [44, 0]      (w:1, o:13, a:1, s:1, b:0), 
% 0.75/1.15  a  [45, 0]      (w:1, o:14, a:1, s:1, b:0).
% 0.75/1.15  
% 0.75/1.15  
% 0.75/1.15  Starting Search:
% 0.75/1.15  
% 0.75/1.15  
% 0.75/1.15  Bliksems!, er is een bewijs:
% 0.75/1.15  % SZS status Unsatisfiable
% 0.75/1.15  % SZS output start Refutation
% 0.75/1.15  
% 0.75/1.15  clause( 0, [ =( divide( divide( X, Y ), X ), zero ) ] )
% 0.75/1.15  .
% 0.75/1.15  clause( 1, [ =( divide( divide( divide( X, Y ), divide( Z, Y ) ), divide( 
% 0.75/1.15    divide( X, Z ), Y ) ), zero ) ] )
% 0.75/1.15  .
% 0.75/1.15  clause( 2, [ =( divide( zero, X ), zero ) ] )
% 0.75/1.15  .
% 0.75/1.15  clause( 3, [ ~( =( divide( X, Y ), zero ) ), ~( =( divide( Y, X ), zero ) )
% 0.75/1.15    , =( X, Y ) ] )
% 0.75/1.15  .
% 0.75/1.15  clause( 5, [ ~( =( divide( a, a ), zero ) ) ] )
% 0.75/1.15  .
% 0.75/1.15  clause( 6, [ ~( =( divide( X, divide( X, Y ) ), zero ) ), =( divide( X, Y )
% 0.75/1.15    , X ) ] )
% 0.75/1.15  .
% 0.75/1.15  clause( 11, [ ~( =( X, zero ) ), ~( =( divide( divide( a, a ), X ), zero )
% 0.75/1.15     ), ~( =( divide( X, divide( a, a ) ), zero ) ) ] )
% 0.75/1.15  .
% 0.75/1.15  clause( 17, [ ~( =( divide( divide( divide( X, Y ), Z ), divide( divide( X
% 0.75/1.15    , Z ), divide( Y, Z ) ) ), zero ) ), =( divide( divide( X, Z ), divide( Y
% 0.75/1.15    , Z ) ), divide( divide( X, Y ), Z ) ) ] )
% 0.75/1.15  .
% 0.75/1.15  clause( 180, [ =( divide( divide( X, X ), divide( Y, X ) ), zero ) ] )
% 0.75/1.15  .
% 0.75/1.15  clause( 184, [ =( divide( X, X ), zero ) ] )
% 0.75/1.15  .
% 0.75/1.15  clause( 186, [] )
% 0.75/1.15  .
% 0.75/1.15  
% 0.75/1.15  
% 0.75/1.15  % SZS output end Refutation
% 0.75/1.15  found a proof!
% 0.75/1.15  
% 0.75/1.15  % ABCDEFGHIJKLMNOPQRSTUVWXYZ
% 0.75/1.15  
% 0.75/1.15  initialclauses(
% 0.75/1.15  [ clause( 188, [ =( divide( divide( X, Y ), X ), zero ) ] )
% 0.75/1.15  , clause( 189, [ =( divide( divide( divide( X, Y ), divide( Z, Y ) ), 
% 0.75/1.15    divide( divide( X, Z ), Y ) ), zero ) ] )
% 0.75/1.15  , clause( 190, [ =( divide( zero, X ), zero ) ] )
% 0.75/1.15  , clause( 191, [ ~( =( divide( X, Y ), zero ) ), ~( =( divide( Y, X ), zero
% 0.75/1.15     ) ), =( X, Y ) ] )
% 0.75/1.15  , clause( 192, [ =( divide( X, identity ), zero ) ] )
% 0.75/1.15  , clause( 193, [ ~( =( divide( a, a ), zero ) ) ] )
% 0.75/1.15  ] ).
% 0.75/1.15  
% 0.75/1.15  
% 0.75/1.15  
% 0.75/1.15  subsumption(
% 0.75/1.15  clause( 0, [ =( divide( divide( X, Y ), X ), zero ) ] )
% 0.75/1.15  , clause( 188, [ =( divide( divide( X, Y ), X ), zero ) ] )
% 0.75/1.15  , substitution( 0, [ :=( X, X ), :=( Y, Y )] ), permutation( 0, [ ==>( 0, 0
% 0.75/1.15     )] ) ).
% 0.75/1.15  
% 0.75/1.15  
% 0.75/1.15  subsumption(
% 0.75/1.15  clause( 1, [ =( divide( divide( divide( X, Y ), divide( Z, Y ) ), divide( 
% 0.75/1.15    divide( X, Z ), Y ) ), zero ) ] )
% 0.75/1.15  , clause( 189, [ =( divide( divide( divide( X, Y ), divide( Z, Y ) ), 
% 0.75/1.15    divide( divide( XCputime limit exceeded (core dumped)
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