TSTP Solution File: HEN003-4 by Otter---3.3
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%------------------------------------------------------------------------------
% File : Otter---3.3
% Problem : HEN003-4 : TPTP v8.1.0. Released v1.0.0.
% Transfm : none
% Format : tptp:raw
% Command : otter-tptp-script %s
% Computer : n010.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 300s
% DateTime : Wed Jul 27 12:57:54 EDT 2022
% Result : Unsatisfiable 1.79s 1.97s
% Output : Refutation 1.79s
% Verified :
% SZS Type : Refutation
% Derivation depth : 6
% Number of leaves : 7
% Syntax : Number of clauses : 13 ( 10 unt; 0 nHn; 5 RR)
% Number of literals : 17 ( 7 equ; 5 neg)
% Maximal clause size : 3 ( 1 avg)
% Maximal term depth : 3 ( 1 avg)
% Number of predicates : 3 ( 1 usr; 1 prp; 0-2 aty)
% Number of functors : 3 ( 3 usr; 2 con; 0-2 aty)
% Number of variables : 21 ( 6 sgn)
% Comments :
%------------------------------------------------------------------------------
cnf(1,axiom,
( ~ less_e_qual(A,B)
| divide(A,B) = zero ),
file('HEN003-4.p',unknown),
[] ).
cnf(2,axiom,
( divide(A,B) != zero
| less_e_qual(A,B) ),
file('HEN003-4.p',unknown),
[] ).
cnf(3,axiom,
( ~ less_e_qual(A,B)
| ~ less_e_qual(B,A)
| A = B ),
file('HEN003-4.p',unknown),
[] ).
cnf(4,axiom,
divide(a,a) != zero,
file('HEN003-4.p',unknown),
[] ).
cnf(6,axiom,
less_e_qual(divide(A,B),A),
file('HEN003-4.p',unknown),
[] ).
cnf(7,axiom,
less_e_qual(divide(divide(A,B),divide(C,B)),divide(divide(A,C),B)),
file('HEN003-4.p',unknown),
[] ).
cnf(8,axiom,
less_e_qual(zero,A),
file('HEN003-4.p',unknown),
[] ).
cnf(17,plain,
divide(divide(A,B),A) = zero,
inference(hyper,[status(thm)],[6,1]),
[iquote('hyper,6,1')] ).
cnf(34,plain,
less_e_qual(divide(divide(A,A),divide(B,A)),zero),
inference(para_from,[status(thm),theory(equality)],[17,7]),
[iquote('para_from,16.1.1,7.1.2')] ).
cnf(49,plain,
divide(divide(A,A),divide(B,A)) = zero,
inference(flip,[status(thm),theory(equality)],[inference(hyper,[status(thm)],[34,3,8])]),
[iquote('hyper,34,3,8,flip.1')] ).
cnf(75,plain,
less_e_qual(divide(A,A),divide(B,A)),
inference(hyper,[status(thm)],[49,2]),
[iquote('hyper,49,2')] ).
cnf(85,plain,
divide(A,A) = zero,
inference(flip,[status(thm),theory(equality)],[inference(demod,[status(thm),theory(equality)],[inference(hyper,[status(thm)],[75,3,6]),17])]),
[iquote('hyper,75,3,6,demod,17,flip.1')] ).
cnf(87,plain,
$false,
inference(binary,[status(thm)],[85,4]),
[iquote('binary,85.1,4.1')] ).
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.06/0.11 % Problem : HEN003-4 : TPTP v8.1.0. Released v1.0.0.
% 0.06/0.12 % Command : otter-tptp-script %s
% 0.12/0.32 % Computer : n010.cluster.edu
% 0.12/0.32 % Model : x86_64 x86_64
% 0.12/0.32 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.32 % Memory : 8042.1875MB
% 0.12/0.32 % OS : Linux 3.10.0-693.el7.x86_64
% 0.12/0.32 % CPULimit : 300
% 0.12/0.32 % WCLimit : 300
% 0.12/0.32 % DateTime : Wed Jul 27 08:50:54 EDT 2022
% 0.12/0.32 % CPUTime :
% 1.79/1.97 ----- Otter 3.3f, August 2004 -----
% 1.79/1.97 The process was started by sandbox2 on n010.cluster.edu,
% 1.79/1.97 Wed Jul 27 08:50:55 2022
% 1.79/1.97 The command was "./otter". The process ID is 13822.
% 1.79/1.97
% 1.79/1.97 set(prolog_style_variables).
% 1.79/1.97 set(auto).
% 1.79/1.97 dependent: set(auto1).
% 1.79/1.97 dependent: set(process_input).
% 1.79/1.97 dependent: clear(print_kept).
% 1.79/1.97 dependent: clear(print_new_demod).
% 1.79/1.97 dependent: clear(print_back_demod).
% 1.79/1.97 dependent: clear(print_back_sub).
% 1.79/1.97 dependent: set(control_memory).
% 1.79/1.97 dependent: assign(max_mem, 12000).
% 1.79/1.97 dependent: assign(pick_given_ratio, 4).
% 1.79/1.97 dependent: assign(stats_level, 1).
% 1.79/1.97 dependent: assign(max_seconds, 10800).
% 1.79/1.97 clear(print_given).
% 1.79/1.97
% 1.79/1.97 list(usable).
% 1.79/1.97 0 [] A=A.
% 1.79/1.97 0 [] -less_e_qual(X,Y)|divide(X,Y)=zero.
% 1.79/1.97 0 [] divide(X,Y)!=zero|less_e_qual(X,Y).
% 1.79/1.97 0 [] less_e_qual(divide(X,Y),X).
% 1.79/1.97 0 [] less_e_qual(divide(divide(X,Z),divide(Y,Z)),divide(divide(X,Y),Z)).
% 1.79/1.97 0 [] less_e_qual(zero,X).
% 1.79/1.97 0 [] -less_e_qual(X,Y)| -less_e_qual(Y,X)|X=Y.
% 1.79/1.97 0 [] less_e_qual(X,identity).
% 1.79/1.97 0 [] divide(X,identity)=zero.
% 1.79/1.97 0 [] divide(zero,X)=zero.
% 1.79/1.97 0 [] divide(a,a)!=zero.
% 1.79/1.97 end_of_list.
% 1.79/1.97
% 1.79/1.97 SCAN INPUT: prop=0, horn=1, equality=1, symmetry=0, max_lits=3.
% 1.79/1.97
% 1.79/1.97 This is a Horn set with equality. The strategy will be
% 1.79/1.97 Knuth-Bendix and hyper_res, with positive clauses in
% 1.79/1.97 sos and nonpositive clauses in usable.
% 1.79/1.97
% 1.79/1.97 dependent: set(knuth_bendix).
% 1.79/1.97 dependent: set(anl_eq).
% 1.79/1.97 dependent: set(para_from).
% 1.79/1.97 dependent: set(para_into).
% 1.79/1.97 dependent: clear(para_from_right).
% 1.79/1.97 dependent: clear(para_into_right).
% 1.79/1.97 dependent: set(para_from_vars).
% 1.79/1.97 dependent: set(eq_units_both_ways).
% 1.79/1.97 dependent: set(dynamic_demod_all).
% 1.79/1.97 dependent: set(dynamic_demod).
% 1.79/1.97 dependent: set(order_eq).
% 1.79/1.97 dependent: set(back_demod).
% 1.79/1.97 dependent: set(lrpo).
% 1.79/1.97 dependent: set(hyper_res).
% 1.79/1.97 dependent: clear(order_hyper).
% 1.79/1.97
% 1.79/1.97 ------------> process usable:
% 1.79/1.97 ** KEPT (pick-wt=8): 1 [] -less_e_qual(A,B)|divide(A,B)=zero.
% 1.79/1.97 ** KEPT (pick-wt=8): 2 [] divide(A,B)!=zero|less_e_qual(A,B).
% 1.79/1.97 ** KEPT (pick-wt=9): 3 [] -less_e_qual(A,B)| -less_e_qual(B,A)|A=B.
% 1.79/1.97 ** KEPT (pick-wt=5): 4 [] divide(a,a)!=zero.
% 1.79/1.97
% 1.79/1.97 ------------> process sos:
% 1.79/1.97 ** KEPT (pick-wt=3): 5 [] A=A.
% 1.79/1.97 ** KEPT (pick-wt=5): 6 [] less_e_qual(divide(A,B),A).
% 1.79/1.97 ** KEPT (pick-wt=13): 7 [] less_e_qual(divide(divide(A,B),divide(C,B)),divide(divide(A,C),B)).
% 1.79/1.97 ** KEPT (pick-wt=3): 8 [] less_e_qual(zero,A).
% 1.79/1.97 ** KEPT (pick-wt=3): 9 [] less_e_qual(A,identity).
% 1.79/1.97 ** KEPT (pick-wt=5): 10 [] divide(A,identity)=zero.
% 1.79/1.97 ---> New Demodulator: 11 [new_demod,10] divide(A,identity)=zero.
% 1.79/1.97 ** KEPT (pick-wt=5): 12 [] divide(zero,A)=zero.
% 1.79/1.97 ---> New Demodulator: 13 [new_demod,12] divide(zero,A)=zero.
% 1.79/1.97 Following clause subsumed by 5 during input processing: 0 [copy,5,flip.1] A=A.
% 1.79/1.97 >>>> Starting back demodulation with 11.
% 1.79/1.97 >>>> Starting back demodulation with 13.
% 1.79/1.97
% 1.79/1.97 ======= end of input processing =======
% 1.79/1.97
% 1.79/1.97 =========== start of search ===========
% 1.79/1.97
% 1.79/1.97 -------- PROOF --------
% 1.79/1.97
% 1.79/1.97 ----> UNIT CONFLICT at 0.00 sec ----> 87 [binary,85.1,4.1] $F.
% 1.79/1.97
% 1.79/1.97 Length of proof is 5. Level of proof is 5.
% 1.79/1.97
% 1.79/1.97 ---------------- PROOF ----------------
% 1.79/1.97 % SZS status Unsatisfiable
% 1.79/1.97 % SZS output start Refutation
% See solution above
% 1.79/1.97 ------------ end of proof -------------
% 1.79/1.97
% 1.79/1.97
% 1.79/1.97 Search stopped by max_proofs option.
% 1.79/1.97
% 1.79/1.97
% 1.79/1.97 Search stopped by max_proofs option.
% 1.79/1.97
% 1.79/1.97 ============ end of search ============
% 1.79/1.97
% 1.79/1.97 -------------- statistics -------------
% 1.79/1.97 clauses given 19
% 1.79/1.97 clauses generated 234
% 1.79/1.97 clauses kept 77
% 1.79/1.97 clauses forward subsumed 170
% 1.79/1.97 clauses back subsumed 2
% 1.79/1.97 Kbytes malloced 976
% 1.79/1.97
% 1.79/1.97 ----------- times (seconds) -----------
% 1.79/1.97 user CPU time 0.00 (0 hr, 0 min, 0 sec)
% 1.79/1.97 system CPU time 0.00 (0 hr, 0 min, 0 sec)
% 1.79/1.97 wall-clock time 1 (0 hr, 0 min, 1 sec)
% 1.79/1.97
% 1.79/1.97 That finishes the proof of the theorem.
% 1.79/1.97
% 1.79/1.97 Process 13822 finished Wed Jul 27 08:50:56 2022
% 1.79/1.97 Otter interrupted
% 1.79/1.97 PROOF FOUND
%------------------------------------------------------------------------------