TSTP Solution File: HAL007+1 by Crossbow---0.1

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : Crossbow---0.1
% Problem  : HAL007+1 : TPTP v8.1.0. Released v6.4.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : do_Crossbow---0.1 %s

% Computer : n024.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 600s
% DateTime : Sat Jul 16 12:44:45 EDT 2022

% Result   : Satisfiable 5.19s 5.39s
% Output   : FiniteModel 5.19s
% Verified : 
% SZS Type : -

% Comments : 
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%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.11/0.12  % Problem    : HAL007+1 : TPTP v8.1.0. Released v6.4.0.
% 0.11/0.12  % Command    : do_Crossbow---0.1 %s
% 0.12/0.33  % Computer : n024.cluster.edu
% 0.12/0.33  % Model    : x86_64 x86_64
% 0.12/0.33  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.33  % Memory   : 8042.1875MB
% 0.12/0.33  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.12/0.33  % CPULimit   : 300
% 0.12/0.33  % WCLimit    : 600
% 0.12/0.33  % DateTime   : Tue Jun  7 21:04:04 EDT 2022
% 0.12/0.33  % CPUTime    : 
% 0.12/0.33  /export/starexec/sandbox2/solver/bin
% 0.12/0.34  crossbow.opt
% 0.12/0.34  do_Crossbow---0.1
% 0.12/0.34  eprover
% 0.12/0.34  runsolver
% 0.12/0.34  starexec_run_Crossbow---0.1
% 5.19/5.39  % SZS status Satisfiable for theBenchmark.p
% 5.19/5.39  % SZS output start FiniteModel for theBenchmark.p
% 5.19/5.39  % domain size: 1
% 5.19/5.39  fof(interp, fi_domain, ![X] : X = 0).
% 5.19/5.39  fof(interp, fi_functors, apply(0, 0) = 0).
% 5.19/5.39  fof(interp, fi_predicates, ~commute(0, 0, 0, 0)).
% 5.19/5.39  fof(interp, fi_predicates, ~element(0, 0)).
% 5.19/5.39  fof(interp, fi_functors, esk1_2(0, 0) = 0).
% 5.19/5.39  fof(interp, fi_functors, esk2_2(0, 0) = 0).
% 5.19/5.39  fof(interp, fi_functors, esk3_4(0, 0, 0, 0) = 0).
% 5.19/5.39  fof(interp, fi_functors, esk4_3(0, 0, 0) = 0).
% 5.19/5.39  fof(interp, fi_functors, esk5_6(0, 0, 0, 0, 0, 0) = 0).
% 5.19/5.39  fof(interp, fi_functors, esk6_5(0, 0, 0, 0, 0) = 0).
% 5.19/5.39  fof(interp, fi_functors, esk7_5(0, 0, 0, 0, 0) = 0).
% 5.19/5.39  fof(interp, fi_functors, esk8_5(0, 0, 0, 0, 0) = 0).
% 5.19/5.39  fof(interp, fi_predicates, ~exact(0, 0)).
% 5.19/5.39  fof(interp, fi_predicates, injection(0)).
% 5.19/5.39  fof(interp, fi_predicates, ~morphism(0, 0, 0)).
% 5.19/5.39  fof(interp, fi_functors, subtract(0, 0, 0) = 0).
% 5.19/5.39  fof(interp, fi_predicates, ~surjection(0)).
% 5.19/5.39  fof(interp, fi_functors, zero(0) = 0).
% 5.19/5.39  % SZS output end FiniteModel for theBenchmark.p
% 5.19/5.39  % 0 lemma(s) from E
% 5.19/5.39  % 49 pred(s)
% 5.19/5.39  % 11 func(s)
% 5.19/5.39  % 3 sort(s)
% 5.19/5.39  % 70 clause(s)
% 5.19/5.39  % Instantiating 1 (5023 ms)
% 5.19/5.39  % Solving (5024 ms)
% 5.19/5.39  % 
% 5.19/5.39  % 1 model found (5024 ms)
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