TSTP Solution File: GRP816+1 by DarwinFM---1.4.5

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : DarwinFM---1.4.5
% Problem  : GRP816+1 : TPTP v8.1.0. Released v7.5.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : darwin -fd true -ppp true -pl 0 -to %d -pmtptp true %s

% Computer : n027.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 0s
% DateTime : Sat Jul 16 08:21:35 EDT 2022

% Result   : CounterSatisfiable 105.48s 105.71s
% Output   : FiniteModel 105.55s
% Verified : 
% SZS Type : FiniteModel
%            Domain size           :    2

% Comments : 
%------------------------------------------------------------------------------
fof(interpretation_domain,fi_domain,
    ! [X] :
      ( X = e1
      | X = e2 ) ).

fof(interpretation_domain_distinct,fi_domain,
    e1 != e2 ).

fof(interpretation_terms,fi_functors,
    ( ! [X0,X1,X2,X3] :
        ( a(X0,X1,X2) = X3
      <=> ( ( X3 = e1
            & ~ ( X0 = e1
                & X1 = e1
                & X2 = e1 ) )
          | ( X0 = e1
            & X1 = e1
            & X2 = e1
            & X3 = e2 ) ) )
    & ! [X0,X1,X2] :
        ( b(X0,X1) = X2
      <=> ( ( X0 = e2
            & X2 = e1
            & X1 != e1 )
          | ( X1 = e2
            & X2 = e1
            & X0 != e1 )
          | ( X2 = e1
            & X0 != e1
            & X1 != e1 )
          | ( X1 = e1
            & X2 = e2
            & X0 != e1 )
          | ( X0 = e1
            & X2 = e2
            & X1 != e1 )
          | ( X0 = e1
            & X1 = e1
            & X2 = e1 ) ) )
    & e = e1
    & esk1_0 = e1
    & esk2_0 = e1
    & esk3_0 = e1
    & esk4_0 = e1
    & esk5_0 = e1
    & ! [X0,X1,X2] :
        ( m(X0,X1) = X2
      <=> ( ( X0 = e2
            & X2 = e1
            & X1 != e1 )
          | ( X1 = e2
            & X2 = e1
            & X0 != e1 )
          | ( X2 = e1
            & X0 != e1
            & X1 != e1 )
          | ( X1 = e1
            & X2 = e2
            & X0 != e1 )
          | ( X0 = e1
            & X2 = e2
            & X1 != e1 )
          | ( X0 = e1
            & X1 = e1
            & X2 = e1 ) ) )
    & ! [X0,X1,X2] :
        ( s(X0,X1) = X2
      <=> ( ( X0 = e2
            & X2 = e1
            & X1 != e1 )
          | ( X2 = e1
            & X0 != e1
            & X1 != e1 )
          | ( X1 = e1
            & X2 = e2
            & X0 != e1 )
          | ( X0 = e1
            & X2 = e2
            & X1 != e1 )
          | ( X0 = e1
            & X1 = e1
            & X2 = e1 ) ) ) ) ).


%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.13  % Problem  : GRP816+1 : TPTP v8.1.0. Released v7.5.0.
% 0.12/0.13  % Command  : darwin -fd true -ppp true -pl 0 -to %d -pmtptp true %s
% 0.14/0.35  % Computer : n027.cluster.edu
% 0.14/0.35  % Model    : x86_64 x86_64
% 0.14/0.35  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.14/0.35  % Memory   : 8042.1875MB
% 0.14/0.35  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.14/0.35  % CPULimit : 300
% 0.14/0.35  % DateTime : Tue Jun 14 06:54:18 EDT 2022
% 0.14/0.35  % CPUTime  : 
% 0.14/0.35  Defaulting to tptp format.
% 105.48/105.71  SZS status CounterSatisfiable for /export/starexec/sandbox/benchmark/theBenchmark.p
% 105.48/105.71  
% 105.48/105.71  MODEL (TPTP):
% 105.48/105.71  SZS output start FiniteModel for /export/starexec/sandbox/benchmark/theBenchmark.p
% See solution above
%------------------------------------------------------------------------------