TSTP Solution File: GRP715-10 by Twee---2.4.2
View Problem
- Process Solution
%------------------------------------------------------------------------------
% File : Twee---2.4.2
% Problem : GRP715-10 : TPTP v8.1.2. Released v8.1.0.
% Transfm : none
% Format : tptp:raw
% Command : parallel-twee %s --tstp --conditional-encoding if --smaller --drop-non-horn --give-up-on-saturation --explain-encoding --formal-proof
% Computer : n009.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 300s
% DateTime : Thu Aug 31 01:19:51 EDT 2023
% Result : Unsatisfiable 0.20s 0.40s
% Output : Proof 0.20s
% Verified :
% SZS Type : -
% Comments :
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.13 % Problem : GRP715-10 : TPTP v8.1.2. Released v8.1.0.
% 0.12/0.13 % Command : parallel-twee %s --tstp --conditional-encoding if --smaller --drop-non-horn --give-up-on-saturation --explain-encoding --formal-proof
% 0.13/0.34 % Computer : n009.cluster.edu
% 0.13/0.34 % Model : x86_64 x86_64
% 0.13/0.34 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.34 % Memory : 8042.1875MB
% 0.13/0.34 % OS : Linux 3.10.0-693.el7.x86_64
% 0.13/0.34 % CPULimit : 300
% 0.13/0.34 % WCLimit : 300
% 0.13/0.34 % DateTime : Tue Aug 29 01:21:35 EDT 2023
% 0.13/0.34 % CPUTime :
% 0.20/0.40 Command-line arguments: --kbo-weight0 --lhs-weight 5 --flip-ordering --normalise-queue-percent 10 --cp-renormalise-threshold 10 --goal-heuristic
% 0.20/0.40
% 0.20/0.40 % SZS status Unsatisfiable
% 0.20/0.40
% 0.20/0.41 % SZS output start Proof
% 0.20/0.41 Axiom 1 (f08): mult(X, unit) = X.
% 0.20/0.41 Axiom 2 (f10): mult(op_a, op_b) = unit.
% 0.20/0.41 Axiom 3 (f09): mult(unit, X) = X.
% 0.20/0.41 Axiom 4 (f11): mult(op_b, op_a) = unit.
% 0.20/0.41 Axiom 5 (f07): mult(X, mult(Y, Y)) = mult(mult(X, Y), Y).
% 0.20/0.41 Axiom 6 (f06): mult(mult(mult(X, Y), Z), Y) = mult(X, mult(mult(Y, Z), Y)).
% 0.20/0.41
% 0.20/0.41 Lemma 7: mult(mult(mult(mult(X, op_a), op_b), op_b), op_a) = X.
% 0.20/0.41 Proof:
% 0.20/0.41 mult(mult(mult(mult(X, op_a), op_b), op_b), op_a)
% 0.20/0.41 = { by axiom 5 (f07) R->L }
% 0.20/0.41 mult(mult(mult(X, op_a), mult(op_b, op_b)), op_a)
% 0.20/0.41 = { by axiom 6 (f06) }
% 0.20/0.41 mult(X, mult(mult(op_a, mult(op_b, op_b)), op_a))
% 0.20/0.41 = { by axiom 5 (f07) }
% 0.20/0.41 mult(X, mult(mult(mult(op_a, op_b), op_b), op_a))
% 0.20/0.41 = { by axiom 2 (f10) }
% 0.20/0.41 mult(X, mult(mult(unit, op_b), op_a))
% 0.20/0.41 = { by axiom 3 (f09) }
% 0.20/0.41 mult(X, mult(op_b, op_a))
% 0.20/0.41 = { by axiom 4 (f11) }
% 0.20/0.41 mult(X, unit)
% 0.20/0.41 = { by axiom 1 (f08) }
% 0.20/0.41 X
% 0.20/0.41
% 0.20/0.41 Goal 1 (goal): mult(mult(x0, op_a), op_b) = x0.
% 0.20/0.41 Proof:
% 0.20/0.41 mult(mult(x0, op_a), op_b)
% 0.20/0.41 = { by lemma 7 R->L }
% 0.20/0.41 mult(mult(mult(mult(mult(mult(x0, op_a), op_b), op_b), op_a), op_a), op_b)
% 0.20/0.41 = { by axiom 5 (f07) R->L }
% 0.20/0.41 mult(mult(mult(mult(mult(x0, op_a), op_b), op_b), mult(op_a, op_a)), op_b)
% 0.20/0.41 = { by axiom 3 (f09) R->L }
% 0.20/0.41 mult(mult(mult(mult(mult(x0, op_a), op_b), mult(unit, op_b)), mult(op_a, op_a)), op_b)
% 0.20/0.41 = { by axiom 4 (f11) R->L }
% 0.20/0.41 mult(mult(mult(mult(mult(x0, op_a), op_b), mult(mult(op_b, op_a), op_b)), mult(op_a, op_a)), op_b)
% 0.20/0.41 = { by axiom 6 (f06) R->L }
% 0.20/0.41 mult(mult(mult(mult(mult(mult(mult(x0, op_a), op_b), op_b), op_a), op_b), mult(op_a, op_a)), op_b)
% 0.20/0.41 = { by lemma 7 }
% 0.20/0.41 mult(mult(mult(x0, op_b), mult(op_a, op_a)), op_b)
% 0.20/0.41 = { by axiom 6 (f06) }
% 0.20/0.41 mult(x0, mult(mult(op_b, mult(op_a, op_a)), op_b))
% 0.20/0.41 = { by axiom 5 (f07) }
% 0.20/0.41 mult(x0, mult(mult(mult(op_b, op_a), op_a), op_b))
% 0.20/0.41 = { by axiom 4 (f11) }
% 0.20/0.41 mult(x0, mult(mult(unit, op_a), op_b))
% 0.20/0.41 = { by axiom 3 (f09) }
% 0.20/0.41 mult(x0, mult(op_a, op_b))
% 0.20/0.41 = { by axiom 2 (f10) }
% 0.20/0.41 mult(x0, unit)
% 0.20/0.41 = { by axiom 1 (f08) }
% 0.20/0.41 x0
% 0.20/0.41 % SZS output end Proof
% 0.20/0.41
% 0.20/0.41 RESULT: Unsatisfiable (the axioms are contradictory).
%------------------------------------------------------------------------------