TSTP Solution File: GRP671-1 by Otter---3.3

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : Otter---3.3
% Problem  : GRP671-1 : TPTP v8.1.0. Released v4.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : otter-tptp-script %s

% Computer : n025.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Wed Jul 27 12:57:37 EDT 2022

% Result   : Unsatisfiable 1.82s 2.02s
% Output   : Refutation 1.82s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :    3
%            Number of leaves      :    4
% Syntax   : Number of clauses     :    7 (   7 unt;   0 nHn;   2 RR)
%            Number of literals    :    7 (   6 equ;   1 neg)
%            Maximal clause size   :    1 (   1 avg)
%            Maximal term depth    :    5 (   2 avg)
%            Number of predicates  :    2 (   0 usr;   1 prp; 0-2 aty)
%            Number of functors    :    4 (   4 usr;   3 con; 0-2 aty)
%            Number of variables   :   10 (   0 sgn)

% Comments : 
%------------------------------------------------------------------------------
cnf(1,axiom,
    mult(mult(a,b),a) != mult(a,mult(b,a)),
    file('GRP671-1.p',unknown),
    [] ).

cnf(12,axiom,
    mult(A,unit) = A,
    file('GRP671-1.p',unknown),
    [] ).

cnf(13,axiom,
    mult(unit,A) = A,
    file('GRP671-1.p',unknown),
    [] ).

cnf(19,axiom,
    mult(mult(A,B),mult(C,mult(A,B))) = mult(mult(mult(A,mult(B,C)),A),B),
    file('GRP671-1.p',unknown),
    [] ).

cnf(20,plain,
    mult(mult(mult(A,mult(B,C)),A),B) = mult(mult(A,B),mult(C,mult(A,B))),
    inference(flip,[status(thm),theory(equality)],[inference(copy,[status(thm)],[19])]),
    [iquote('copy,19,flip.1')] ).

cnf(63,plain,
    mult(mult(A,B),A) = mult(A,mult(B,A)),
    inference(demod,[status(thm),theory(equality)],[inference(para_into,[status(thm),theory(equality)],[20,13]),12,12,12]),
    [iquote('para_into,20.1.1.1.1.2,13.1.1,demod,12,12,12')] ).

cnf(65,plain,
    $false,
    inference(binary,[status(thm)],[63,1]),
    [iquote('binary,63.1,1.1')] ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.06/0.11  % Problem  : GRP671-1 : TPTP v8.1.0. Released v4.0.0.
% 0.06/0.12  % Command  : otter-tptp-script %s
% 0.12/0.33  % Computer : n025.cluster.edu
% 0.12/0.33  % Model    : x86_64 x86_64
% 0.12/0.33  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.33  % Memory   : 8042.1875MB
% 0.12/0.33  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.12/0.33  % CPULimit : 300
% 0.12/0.33  % WCLimit  : 300
% 0.12/0.33  % DateTime : Wed Jul 27 05:09:45 EDT 2022
% 0.12/0.33  % CPUTime  : 
% 1.82/2.02  ----- Otter 3.3f, August 2004 -----
% 1.82/2.02  The process was started by sandbox2 on n025.cluster.edu,
% 1.82/2.02  Wed Jul 27 05:09:45 2022
% 1.82/2.02  The command was "./otter".  The process ID is 5627.
% 1.82/2.02  
% 1.82/2.02  set(prolog_style_variables).
% 1.82/2.02  set(auto).
% 1.82/2.02     dependent: set(auto1).
% 1.82/2.02     dependent: set(process_input).
% 1.82/2.02     dependent: clear(print_kept).
% 1.82/2.02     dependent: clear(print_new_demod).
% 1.82/2.02     dependent: clear(print_back_demod).
% 1.82/2.02     dependent: clear(print_back_sub).
% 1.82/2.02     dependent: set(control_memory).
% 1.82/2.02     dependent: assign(max_mem, 12000).
% 1.82/2.02     dependent: assign(pick_given_ratio, 4).
% 1.82/2.02     dependent: assign(stats_level, 1).
% 1.82/2.02     dependent: assign(max_seconds, 10800).
% 1.82/2.02  clear(print_given).
% 1.82/2.02  
% 1.82/2.02  list(usable).
% 1.82/2.02  0 [] A=A.
% 1.82/2.02  0 [] mult(A,ld(A,B))=B.
% 1.82/2.02  0 [] ld(A,mult(A,B))=B.
% 1.82/2.02  0 [] mult(rd(A,B),B)=A.
% 1.82/2.02  0 [] rd(mult(A,B),B)=A.
% 1.82/2.02  0 [] mult(A,unit)=A.
% 1.82/2.02  0 [] mult(unit,A)=A.
% 1.82/2.02  0 [] mult(i(A),mult(A,B))=B.
% 1.82/2.02  0 [] mult(mult(A,B),i(B))=A.
% 1.82/2.02  0 [] mult(mult(A,B),mult(C,mult(A,B)))=mult(mult(mult(A,mult(B,C)),A),B).
% 1.82/2.02  0 [] mult(mult(a,b),a)!=mult(a,mult(b,a)).
% 1.82/2.02  end_of_list.
% 1.82/2.02  
% 1.82/2.02  SCAN INPUT: prop=0, horn=1, equality=1, symmetry=0, max_lits=1.
% 1.82/2.02  
% 1.82/2.02  All clauses are units, and equality is present; the
% 1.82/2.02  strategy will be Knuth-Bendix with positive clauses in sos.
% 1.82/2.02  
% 1.82/2.02     dependent: set(knuth_bendix).
% 1.82/2.02     dependent: set(anl_eq).
% 1.82/2.02     dependent: set(para_from).
% 1.82/2.02     dependent: set(para_into).
% 1.82/2.02     dependent: clear(para_from_right).
% 1.82/2.02     dependent: clear(para_into_right).
% 1.82/2.02     dependent: set(para_from_vars).
% 1.82/2.02     dependent: set(eq_units_both_ways).
% 1.82/2.02     dependent: set(dynamic_demod_all).
% 1.82/2.02     dependent: set(dynamic_demod).
% 1.82/2.02     dependent: set(order_eq).
% 1.82/2.02     dependent: set(back_demod).
% 1.82/2.02     dependent: set(lrpo).
% 1.82/2.02  
% 1.82/2.02  ------------> process usable:
% 1.82/2.02  ** KEPT (pick-wt=11): 1 [] mult(mult(a,b),a)!=mult(a,mult(b,a)).
% 1.82/2.02  
% 1.82/2.02  ------------> process sos:
% 1.82/2.02  ** KEPT (pick-wt=3): 2 [] A=A.
% 1.82/2.02  ** KEPT (pick-wt=7): 3 [] mult(A,ld(A,B))=B.
% 1.82/2.02  ---> New Demodulator: 4 [new_demod,3] mult(A,ld(A,B))=B.
% 1.82/2.02  ** KEPT (pick-wt=7): 5 [] ld(A,mult(A,B))=B.
% 1.82/2.02  ---> New Demodulator: 6 [new_demod,5] ld(A,mult(A,B))=B.
% 1.82/2.02  ** KEPT (pick-wt=7): 7 [] mult(rd(A,B),B)=A.
% 1.82/2.02  ---> New Demodulator: 8 [new_demod,7] mult(rd(A,B),B)=A.
% 1.82/2.02  ** KEPT (pick-wt=7): 9 [] rd(mult(A,B),B)=A.
% 1.82/2.02  ---> New Demodulator: 10 [new_demod,9] rd(mult(A,B),B)=A.
% 1.82/2.02  ** KEPT (pick-wt=5): 11 [] mult(A,unit)=A.
% 1.82/2.02  ---> New Demodulator: 12 [new_demod,11] mult(A,unit)=A.
% 1.82/2.02  ** KEPT (pick-wt=5): 13 [] mult(unit,A)=A.
% 1.82/2.02  ---> New Demodulator: 14 [new_demod,13] mult(unit,A)=A.
% 1.82/2.02  ** KEPT (pick-wt=8): 15 [] mult(i(A),mult(A,B))=B.
% 1.82/2.02  ---> New Demodulator: 16 [new_demod,15] mult(i(A),mult(A,B))=B.
% 1.82/2.02  ** KEPT (pick-wt=8): 17 [] mult(mult(A,B),i(B))=A.
% 1.82/2.02  ---> New Demodulator: 18 [new_demod,17] mult(mult(A,B),i(B))=A.
% 1.82/2.02  ** KEPT (pick-wt=19): 20 [copy,19,flip.1] mult(mult(mult(A,mult(B,C)),A),B)=mult(mult(A,B),mult(C,mult(A,B))).
% 1.82/2.02  ---> New Demodulator: 21 [new_demod,20] mult(mult(mult(A,mult(B,C)),A),B)=mult(mult(A,B),mult(C,mult(A,B))).
% 1.82/2.02    Following clause subsumed by 2 during input processing: 0 [copy,2,flip.1] A=A.
% 1.82/2.02  >>>> Starting back demodulation with 4.
% 1.82/2.02  >>>> Starting back demodulation with 6.
% 1.82/2.02  >>>> Starting back demodulation with 8.
% 1.82/2.02  >>>> Starting back demodulation with 10.
% 1.82/2.02  >>>> Starting back demodulation with 12.
% 1.82/2.02  >>>> Starting back demodulation with 14.
% 1.82/2.02  >>>> Starting back demodulation with 16.
% 1.82/2.02  >>>> Starting back demodulation with 18.
% 1.82/2.02  >>>> Starting back demodulation with 21.
% 1.82/2.02  
% 1.82/2.02  ======= end of input processing =======
% 1.82/2.02  
% 1.82/2.02  =========== start of search ===========
% 1.82/2.02  
% 1.82/2.02  -------- PROOF -------- 
% 1.82/2.02  
% 1.82/2.02  ----> UNIT CONFLICT at   0.00 sec ----> 65 [binary,63.1,1.1] $F.
% 1.82/2.02  
% 1.82/2.02  Length of proof is 2.  Level of proof is 2.
% 1.82/2.02  
% 1.82/2.02  ---------------- PROOF ----------------
% 1.82/2.02  % SZS status Unsatisfiable
% 1.82/2.02  % SZS output start Refutation
% See solution above
% 1.82/2.02  ------------ end of proof -------------
% 1.82/2.02  
% 1.82/2.02  
% 1.82/2.02  Search stopped by max_proofs option.
% 1.82/2.02  
% 1.82/2.02  
% 1.82/2.02  Search stopped by max_proofs option.
% 1.82/2.02  
% 1.82/2.02  ============ end of search ============
% 1.82/2.02  
% 1.82/2.02  -------------- statistics -------------
% 1.82/2.02  clauses given                 16
% 1.82/2.02  clauses generated             81
% 1.82/2.02  clauses kept                  36
% 1.82/2.02  clauses forward subsumed      68
% 1.82/2.02  clauses back subsumed          0
% 1.82/2.02  Kbytes malloced              976
% 1.82/2.02  
% 1.82/2.02  ----------- times (seconds) -----------
% 1.82/2.02  user CPU time          0.00          (0 hr, 0 min, 0 sec)
% 1.82/2.02  system CPU time        0.00          (0 hr, 0 min, 0 sec)
% 1.82/2.02  wall-clock time        2             (0 hr, 0 min, 2 sec)
% 1.82/2.02  
% 1.82/2.02  That finishes the proof of the theorem.
% 1.82/2.02  
% 1.82/2.02  Process 5627 finished Wed Jul 27 05:09:47 2022
% 1.82/2.02  Otter interrupted
% 1.82/2.02  PROOF FOUND
%------------------------------------------------------------------------------