TSTP Solution File: GRP665-10 by SPASS---3.9

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : SPASS---3.9
% Problem  : GRP665-10 : TPTP v8.1.0. Released v8.1.0.
% Transfm  : none
% Format   : tptp
% Command  : run_spass %d %s

% Computer : n028.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 600s
% DateTime : Sat Jul 16 11:48:49 EDT 2022

% Result   : Unsatisfiable 0.20s 0.44s
% Output   : Refutation 0.20s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :    6
%            Number of leaves      :    5
% Syntax   : Number of clauses     :   12 (  12 unt;   0 nHn;  12 RR)
%            Number of literals    :   12 (   0 equ;   1 neg)
%            Maximal clause size   :    1 (   1 avg)
%            Maximal term depth    :    5 (   2 avg)
%            Number of predicates  :    2 (   1 usr;   1 prp; 0-2 aty)
%            Number of functors    :    8 (   8 usr;   6 con; 0-2 aty)
%            Number of variables   :    0 (   0 sgn)

% Comments : 
%------------------------------------------------------------------------------
cnf(1,axiom,
    equal(mult(u,ld(u,v)),v),
    file('GRP665-10.p',unknown),
    [] ).

cnf(2,axiom,
    equal(ld(u,mult(u,v)),v),
    file('GRP665-10.p',unknown),
    [] ).

cnf(8,axiom,
    equal(mult(mult(u,v),ld(v,mult(w,v))),mult(mult(u,w),v)),
    file('GRP665-10.p',unknown),
    [] ).

cnf(9,axiom,
    equal(mult(op_c,u),mult(u,op_c)),
    file('GRP665-10.p',unknown),
    [] ).

cnf(10,axiom,
    ~ equal(mult(mult(op_c,x0__dfg),x1__dfg),mult(op_c,mult(x0__dfg,x1__dfg))),
    file('GRP665-10.p',unknown),
    [] ).

cnf(52,plain,
    equal(ld(op_c,mult(u,op_c)),u),
    inference(spr,[status(thm),theory(equality)],[9,2]),
    [iquote('0:SpR:9.0,2.0')] ).

cnf(235,plain,
    equal(mult(mult(u,op_c),v),mult(mult(u,v),op_c)),
    inference(spr,[status(thm),theory(equality)],[52,8]),
    [iquote('0:SpR:52.0,8.0')] ).

cnf(239,plain,
    equal(mult(mult(u,op_c),ld(u,mult(v,u))),mult(mult(op_c,v),u)),
    inference(spr,[status(thm),theory(equality)],[9,8]),
    [iquote('0:SpR:9.0,8.0')] ).

cnf(248,plain,
    equal(mult(mult(u,op_c),v),mult(op_c,mult(u,v))),
    inference(rew,[status(thm),theory(equality)],[9,235]),
    [iquote('0:Rew:9.0,235.0')] ).

cnf(257,plain,
    equal(mult(op_c,mult(u,ld(u,mult(v,u)))),mult(mult(op_c,v),u)),
    inference(rew,[status(thm),theory(equality)],[248,239]),
    [iquote('0:Rew:248.0,239.0')] ).

cnf(258,plain,
    equal(mult(mult(op_c,u),v),mult(op_c,mult(u,v))),
    inference(rew,[status(thm),theory(equality)],[1,257]),
    [iquote('0:Rew:1.0,257.0')] ).

cnf(259,plain,
    $false,
    inference(unc,[status(thm)],[258,10]),
    [iquote('0:UnC:258.0,10.0')] ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.07/0.13  % Problem  : GRP665-10 : TPTP v8.1.0. Released v8.1.0.
% 0.07/0.13  % Command  : run_spass %d %s
% 0.13/0.35  % Computer : n028.cluster.edu
% 0.13/0.35  % Model    : x86_64 x86_64
% 0.13/0.35  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.35  % Memory   : 8042.1875MB
% 0.13/0.35  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.13/0.35  % CPULimit : 300
% 0.13/0.35  % WCLimit  : 600
% 0.13/0.35  % DateTime : Mon Jun 13 14:47:37 EDT 2022
% 0.13/0.35  % CPUTime  : 
% 0.20/0.44  
% 0.20/0.44  SPASS V 3.9 
% 0.20/0.44  SPASS beiseite: Proof found.
% 0.20/0.44  % SZS status Theorem
% 0.20/0.44  Problem: /export/starexec/sandbox/benchmark/theBenchmark.p 
% 0.20/0.44  SPASS derived 210 clauses, backtracked 0 clauses, performed 0 splits and kept 68 clauses.
% 0.20/0.44  SPASS allocated 63399 KBytes.
% 0.20/0.44  SPASS spent	0:00:00.08 on the problem.
% 0.20/0.44  		0:00:00.03 for the input.
% 0.20/0.44  		0:00:00.00 for the FLOTTER CNF translation.
% 0.20/0.44  		0:00:00.00 for inferences.
% 0.20/0.44  		0:00:00.00 for the backtracking.
% 0.20/0.44  		0:00:00.02 for the reduction.
% 0.20/0.44  
% 0.20/0.44  
% 0.20/0.44  Here is a proof with depth 2, length 12 :
% 0.20/0.44  % SZS output start Refutation
% See solution above
% 0.20/0.44  Formulae used in the proof : f01 f02 f08 f09 goal
% 0.20/0.44  
%------------------------------------------------------------------------------