TSTP Solution File: GRP600-1 by Prover9---1109a
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- Process Solution
%------------------------------------------------------------------------------
% File : Prover9---1109a
% Problem : GRP600-1 : TPTP v8.1.0. Bugfixed v2.7.0.
% Transfm : none
% Format : tptp:raw
% Command : tptp2X_and_run_prover9 %d %s
% Computer : n005.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 600s
% DateTime : Sat Jul 16 11:19:47 EDT 2022
% Result : Unsatisfiable 0.45s 1.02s
% Output : Refutation 0.45s
% Verified :
% SZS Type : -
% Comments :
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.04/0.13 % Problem : GRP600-1 : TPTP v8.1.0. Bugfixed v2.7.0.
% 0.04/0.13 % Command : tptp2X_and_run_prover9 %d %s
% 0.13/0.35 % Computer : n005.cluster.edu
% 0.13/0.35 % Model : x86_64 x86_64
% 0.13/0.35 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.35 % Memory : 8042.1875MB
% 0.13/0.35 % OS : Linux 3.10.0-693.el7.x86_64
% 0.13/0.35 % CPULimit : 300
% 0.13/0.35 % WCLimit : 600
% 0.13/0.35 % DateTime : Mon Jun 13 10:49:39 EDT 2022
% 0.13/0.35 % CPUTime :
% 0.45/1.02 ============================== Prover9 ===============================
% 0.45/1.02 Prover9 (32) version 2009-11A, November 2009.
% 0.45/1.02 Process 21742 was started by sandbox on n005.cluster.edu,
% 0.45/1.02 Mon Jun 13 10:49:39 2022
% 0.45/1.02 The command was "/export/starexec/sandbox/solver/bin/prover9 -t 300 -f /tmp/Prover9_21411_n005.cluster.edu".
% 0.45/1.02 ============================== end of head ===========================
% 0.45/1.02
% 0.45/1.02 ============================== INPUT =================================
% 0.45/1.02
% 0.45/1.02 % Reading from file /tmp/Prover9_21411_n005.cluster.edu
% 0.45/1.02
% 0.45/1.02 set(prolog_style_variables).
% 0.45/1.02 set(auto2).
% 0.45/1.02 % set(auto2) -> set(auto).
% 0.45/1.02 % set(auto) -> set(auto_inference).
% 0.45/1.02 % set(auto) -> set(auto_setup).
% 0.45/1.02 % set(auto_setup) -> set(predicate_elim).
% 0.45/1.02 % set(auto_setup) -> assign(eq_defs, unfold).
% 0.45/1.02 % set(auto) -> set(auto_limits).
% 0.45/1.02 % set(auto_limits) -> assign(max_weight, "100.000").
% 0.45/1.02 % set(auto_limits) -> assign(sos_limit, 20000).
% 0.45/1.02 % set(auto) -> set(auto_denials).
% 0.45/1.02 % set(auto) -> set(auto_process).
% 0.45/1.02 % set(auto2) -> assign(new_constants, 1).
% 0.45/1.02 % set(auto2) -> assign(fold_denial_max, 3).
% 0.45/1.02 % set(auto2) -> assign(max_weight, "200.000").
% 0.45/1.02 % set(auto2) -> assign(max_hours, 1).
% 0.45/1.02 % assign(max_hours, 1) -> assign(max_seconds, 3600).
% 0.45/1.02 % set(auto2) -> assign(max_seconds, 0).
% 0.45/1.02 % set(auto2) -> assign(max_minutes, 5).
% 0.45/1.02 % assign(max_minutes, 5) -> assign(max_seconds, 300).
% 0.45/1.02 % set(auto2) -> set(sort_initial_sos).
% 0.45/1.02 % set(auto2) -> assign(sos_limit, -1).
% 0.45/1.02 % set(auto2) -> assign(lrs_ticks, 3000).
% 0.45/1.02 % set(auto2) -> assign(max_megs, 400).
% 0.45/1.02 % set(auto2) -> assign(stats, some).
% 0.45/1.02 % set(auto2) -> clear(echo_input).
% 0.45/1.02 % set(auto2) -> set(quiet).
% 0.45/1.02 % set(auto2) -> clear(print_initial_clauses).
% 0.45/1.02 % set(auto2) -> clear(print_given).
% 0.45/1.02 assign(lrs_ticks,-1).
% 0.45/1.02 assign(sos_limit,10000).
% 0.45/1.02 assign(order,kbo).
% 0.45/1.02 set(lex_order_vars).
% 0.45/1.02 clear(print_given).
% 0.45/1.02
% 0.45/1.02 % formulas(sos). % not echoed (3 formulas)
% 0.45/1.02
% 0.45/1.02 ============================== end of input ==========================
% 0.45/1.02
% 0.45/1.02 % From the command line: assign(max_seconds, 300).
% 0.45/1.02
% 0.45/1.02 ============================== PROCESS NON-CLAUSAL FORMULAS ==========
% 0.45/1.02
% 0.45/1.02 % Formulas that are not ordinary clauses:
% 0.45/1.02
% 0.45/1.02 ============================== end of process non-clausal formulas ===
% 0.45/1.02
% 0.45/1.02 ============================== PROCESS INITIAL CLAUSES ===============
% 0.45/1.02
% 0.45/1.02 ============================== PREDICATE ELIMINATION =================
% 0.45/1.02
% 0.45/1.02 ============================== end predicate elimination =============
% 0.45/1.02
% 0.45/1.02 Auto_denials:
% 0.45/1.02 % copying label prove_these_axioms_4 to answer in negative clause
% 0.45/1.02
% 0.45/1.02 Term ordering decisions:
% 0.45/1.02
% 0.45/1.02 % Assigning unary symbol inverse kb_weight 0 and highest precedence (6).
% 0.45/1.02 Function symbol KB weights: a=1. b=1. double_divide=1. multiply=1. inverse=0.
% 0.45/1.02
% 0.45/1.02 ============================== end of process initial clauses ========
% 0.45/1.02
% 0.45/1.02 ============================== CLAUSES FOR SEARCH ====================
% 0.45/1.02
% 0.45/1.02 ============================== end of clauses for search =============
% 0.45/1.02
% 0.45/1.02 ============================== SEARCH ================================
% 0.45/1.02
% 0.45/1.02 % Starting search at 0.01 seconds.
% 0.45/1.02
% 0.45/1.02 ============================== PROOF =================================
% 0.45/1.02 % SZS status Unsatisfiable
% 0.45/1.02 % SZS output start Refutation
% 0.45/1.02
% 0.45/1.02 % Proof 1 at 0.02 (+ 0.00) seconds: prove_these_axioms_4.
% 0.45/1.02 % Length of proof is 14.
% 0.45/1.02 % Level of proof is 10.
% 0.45/1.02 % Maximum clause weight is 21.000.
% 0.45/1.02 % Given clauses 14.
% 0.45/1.02
% 0.45/1.02 1 multiply(A,B) = inverse(double_divide(B,A)) # label(multiply) # label(axiom). [assumption].
% 0.45/1.02 2 double_divide(double_divide(A,B),inverse(double_divide(A,inverse(double_divide(inverse(C),B))))) = C # label(single_axiom) # label(axiom). [assumption].
% 0.45/1.02 3 multiply(a,b) != multiply(b,a) # label(prove_these_axioms_4) # label(negated_conjecture) # answer(prove_these_axioms_4). [assumption].
% 0.45/1.02 4 inverse(double_divide(b,a)) != inverse(double_divide(a,b)) # answer(prove_these_axioms_4). [copy(3),rewrite([1(3),1(7)])].
% 0.45/1.02 5 double_divide(A,inverse(double_divide(double_divide(B,C),inverse(double_divide(inverse(D),inverse(double_divide(B,inverse(double_divide(inverse(A),C))))))))) = D. [para(2(a,1),2(a,1,1))].
% 0.45/1.02 12 double_divide(A,inverse(double_divide(inverse(B),inverse(A)))) = B. [para(5(a,1),5(a,1,2,1,2,1)),rewrite([2(8)])].
% 0.45/1.02 15 double_divide(double_divide(A,inverse(A)),inverse(B)) = B. [para(12(a,1),2(a,1,2,1))].
% 0.45/1.02 23 double_divide(inverse(A),inverse(double_divide(B,inverse(B)))) = A. [para(15(a,1),12(a,1))].
% 0.45/1.02 24 double_divide(A,inverse(double_divide(inverse(A),inverse(B)))) = B. [para(23(a,1),2(a,1,1)),rewrite([23(6)])].
% 0.45/1.02 31 double_divide(double_divide(A,inverse(B)),inverse(B)) = A. [para(24(a,1),2(a,1,2,1))].
% 0.45/1.02 38 inverse(inverse(A)) = A. [para(24(a,1),12(a,1,2,1)),rewrite([31(6)])].
% 0.45/1.02 39 double_divide(inverse(A),B) = double_divide(B,inverse(A)). [para(12(a,1),24(a,1,2,1)),rewrite([38(5)]),flip(a)].
% 0.45/1.02 75 double_divide(A,B) = double_divide(B,A). [para(38(a,1),39(a,1,1)),rewrite([38(3)])].
% 0.45/1.02 81 $F # answer(prove_these_axioms_4). [back_rewrite(4),rewrite([75(3)]),xx(a)].
% 0.45/1.02
% 0.45/1.02 % SZS output end Refutation
% 0.45/1.02 ============================== end of proof ==========================
% 0.45/1.02
% 0.45/1.02 ============================== STATISTICS ============================
% 0.45/1.02
% 0.45/1.02 Given=14. Generated=175. Kept=79. proofs=1.
% 0.45/1.02 Usable=4. Sos=15. Demods=25. Limbo=6, Disabled=57. Hints=0.
% 0.45/1.02 Megabytes=0.10.
% 0.45/1.02 User_CPU=0.02, System_CPU=0.00, Wall_clock=0.
% 0.45/1.02
% 0.45/1.02 ============================== end of statistics =====================
% 0.45/1.02
% 0.45/1.02 ============================== end of search =========================
% 0.45/1.02
% 0.45/1.02 THEOREM PROVED
% 0.45/1.02 % SZS status Unsatisfiable
% 0.45/1.02
% 0.45/1.02 Exiting with 1 proof.
% 0.45/1.02
% 0.45/1.02 Process 21742 exit (max_proofs) Mon Jun 13 10:49:39 2022
% 0.45/1.02 Prover9 interrupted
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