TSTP Solution File: GRP561-1 by Otter---3.3

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : Otter---3.3
% Problem  : GRP561-1 : TPTP v8.1.0. Released v2.6.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : otter-tptp-script %s

% Computer : n027.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Wed Jul 27 12:57:15 EDT 2022

% Result   : Unsatisfiable 1.67s 1.90s
% Output   : Refutation 1.67s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :   11
%            Number of leaves      :    3
% Syntax   : Number of clauses     :   22 (  22 unt;   0 nHn;   4 RR)
%            Number of literals    :   22 (  21 equ;   3 neg)
%            Maximal clause size   :    1 (   1 avg)
%            Maximal term depth    :    7 (   2 avg)
%            Number of predicates  :    2 (   0 usr;   1 prp; 0-2 aty)
%            Number of functors    :    5 (   5 usr;   2 con; 0-2 aty)
%            Number of variables   :   44 (   0 sgn)

% Comments : 
%------------------------------------------------------------------------------
cnf(1,axiom,
    multiply(inverse(a1),a1) != multiply(inverse(b1),b1),
    file('GRP561-1.p',unknown),
    [] ).

cnf(2,plain,
    multiply(inverse(b1),b1) != multiply(inverse(a1),a1),
    inference(flip,[status(thm),theory(equality)],[inference(copy,[status(thm)],[1])]),
    [iquote('copy,1,flip.1')] ).

cnf(5,axiom,
    divide(divide(divide(A,inverse(B)),C),divide(A,C)) = B,
    file('GRP561-1.p',unknown),
    [] ).

cnf(6,axiom,
    multiply(A,B) = divide(A,inverse(B)),
    file('GRP561-1.p',unknown),
    [] ).

cnf(7,plain,
    divide(A,inverse(B)) = multiply(A,B),
    inference(flip,[status(thm),theory(equality)],[inference(copy,[status(thm)],[6])]),
    [iquote('copy,6,flip.1')] ).

cnf(8,plain,
    divide(inverse(b1),inverse(b1)) != multiply(inverse(a1),a1),
    inference(para_from,[status(thm),theory(equality)],[6,2]),
    [iquote('para_from,6.1.1,2.1.1')] ).

cnf(9,plain,
    divide(divide(multiply(A,B),C),divide(A,C)) = B,
    inference(para_into,[status(thm),theory(equality)],[5,7]),
    [iquote('para_into,4.1.1.1.1,7.1.1')] ).

cnf(17,plain,
    divide(divide(divide(divide(divide(A,inverse(B)),C),inverse(D)),divide(A,C)),B) = D,
    inference(para_into,[status(thm),theory(equality)],[5,5]),
    [iquote('para_into,4.1.1.2,4.1.1')] ).

cnf(19,plain,
    divide(multiply(multiply(A,B),C),divide(A,inverse(C))) = B,
    inference(para_into,[status(thm),theory(equality)],[9,7]),
    [iquote('para_into,9.1.1.1,7.1.1')] ).

cnf(31,plain,
    divide(multiply(multiply(A,B),C),multiply(A,C)) = B,
    inference(para_into,[status(thm),theory(equality)],[19,7]),
    [iquote('para_into,19.1.1.2,7.1.1')] ).

cnf(39,plain,
    divide(A,divide(multiply(B,A),multiply(B,C))) = C,
    inference(para_from,[status(thm),theory(equality)],[31,9]),
    [iquote('para_from,31.1.1,9.1.1.1')] ).

cnf(45,plain,
    divide(A,divide(divide(B,inverse(A)),multiply(B,C))) = C,
    inference(para_into,[status(thm),theory(equality)],[39,6]),
    [iquote('para_into,39.1.1.2.1,6.1.1')] ).

cnf(233,plain,
    divide(divide(A,inverse(B)),A) = B,
    inference(demod,[status(thm),theory(equality)],[inference(para_into,[status(thm),theory(equality)],[17,17]),5]),
    [iquote('para_into,17.1.1.1.1,17.1.1,demod,5')] ).

cnf(305,plain,
    divide(multiply(A,B),A) = B,
    inference(para_into,[status(thm),theory(equality)],[233,7]),
    [iquote('para_into,233.1.1.1,7.1.1')] ).

cnf(333,plain,
    divide(A,divide(B,B)) = A,
    inference(para_from,[status(thm),theory(equality)],[233,5]),
    [iquote('para_from,233.1.1,4.1.1.1')] ).

cnf(373,plain,
    multiply(divide(A,A),B) = B,
    inference(flip,[status(thm),theory(equality)],[inference(para_into,[status(thm),theory(equality)],[333,305])]),
    [iquote('para_into,333.1.1,305.1.1,flip.1')] ).

cnf(376,plain,
    divide(divide(A,A),inverse(B)) = B,
    inference(flip,[status(thm),theory(equality)],[inference(para_into,[status(thm),theory(equality)],[333,233])]),
    [iquote('para_into,333.1.1,233.1.1,flip.1')] ).

cnf(383,plain,
    divide(A,divide(A,B)) = B,
    inference(demod,[status(thm),theory(equality)],[inference(para_from,[status(thm),theory(equality)],[373,45]),376]),
    [iquote('para_from,373.1.1,45.1.1.2.2,demod,376')] ).

cnf(395,plain,
    divide(A,A) = divide(B,B),
    inference(para_into,[status(thm),theory(equality)],[383,333]),
    [iquote('para_into,383.1.1.2,333.1.1')] ).

cnf(460,plain,
    multiply(inverse(A),A) = divide(B,B),
    inference(para_into,[status(thm),theory(equality)],[395,7]),
    [iquote('para_into,395.1.1,7.1.1')] ).

cnf(461,plain,
    divide(A,A) = multiply(inverse(B),B),
    inference(flip,[status(thm),theory(equality)],[inference(copy,[status(thm)],[460])]),
    [iquote('copy,460,flip.1')] ).

cnf(462,plain,
    $false,
    inference(binary,[status(thm)],[461,8]),
    [iquote('binary,461.1,8.1')] ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.10/0.12  % Problem  : GRP561-1 : TPTP v8.1.0. Released v2.6.0.
% 0.10/0.12  % Command  : otter-tptp-script %s
% 0.12/0.33  % Computer : n027.cluster.edu
% 0.12/0.33  % Model    : x86_64 x86_64
% 0.12/0.33  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.33  % Memory   : 8042.1875MB
% 0.12/0.33  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.12/0.33  % CPULimit : 300
% 0.12/0.33  % WCLimit  : 300
% 0.12/0.33  % DateTime : Wed Jul 27 05:38:21 EDT 2022
% 0.12/0.33  % CPUTime  : 
% 1.67/1.90  ----- Otter 3.3f, August 2004 -----
% 1.67/1.90  The process was started by sandbox2 on n027.cluster.edu,
% 1.67/1.90  Wed Jul 27 05:38:21 2022
% 1.67/1.90  The command was "./otter".  The process ID is 11332.
% 1.67/1.90  
% 1.67/1.90  set(prolog_style_variables).
% 1.67/1.90  set(auto).
% 1.67/1.90     dependent: set(auto1).
% 1.67/1.90     dependent: set(process_input).
% 1.67/1.90     dependent: clear(print_kept).
% 1.67/1.90     dependent: clear(print_new_demod).
% 1.67/1.90     dependent: clear(print_back_demod).
% 1.67/1.90     dependent: clear(print_back_sub).
% 1.67/1.90     dependent: set(control_memory).
% 1.67/1.90     dependent: assign(max_mem, 12000).
% 1.67/1.90     dependent: assign(pick_given_ratio, 4).
% 1.67/1.90     dependent: assign(stats_level, 1).
% 1.67/1.90     dependent: assign(max_seconds, 10800).
% 1.67/1.90  clear(print_given).
% 1.67/1.90  
% 1.67/1.90  list(usable).
% 1.67/1.90  0 [] A=A.
% 1.67/1.90  0 [] divide(divide(divide(A,inverse(B)),C),divide(A,C))=B.
% 1.67/1.90  0 [] multiply(A,B)=divide(A,inverse(B)).
% 1.67/1.90  0 [] multiply(inverse(a1),a1)!=multiply(inverse(b1),b1).
% 1.67/1.90  end_of_list.
% 1.67/1.90  
% 1.67/1.90  SCAN INPUT: prop=0, horn=1, equality=1, symmetry=0, max_lits=1.
% 1.67/1.90  
% 1.67/1.90  All clauses are units, and equality is present; the
% 1.67/1.90  strategy will be Knuth-Bendix with positive clauses in sos.
% 1.67/1.90  
% 1.67/1.90     dependent: set(knuth_bendix).
% 1.67/1.90     dependent: set(anl_eq).
% 1.67/1.90     dependent: set(para_from).
% 1.67/1.90     dependent: set(para_into).
% 1.67/1.90     dependent: clear(para_from_right).
% 1.67/1.90     dependent: clear(para_into_right).
% 1.67/1.90     dependent: set(para_from_vars).
% 1.67/1.90     dependent: set(eq_units_both_ways).
% 1.67/1.90     dependent: set(dynamic_demod_all).
% 1.67/1.90     dependent: set(dynamic_demod).
% 1.67/1.90     dependent: set(order_eq).
% 1.67/1.90     dependent: set(back_demod).
% 1.67/1.90     dependent: set(lrpo).
% 1.67/1.90  
% 1.67/1.90  ------------> process usable:
% 1.67/1.90  ** KEPT (pick-wt=9): 2 [copy,1,flip.1] multiply(inverse(b1),b1)!=multiply(inverse(a1),a1).
% 1.67/1.90  
% 1.67/1.90  ------------> process sos:
% 1.67/1.90  ** KEPT (pick-wt=3): 3 [] A=A.
% 1.67/1.90  ** KEPT (pick-wt=12): 4 [] divide(divide(divide(A,inverse(B)),C),divide(A,C))=B.
% 1.67/1.90  ---> New Demodulator: 5 [new_demod,4] divide(divide(divide(A,inverse(B)),C),divide(A,C))=B.
% 1.67/1.90  ** KEPT (pick-wt=8): 6 [] multiply(A,B)=divide(A,inverse(B)).
% 1.67/1.90    Following clause subsumed by 3 during input processing: 0 [copy,3,flip.1] A=A.
% 1.67/1.90  >>>> Starting back demodulation with 5.
% 1.67/1.90  ** KEPT (pick-wt=8): 7 [copy,6,flip.1] divide(A,inverse(B))=multiply(A,B).
% 1.67/1.90    Following clause subsumed by 6 during input processing: 0 [copy,7,flip.1] multiply(A,B)=divide(A,inverse(B)).
% 1.67/1.90  
% 1.67/1.90  ======= end of input processing =======
% 1.67/1.90  
% 1.67/1.90  =========== start of search ===========
% 1.67/1.90  
% 1.67/1.90  
% 1.67/1.90  Resetting weight limit to 13.
% 1.67/1.90  
% 1.67/1.90  
% 1.67/1.90  Resetting weight limit to 13.
% 1.67/1.90  
% 1.67/1.90  sos_size=149
% 1.67/1.90  
% 1.67/1.90  -------- PROOF -------- 
% 1.67/1.90  
% 1.67/1.90  ----> UNIT CONFLICT at   0.01 sec ----> 462 [binary,461.1,8.1] $F.
% 1.67/1.90  
% 1.67/1.90  Length of proof is 18.  Level of proof is 10.
% 1.67/1.90  
% 1.67/1.90  ---------------- PROOF ----------------
% 1.67/1.90  % SZS status Unsatisfiable
% 1.67/1.90  % SZS output start Refutation
% See solution above
% 1.67/1.90  ------------ end of proof -------------
% 1.67/1.90  
% 1.67/1.90  
% 1.67/1.90  Search stopped by max_proofs option.
% 1.67/1.90  
% 1.67/1.90  
% 1.67/1.90  Search stopped by max_proofs option.
% 1.67/1.90  
% 1.67/1.90  ============ end of search ============
% 1.67/1.90  
% 1.67/1.90  -------------- statistics -------------
% 1.67/1.90  clauses given                 29
% 1.67/1.90  clauses generated            531
% 1.67/1.90  clauses kept                 236
% 1.67/1.90  clauses forward subsumed     268
% 1.67/1.90  clauses back subsumed          0
% 1.67/1.90  Kbytes malloced             4882
% 1.67/1.90  
% 1.67/1.90  ----------- times (seconds) -----------
% 1.67/1.90  user CPU time          0.01          (0 hr, 0 min, 0 sec)
% 1.67/1.90  system CPU time        0.00          (0 hr, 0 min, 0 sec)
% 1.67/1.90  wall-clock time        2             (0 hr, 0 min, 2 sec)
% 1.67/1.90  
% 1.67/1.90  That finishes the proof of the theorem.
% 1.67/1.90  
% 1.67/1.90  Process 11332 finished Wed Jul 27 05:38:23 2022
% 1.67/1.91  Otter interrupted
% 1.67/1.91  PROOF FOUND
%------------------------------------------------------------------------------