TSTP Solution File: GRP553-1 by Otter---3.3

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : Otter---3.3
% Problem  : GRP553-1 : TPTP v8.1.0. Released v2.6.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : otter-tptp-script %s

% Computer : n014.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Wed Jul 27 12:57:14 EDT 2022

% Result   : Unsatisfiable 1.71s 1.94s
% Output   : Refutation 1.71s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :    9
%            Number of leaves      :    3
% Syntax   : Number of clauses     :   18 (  18 unt;   0 nHn;   4 RR)
%            Number of literals    :   18 (  17 equ;   3 neg)
%            Maximal clause size   :    1 (   1 avg)
%            Maximal term depth    :    7 (   2 avg)
%            Number of predicates  :    2 (   0 usr;   1 prp; 0-2 aty)
%            Number of functors    :    5 (   5 usr;   2 con; 0-2 aty)
%            Number of variables   :   33 (   0 sgn)

% Comments : 
%------------------------------------------------------------------------------
cnf(1,axiom,
    multiply(inverse(a1),a1) != multiply(inverse(b1),b1),
    file('GRP553-1.p',unknown),
    [] ).

cnf(2,plain,
    multiply(inverse(b1),b1) != multiply(inverse(a1),a1),
    inference(flip,[status(thm),theory(equality)],[inference(copy,[status(thm)],[1])]),
    [iquote('copy,1,flip.1')] ).

cnf(4,axiom,
    divide(divide(A,inverse(divide(B,divide(A,C)))),C) = B,
    file('GRP553-1.p',unknown),
    [] ).

cnf(6,axiom,
    multiply(A,B) = divide(A,inverse(B)),
    file('GRP553-1.p',unknown),
    [] ).

cnf(7,plain,
    divide(A,inverse(B)) = multiply(A,B),
    inference(flip,[status(thm),theory(equality)],[inference(copy,[status(thm)],[6])]),
    [iquote('copy,6,flip.1')] ).

cnf(8,plain,
    divide(inverse(b1),inverse(b1)) != multiply(inverse(a1),a1),
    inference(para_from,[status(thm),theory(equality)],[6,2]),
    [iquote('para_from,6.1.1,2.1.1')] ).

cnf(11,plain,
    divide(divide(divide(A,inverse(divide(B,divide(A,C)))),inverse(divide(D,B))),C) = D,
    inference(para_into,[status(thm),theory(equality)],[4,4]),
    [iquote('para_into,4.1.1.1.2.1.2,4.1.1')] ).

cnf(15,plain,
    divide(multiply(A,divide(B,divide(A,C))),C) = B,
    inference(para_into,[status(thm),theory(equality)],[4,7]),
    [iquote('para_into,4.1.1.1,7.1.1')] ).

cnf(88,plain,
    divide(A,inverse(divide(B,A))) = B,
    inference(para_into,[status(thm),theory(equality)],[11,4]),
    [iquote('para_into,11.1.1.1,4.1.1')] ).

cnf(122,plain,
    divide(A,inverse(divide(B,divide(A,C)))) = divide(C,inverse(B)),
    inference(flip,[status(thm),theory(equality)],[inference(para_into,[status(thm),theory(equality)],[88,4])]),
    [iquote('para_into,88.1.1.2.1,4.1.1,flip.1')] ).

cnf(123,plain,
    multiply(A,divide(B,A)) = B,
    inference(para_into,[status(thm),theory(equality)],[88,7]),
    [iquote('para_into,88.1.1,7.1.1')] ).

cnf(157,plain,
    divide(divide(A,inverse(B)),A) = B,
    inference(demod,[status(thm),theory(equality)],[inference(back_demod,[status(thm)],[4]),122]),
    [iquote('back_demod,4,demod,122')] ).

cnf(163,plain,
    multiply(inverse(divide(A,B)),A) = B,
    inference(para_into,[status(thm),theory(equality)],[123,88]),
    [iquote('para_into,123.1.1.2,88.1.1')] ).

cnf(179,plain,
    divide(multiply(A,B),A) = B,
    inference(para_into,[status(thm),theory(equality)],[157,7]),
    [iquote('para_into,157.1.1.1,7.1.1')] ).

cnf(188,plain,
    divide(A,divide(B,B)) = A,
    inference(flip,[status(thm),theory(equality)],[inference(para_into,[status(thm),theory(equality)],[179,15])]),
    [iquote('para_into,179.1.1,15.1.1,flip.1')] ).

cnf(231,plain,
    multiply(inverse(A),A) = divide(B,B),
    inference(para_into,[status(thm),theory(equality)],[163,188]),
    [iquote('para_into,163.1.1.1.1,188.1.1')] ).

cnf(239,plain,
    divide(A,A) = multiply(inverse(B),B),
    inference(flip,[status(thm),theory(equality)],[inference(copy,[status(thm)],[231])]),
    [iquote('copy,231,flip.1')] ).

cnf(240,plain,
    $false,
    inference(binary,[status(thm)],[239,8]),
    [iquote('binary,239.1,8.1')] ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.03/0.12  % Problem  : GRP553-1 : TPTP v8.1.0. Released v2.6.0.
% 0.03/0.13  % Command  : otter-tptp-script %s
% 0.12/0.33  % Computer : n014.cluster.edu
% 0.12/0.33  % Model    : x86_64 x86_64
% 0.12/0.33  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.33  % Memory   : 8042.1875MB
% 0.12/0.33  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.12/0.33  % CPULimit : 300
% 0.12/0.33  % WCLimit  : 300
% 0.12/0.33  % DateTime : Wed Jul 27 05:18:54 EDT 2022
% 0.12/0.34  % CPUTime  : 
% 1.71/1.94  ----- Otter 3.3f, August 2004 -----
% 1.71/1.94  The process was started by sandbox on n014.cluster.edu,
% 1.71/1.94  Wed Jul 27 05:18:54 2022
% 1.71/1.94  The command was "./otter".  The process ID is 30106.
% 1.71/1.94  
% 1.71/1.94  set(prolog_style_variables).
% 1.71/1.94  set(auto).
% 1.71/1.94     dependent: set(auto1).
% 1.71/1.94     dependent: set(process_input).
% 1.71/1.94     dependent: clear(print_kept).
% 1.71/1.94     dependent: clear(print_new_demod).
% 1.71/1.94     dependent: clear(print_back_demod).
% 1.71/1.94     dependent: clear(print_back_sub).
% 1.71/1.94     dependent: set(control_memory).
% 1.71/1.94     dependent: assign(max_mem, 12000).
% 1.71/1.94     dependent: assign(pick_given_ratio, 4).
% 1.71/1.94     dependent: assign(stats_level, 1).
% 1.71/1.94     dependent: assign(max_seconds, 10800).
% 1.71/1.94  clear(print_given).
% 1.71/1.94  
% 1.71/1.94  list(usable).
% 1.71/1.94  0 [] A=A.
% 1.71/1.94  0 [] divide(divide(A,inverse(divide(B,divide(A,C)))),C)=B.
% 1.71/1.94  0 [] multiply(A,B)=divide(A,inverse(B)).
% 1.71/1.94  0 [] multiply(inverse(a1),a1)!=multiply(inverse(b1),b1).
% 1.71/1.94  end_of_list.
% 1.71/1.94  
% 1.71/1.94  SCAN INPUT: prop=0, horn=1, equality=1, symmetry=0, max_lits=1.
% 1.71/1.94  
% 1.71/1.94  All clauses are units, and equality is present; the
% 1.71/1.94  strategy will be Knuth-Bendix with positive clauses in sos.
% 1.71/1.94  
% 1.71/1.94     dependent: set(knuth_bendix).
% 1.71/1.94     dependent: set(anl_eq).
% 1.71/1.94     dependent: set(para_from).
% 1.71/1.94     dependent: set(para_into).
% 1.71/1.94     dependent: clear(para_from_right).
% 1.71/1.94     dependent: clear(para_into_right).
% 1.71/1.94     dependent: set(para_from_vars).
% 1.71/1.94     dependent: set(eq_units_both_ways).
% 1.71/1.94     dependent: set(dynamic_demod_all).
% 1.71/1.94     dependent: set(dynamic_demod).
% 1.71/1.94     dependent: set(order_eq).
% 1.71/1.94     dependent: set(back_demod).
% 1.71/1.94     dependent: set(lrpo).
% 1.71/1.94  
% 1.71/1.94  ------------> process usable:
% 1.71/1.94  ** KEPT (pick-wt=9): 2 [copy,1,flip.1] multiply(inverse(b1),b1)!=multiply(inverse(a1),a1).
% 1.71/1.94  
% 1.71/1.94  ------------> process sos:
% 1.71/1.94  ** KEPT (pick-wt=3): 3 [] A=A.
% 1.71/1.94  ** KEPT (pick-wt=12): 4 [] divide(divide(A,inverse(divide(B,divide(A,C)))),C)=B.
% 1.71/1.94  ---> New Demodulator: 5 [new_demod,4] divide(divide(A,inverse(divide(B,divide(A,C)))),C)=B.
% 1.71/1.94  ** KEPT (pick-wt=8): 6 [] multiply(A,B)=divide(A,inverse(B)).
% 1.71/1.94    Following clause subsumed by 3 during input processing: 0 [copy,3,flip.1] A=A.
% 1.71/1.94  >>>> Starting back demodulation with 5.
% 1.71/1.94  ** KEPT (pick-wt=8): 7 [copy,6,flip.1] divide(A,inverse(B))=multiply(A,B).
% 1.71/1.94    Following clause subsumed by 6 during input processing: 0 [copy,7,flip.1] multiply(A,B)=divide(A,inverse(B)).
% 1.71/1.94  
% 1.71/1.94  ======= end of input processing =======
% 1.71/1.94  
% 1.71/1.94  =========== start of search ===========
% 1.71/1.94  
% 1.71/1.94  -------- PROOF -------- 
% 1.71/1.94  
% 1.71/1.94  ----> UNIT CONFLICT at   0.01 sec ----> 240 [binary,239.1,8.1] $F.
% 1.71/1.94  
% 1.71/1.94  Length of proof is 14.  Level of proof is 8.
% 1.71/1.94  
% 1.71/1.94  ---------------- PROOF ----------------
% 1.71/1.94  % SZS status Unsatisfiable
% 1.71/1.94  % SZS output start Refutation
% See solution above
% 1.71/1.94  ------------ end of proof -------------
% 1.71/1.94  
% 1.71/1.94  
% 1.71/1.94  Search stopped by max_proofs option.
% 1.71/1.94  
% 1.71/1.94  
% 1.71/1.94  Search stopped by max_proofs option.
% 1.71/1.94  
% 1.71/1.94  ============ end of search ============
% 1.71/1.94  
% 1.71/1.94  -------------- statistics -------------
% 1.71/1.94  clauses given                 18
% 1.71/1.94  clauses generated            212
% 1.71/1.94  clauses kept                 153
% 1.71/1.94  clauses forward subsumed     178
% 1.71/1.94  clauses back subsumed          6
% 1.71/1.94  Kbytes malloced             1953
% 1.71/1.94  
% 1.71/1.94  ----------- times (seconds) -----------
% 1.71/1.94  user CPU time          0.01          (0 hr, 0 min, 0 sec)
% 1.71/1.94  system CPU time        0.00          (0 hr, 0 min, 0 sec)
% 1.71/1.94  wall-clock time        1             (0 hr, 0 min, 1 sec)
% 1.71/1.94  
% 1.71/1.94  That finishes the proof of the theorem.
% 1.71/1.94  
% 1.71/1.94  Process 30106 finished Wed Jul 27 05:18:55 2022
% 1.71/1.94  Otter interrupted
% 1.71/1.94  PROOF FOUND
%------------------------------------------------------------------------------