TSTP Solution File: GRP535-1 by Otter---3.3

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : Otter---3.3
% Problem  : GRP535-1 : TPTP v8.1.0. Released v2.6.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : otter-tptp-script %s

% Computer : n014.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Wed Jul 27 12:57:12 EDT 2022

% Result   : Unsatisfiable 1.75s 1.94s
% Output   : Refutation 1.75s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :   10
%            Number of leaves      :    5
% Syntax   : Number of clauses     :   22 (  22 unt;   0 nHn;   5 RR)
%            Number of literals    :   22 (  21 equ;   4 neg)
%            Maximal clause size   :    1 (   1 avg)
%            Maximal term depth    :    5 (   2 avg)
%            Number of predicates  :    2 (   0 usr;   1 prp; 0-2 aty)
%            Number of functors    :    6 (   6 usr;   4 con; 0-2 aty)
%            Number of variables   :   34 (   0 sgn)

% Comments : 
%------------------------------------------------------------------------------
cnf(1,axiom,
    multiply(multiply(a3,b3),c3) != multiply(a3,multiply(b3,c3)),
    file('GRP535-1.p',unknown),
    [] ).

cnf(2,axiom,
    A = A,
    file('GRP535-1.p',unknown),
    [] ).

cnf(3,axiom,
    divide(divide(A,divide(divide(A,B),C)),B) = C,
    file('GRP535-1.p',unknown),
    [] ).

cnf(5,axiom,
    multiply(A,B) = divide(A,divide(divide(C,C),B)),
    file('GRP535-1.p',unknown),
    [] ).

cnf(7,axiom,
    identity = divide(A,A),
    file('GRP535-1.p',unknown),
    [] ).

cnf(9,plain,
    divide(A,A) = identity,
    inference(flip,[status(thm),theory(equality)],[inference(copy,[status(thm)],[7])]),
    [iquote('copy,7,flip.1')] ).

cnf(11,plain,
    multiply(A,B) = divide(A,divide(identity,B)),
    inference(flip,[status(thm),theory(equality)],[inference(demod,[status(thm),theory(equality)],[inference(flip,[status(thm),theory(equality)],[inference(copy,[status(thm)],[5])]),9])]),
    [iquote('copy,5,flip.1,demod,9,flip.1')] ).

cnf(14,plain,
    divide(divide(a3,divide(identity,b3)),divide(identity,c3)) != divide(a3,divide(identity,divide(b3,divide(identity,c3)))),
    inference(demod,[status(thm),theory(equality)],[inference(back_demod,[status(thm)],[1]),11,11,11,11]),
    [iquote('back_demod,1,demod,11,11,11,11')] ).

cnf(15,plain,
    divide(divide(A,divide(identity,B)),A) = B,
    inference(para_into,[status(thm),theory(equality)],[3,9]),
    [iquote('para_into,3.1.1.1.2.1,8.1.1')] ).

cnf(25,plain,
    divide(identity,divide(identity,A)) = A,
    inference(para_into,[status(thm),theory(equality)],[15,9]),
    [iquote('para_into,15.1.1.1,8.1.1')] ).

cnf(29,plain,
    divide(divide(A,B),divide(identity,B)) = A,
    inference(para_from,[status(thm),theory(equality)],[15,3]),
    [iquote('para_from,15.1.1,3.1.1.1.2')] ).

cnf(34,plain,
    divide(A,identity) = A,
    inference(para_from,[status(thm),theory(equality)],[25,15]),
    [iquote('para_from,25.1.1,15.1.1.1')] ).

cnf(35,plain,
    divide(divide(A,B),A) = divide(identity,B),
    inference(para_from,[status(thm),theory(equality)],[25,15]),
    [iquote('para_from,25.1.1,15.1.1.1.2')] ).

cnf(40,plain,
    divide(A,divide(A,B)) = B,
    inference(flip,[status(thm),theory(equality)],[inference(demod,[status(thm),theory(equality)],[inference(para_into,[status(thm),theory(equality)],[34,3]),34])]),
    [iquote('para_into,33.1.1,3.1.1,demod,34,flip.1')] ).

cnf(43,plain,
    divide(divide(A,B),C) = divide(divide(A,C),B),
    inference(para_from,[status(thm),theory(equality)],[40,3]),
    [iquote('para_from,39.1.1,3.1.1.1.2')] ).

cnf(62,plain,
    divide(A,divide(identity,divide(B,A))) = B,
    inference(para_into,[status(thm),theory(equality)],[29,40]),
    [iquote('para_into,29.1.1.1,39.1.1')] ).

cnf(70,plain,
    divide(A,B) = divide(identity,divide(B,A)),
    inference(para_into,[status(thm),theory(equality)],[35,40]),
    [iquote('para_into,35.1.1.1,39.1.1')] ).

cnf(81,plain,
    divide(A,divide(divide(A,B),C)) = divide(B,divide(identity,C)),
    inference(flip,[status(thm),theory(equality)],[inference(para_into,[status(thm),theory(equality)],[62,3])]),
    [iquote('para_into,62.1.1.2.2,3.1.1,flip.1')] ).

cnf(117,plain,
    divide(divide(b3,divide(identity,a3)),divide(identity,c3)) != divide(a3,divide(identity,divide(b3,divide(identity,c3)))),
    inference(demod,[status(thm),theory(equality)],[inference(para_from,[status(thm),theory(equality)],[70,14]),81]),
    [iquote('para_from,70.1.1,14.1.1.1,demod,81')] ).

cnf(134,plain,
    divide(divide(A,B),C) = divide(identity,divide(B,divide(A,C))),
    inference(flip,[status(thm),theory(equality)],[inference(para_into,[status(thm),theory(equality)],[43,70])]),
    [iquote('para_into,43.1.1,70.1.1,flip.1')] ).

cnf(148,plain,
    divide(a3,divide(identity,divide(b3,divide(identity,c3)))) != divide(a3,divide(identity,divide(b3,divide(identity,c3)))),
    inference(demod,[status(thm),theory(equality)],[inference(back_demod,[status(thm)],[117]),134,134,40]),
    [iquote('back_demod,117,demod,134,134,40')] ).

cnf(149,plain,
    $false,
    inference(binary,[status(thm)],[148,2]),
    [iquote('binary,148.1,2.1')] ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.03/0.12  % Problem  : GRP535-1 : TPTP v8.1.0. Released v2.6.0.
% 0.03/0.13  % Command  : otter-tptp-script %s
% 0.12/0.34  % Computer : n014.cluster.edu
% 0.12/0.34  % Model    : x86_64 x86_64
% 0.12/0.34  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.34  % Memory   : 8042.1875MB
% 0.12/0.34  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.12/0.34  % CPULimit : 300
% 0.12/0.34  % WCLimit  : 300
% 0.12/0.34  % DateTime : Wed Jul 27 05:20:09 EDT 2022
% 0.12/0.34  % CPUTime  : 
% 1.75/1.94  ----- Otter 3.3f, August 2004 -----
% 1.75/1.94  The process was started by sandbox2 on n014.cluster.edu,
% 1.75/1.94  Wed Jul 27 05:20:09 2022
% 1.75/1.94  The command was "./otter".  The process ID is 2911.
% 1.75/1.94  
% 1.75/1.94  set(prolog_style_variables).
% 1.75/1.94  set(auto).
% 1.75/1.94     dependent: set(auto1).
% 1.75/1.94     dependent: set(process_input).
% 1.75/1.94     dependent: clear(print_kept).
% 1.75/1.94     dependent: clear(print_new_demod).
% 1.75/1.94     dependent: clear(print_back_demod).
% 1.75/1.94     dependent: clear(print_back_sub).
% 1.75/1.94     dependent: set(control_memory).
% 1.75/1.94     dependent: assign(max_mem, 12000).
% 1.75/1.94     dependent: assign(pick_given_ratio, 4).
% 1.75/1.94     dependent: assign(stats_level, 1).
% 1.75/1.94     dependent: assign(max_seconds, 10800).
% 1.75/1.94  clear(print_given).
% 1.75/1.94  
% 1.75/1.94  list(usable).
% 1.75/1.94  0 [] A=A.
% 1.75/1.94  0 [] divide(divide(A,divide(divide(A,B),C)),B)=C.
% 1.75/1.94  0 [] multiply(A,B)=divide(A,divide(divide(C,C),B)).
% 1.75/1.94  0 [] inverse(A)=divide(divide(B,B),A).
% 1.75/1.94  0 [] identity=divide(A,A).
% 1.75/1.94  0 [] multiply(multiply(a3,b3),c3)!=multiply(a3,multiply(b3,c3)).
% 1.75/1.94  end_of_list.
% 1.75/1.94  
% 1.75/1.94  SCAN INPUT: prop=0, horn=1, equality=1, symmetry=0, max_lits=1.
% 1.75/1.94  
% 1.75/1.94  All clauses are units, and equality is present; the
% 1.75/1.94  strategy will be Knuth-Bendix with positive clauses in sos.
% 1.75/1.94  
% 1.75/1.94     dependent: set(knuth_bendix).
% 1.75/1.94     dependent: set(anl_eq).
% 1.75/1.94     dependent: set(para_from).
% 1.75/1.94     dependent: set(para_into).
% 1.75/1.94     dependent: clear(para_from_right).
% 1.75/1.94     dependent: clear(para_into_right).
% 1.75/1.94     dependent: set(para_from_vars).
% 1.75/1.94     dependent: set(eq_units_both_ways).
% 1.75/1.94     dependent: set(dynamic_demod_all).
% 1.75/1.94     dependent: set(dynamic_demod).
% 1.75/1.94     dependent: set(order_eq).
% 1.75/1.94     dependent: set(back_demod).
% 1.75/1.94     dependent: set(lrpo).
% 1.75/1.94  
% 1.75/1.94  ------------> process usable:
% 1.75/1.94  ** KEPT (pick-wt=11): 1 [] multiply(multiply(a3,b3),c3)!=multiply(a3,multiply(b3,c3)).
% 1.75/1.94  
% 1.75/1.94  ------------> process sos:
% 1.75/1.94  ** KEPT (pick-wt=3): 2 [] A=A.
% 1.75/1.94  ** KEPT (pick-wt=11): 3 [] divide(divide(A,divide(divide(A,B),C)),B)=C.
% 1.75/1.94  ---> New Demodulator: 4 [new_demod,3] divide(divide(A,divide(divide(A,B),C)),B)=C.
% 1.75/1.94  ** KEPT (pick-wt=11): 5 [] multiply(A,B)=divide(A,divide(divide(C,C),B)).
% 1.75/1.94  ** KEPT (pick-wt=8): 6 [] inverse(A)=divide(divide(B,B),A).
% 1.75/1.94  ** KEPT (pick-wt=5): 8 [copy,7,flip.1] divide(A,A)=identity.
% 1.75/1.94  ---> New Demodulator: 9 [new_demod,8] divide(A,A)=identity.
% 1.75/1.94    Following clause subsumed by 2 during input processing: 0 [copy,2,flip.1] A=A.
% 1.75/1.94  >>>> Starting back demodulation with 4.
% 1.75/1.94  ** KEPT (pick-wt=9): 10 [copy,5,flip.1,demod,9,flip.1] multiply(A,B)=divide(A,divide(identity,B)).
% 1.75/1.94  ---> New Demodulator: 11 [new_demod,10] multiply(A,B)=divide(A,divide(identity,B)).
% 1.75/1.94  ** KEPT (pick-wt=6): 12 [copy,6,flip.1,demod,9,flip.1] inverse(A)=divide(identity,A).
% 1.75/1.94  ---> New Demodulator: 13 [new_demod,12] inverse(A)=divide(identity,A).
% 1.75/1.94  >>>> Starting back demodulation with 9.
% 1.75/1.94      >> back demodulating 6 with 9.
% 1.75/1.94      >> back demodulating 5 with 9.
% 1.75/1.94  >>>> Starting back demodulation with 11.
% 1.75/1.94      >> back demodulating 1 with 11.
% 1.75/1.94  >>>> Starting back demodulation with 13.
% 1.75/1.94  
% 1.75/1.94  ======= end of input processing =======
% 1.75/1.94  
% 1.75/1.94  =========== start of search ===========
% 1.75/1.94  
% 1.75/1.94  -------- PROOF -------- 
% 1.75/1.94  
% 1.75/1.94  ----> UNIT CONFLICT at   0.00 sec ----> 149 [binary,148.1,2.1] $F.
% 1.75/1.94  
% 1.75/1.94  Length of proof is 16.  Level of proof is 9.
% 1.75/1.94  
% 1.75/1.94  ---------------- PROOF ----------------
% 1.75/1.94  % SZS status Unsatisfiable
% 1.75/1.94  % SZS output start Refutation
% See solution above
% 1.75/1.94  ------------ end of proof -------------
% 1.75/1.94  
% 1.75/1.94  
% 1.75/1.94  Search stopped by max_proofs option.
% 1.75/1.94  
% 1.75/1.94  
% 1.75/1.94  Search stopped by max_proofs option.
% 1.75/1.94  
% 1.75/1.94  ============ end of search ============
% 1.75/1.94  
% 1.75/1.94  -------------- statistics -------------
% 1.75/1.94  clauses given                 19
% 1.75/1.94  clauses generated            232
% 1.75/1.94  clauses kept                  89
% 1.75/1.94  clauses forward subsumed     209
% 1.75/1.94  clauses back subsumed          1
% 1.75/1.94  Kbytes malloced              976
% 1.75/1.94  
% 1.75/1.94  ----------- times (seconds) -----------
% 1.75/1.94  user CPU time          0.00          (0 hr, 0 min, 0 sec)
% 1.75/1.94  system CPU time        0.00          (0 hr, 0 min, 0 sec)
% 1.75/1.94  wall-clock time        2             (0 hr, 0 min, 2 sec)
% 1.75/1.94  
% 1.75/1.94  That finishes the proof of the theorem.
% 1.75/1.94  
% 1.75/1.94  Process 2911 finished Wed Jul 27 05:20:11 2022
% 1.75/1.95  Otter interrupted
% 1.75/1.95  PROOF FOUND
%------------------------------------------------------------------------------